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Hydrocarbons Test - 45

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Hydrocarbons Test - 45
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  • Question 1
    1 / -0
    Methyl bromide is converted into ethane by heating it in ether medium with:
    Solution
    Methyl Bromide can be converted to ethane by wurtz's reaction:
    $$\mathrm{2CH_3Br+2Na\xrightarrow{Dry\ ether} CH_3-CH_3 +2NaBr}$$

    Hence, Option "C" is the correct answer.
  • Question 2
    1 / -0
    Which of the following is an appropriate set of reactants for the preparation of 1-methoxy-4-nitrobenzene ?

    Solution

  • Question 3
    1 / -0
    Carbon-carbon bond distance in benzene is
    Solution
    Carbon-carbon single bond is longer than carbon-carbon double bond because, bond length depend on the percentage s character.

  • Question 4
    1 / -0
    Which of the following is not aromatic?
    Solution

  • Question 5
    1 / -0
    The benzene molecule is
    Solution
    The shape of Benzene is a $$planar $$ regular hexagon, with bond angles of 120°.

    This is easily explained. 

    It is a regular hexagon because all the bonds are identical. The delocalisation of the electrons means that there aren't alternating double and single bonds. 
  • Question 6
    1 / -0
    The centric formula of benzene was proposed by
    Solution
    Centric structure of benzene was proposed by $$Armstrong \ and\  Baeyer$$.
  • Question 7
    1 / -0
    Which gives only monosubstituted product?
    Solution
    m-Dinitrobenzene will give only monosubstituted product. $$NO_2$$ group is meta directing group and there is only one $$meta-$$ position available in case of m-dinitrobenzene.
  • Question 8
    1 / -0
    The carbon-carbon bond length in benzene is:
    Solution
    We know, that there are only sigma bonds in ethane (C₂H₆), one sigma and one PI bond in ethene (C₂H₄), and one sigma and two PI bonds in acetylene (C₂H₂). Benzene (C₆H₆) is an aromatic compound, and due to resonance, there is partial double bonds everywhere.
    Now, hybridization of carbons of alkane is $$sp^3$$, that of alkene is $$sp^2$$, and that of alkyne is $$sp$$. Thus, in $$sp$$, there's an increased s-character, that reduces the bond length.
    Hence the correct options is C. 

  • Question 9
    1 / -0
    Which does not show substitution in benzene ring?
    Solution
    Benzene would never react with $$HCl.$$ As $$HCl$$ as an inorganic acid doesn't have electrophile to replace the $$H$$ atom of benzene. Here $$Cl$$ act as Lewis base so it doesn't act as an electrophile . Also, addition does not take place if it does it lose its aromaticity.
  • Question 10
    1 / -0
    Which is not an aromatic compound?
    Solution
    Cyclohexane is not aromatic since it does not have alternating double and single bonds between the C-atoms. 
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