Hydrocarbons Test

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Hydrocarbons Test - 54

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Weekly Quiz Competition

Question 1
1 / -0

Among the following select the alkane that is expected to have lowest boiling point:

A
Hexane

B
$$2$$-Methylpentane

C
$$3$$-Methylpentane

D
$$2,2$$-Dimethylbutane

Solution
Question 2
1 / -0

Which of the following does not give isopropylbenzene as a product upon reaction with benzene?

A
$$(CH_3)_2CHCl/AlCl_3$$

B
$$CH_3CH_2CH_2Cl/AlCl_3$$

C
$$CH_3CH=CH_2/H_3PO_4$$

D
$$(CH_3)_2C=CH_2/H_3PO_4$$

Solution

From the above reaction D does not give isopropyl Benzene.
Question 3
1 / -0

Large molecule alkane on heating at a high temperature forms low molecular alkane and alkene by a process called as___________.

A
Cracking

B
Dehydrogenation

C
Hydration

D
Both a and b

Solution

When alkanes of high molecular weight are heated at high temperature, the molecules breaks into alkane and alkenes of low molecular weight. This process is called cracking or dehydrogenation. Ethane when heated upto 500 degree Celsius forms ethene.
Question 4
1 / -0

Which of the following is NOT correct?

A
$$LiOH$$ is a weaker base than $$NaOH$$.

B
Salts of $$Be$$ undergo hydrolysis.

C
$$Ca{ \left( HC{ O }_{ 3 } \right) }_{ 2 }$$ is soluble in water.

D
Hydrolysis of beryllium carbide gives acetylene.

Solution

Hydrolysis of Beryllium carbide does not give acetylene, it gives methane.

$$Be_2C + 4 H_2O \rightarrow 2Be(OH)_2 + CH_4 $$
Question 5
1 / -0

$$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ CH }_{ 3 }+{ Br }_{ 2 }\rightarrow HBr +$$ $$X$$ . Identify $$X$$.

A
$$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }OH$$

B
$$\displaystyle { CH }_{ 3 }CH\left( Br \right) CH\left( Br \right) { CH }_{ 3 }$$

C
$$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }CH\left( Br \right) { CH }_{ 3 }$$

D
$$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }COOH$$

E
$$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ CH }_{ 3 }$$

Solution
Question 6
1 / -0

$$CH-CH=CH_2 + HCl \xrightarrow{Organic \ peroxide} A.$$

The product A is:

A
$$CH_3 - \underset{Cl}{\underset{\mid}{CH}} - CH_3$$

B
$$CH_3 - CH_2 - Cl$$

C
$$\underset{Cl}{\underset{\mid}{CH_2}} - CH = CH_2$$

D
$$CH_3 - CH = CH - Cl$$

Solution

$$CH-CH=CH_2 + HCl \xrightarrow{Organic \ peroxide} $$ $$CH_3 - \underset{Cl}{\underset{\mid}{CH}} - CH_3$$

The major product of the reaction is $$\displaystyle CH_3 - \underset{ \displaystyle Cl}{\underset{ \displaystyle\mid}{CH}} - CH_3$$
A molecule of $$\displaystyle HCl$$ adds to $$\displaystyle C=C$$ double bond. $$\displaystyle Cl$$ atom is added to most substituted C atom.

Note: Peroxide effect is observed only in case of $$\displaystyle HBr$$. It is not observed in case of $$\displaystyle HCl$$.
Question 7
1 / -0

Which of the following statements is false regarding the reaction between $$Cl_2$$ and $$C_2H_6$$?

A
It is a substitution reaction

B
The reaction will give a single product of $$C_2H_5Cl$$

C
The reaction mechanism involves free radicals

D
The reaction can be initiated with either sunlight or heat

Solution

$$C_2H_6 + Cl_2\rightarrow C_2H_5Cl + HCl$$
This reaction is a substitution reaction, involving chlorine free radicals, and this reaction can be initiated with either sunlight or heat.
This reaction produces ethyl chloride and Hydrochloric acid.
Question 8
1 / -0

$$X, Y$$ and $$Z$$ respectively are:

A

B

C

D

Solution

Option (A) represents the structures of $$X,Y$$ and $$Z$$.

$$X$$ is obtained when a molecule of $$D_2O$$ is added to carbon-carbon triple bond via oxymercuration demercuration. $$-OH$$ group is added to more substituted $$C$$ atom. This is followed by keto-enol tautomerism.

$$Y$$ is obtained when a molecule of water is added to carbon-carbon triple bond via oxymercuration demercuration. $$-OH$$ group is added to more substituted $$C$$ atom. This is followed by keto-enol tautomerism.

$$Z$$ is obtained when a molecule of water is added to carbon carbon triple bond via hydroboration oxidation. $$-OH$$ group is added to less substituted $$C$$ atom. This is followed by keto enol tautomerism.
Question 9
1 / -0

Out of $$5$$ isomers of $$C_4H_8$$, how many of them are cyclic?

A
$$1$$

B
$$2$$

C
$$3$$

D
$$0$$
Solution
There are five constitutional isomers with the formula $${ C }_{ 4 }{ H }_{ 8 }$$. They are:
1. But-1-ene
2. But-2-ene
3. 2-Methylpropane
4. Cyclobutane (cyclic)
5. methylcyclopropane (cyclic)
Question 10
1 / -0

Acetylene can be obtained by the reaction:

A
$$HCOOK \xrightarrow{Electrolysis}$$

B
$$CHI_3 + Ag \xrightarrow{\Delta}$$

C
$$CH_3 CH_2 OH \xrightarrow[443 K]{Conc. H_2SO_4}$$

D
$$Be_2C+ H_2O \rightarrow$$

Solution

Hint: Acetylene is the common name of the simplest alkyne.

Explanation:
■ In the first reaction, Potassium formate undergoes electrolysis to give hydrogen, Carbon dioxide and Potassium hydroxide.

■ In second reaction, Iodoform reacts with silver to give acetylene and silver iodide.

■ In the third reaction, Ethanol reacts with concentrated sulphuric acid to give ethene and water.

■ In fourth reaction, Beryllium carbide reacts with water to give methane and beryllium oxide.

Final answer:
The correct answer is option $$(B).$$