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Hydrocarbons Test - 57

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Hydrocarbons Test - 57
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  • Question 1
    1 / -0
    The energy required to vapourise one mole of benzene at it's boiling point is $$31.2\ kJ$$. For how long a $$100\ w$$ electric heater has to be operated in order to vaporize a $$100\ g$$ sample of benzene at it's boiling temperature?
    Solution
    Power =100 $$ \cfrac { joule }{ sec } $$
    For one mole = (31.2X1000)  $$ \cfrac { joule }{ sec } $$
    for 100gm $$\rightarrow$$  = (31.2X1000) X  $$ \cfrac { 100 }{ 78.11 } $$ joule

    Equal to 399.4 seconds.
  • Question 2
    1 / -0
    The reaction of one molecule of $$HBr$$ with one molecule of $$1,3-$$butadiene at $$40^{\circ}C$$ gives predominantly:
    Solution
    Solution:- (B) $$1$$-bromo -$$2$$-butene under thermodynamically controlled conditions

    $$C{H}_{2}=CH-CH=C{H}_{2} + HBr \longrightarrow \underset{1,2-\text{addition product}}{C{H}_{3}-\underset{\overset{|}{Br}}{CH}-CH=C{H}_{2}} + \underset{1,4-\text{addition product}}{C{H}_{3}-CH=CH-\underset{\overset{|}{Br}}{C{H}_{2}}}$$

    Under mild conditions (temprature $$=  80 ℃$$), kinetic product is the $$1, 2$$-addition product and under vigorous conditions, (temp. $$= 40 ℃$$) thermodynamic product is the $$1, 4$$-addition product. 

    Hence, $$1$$-bromo -$$2$$-butene is the major product under a given condition.
  • Question 3
    1 / -0
    Towards catalytic hydrogenation, the least reactive compound is:
    Solution
    As a number of $$\alpha$$-Hydrogen increases reactivity towards catalytic hydrogenation increases.
    $$CH_{2}$$=$$CH_{2}$$ have zero $$\alpha$$-Hydrogen. So, it is least reactive towards catalytic hydrogenation.
  • Question 4
    1 / -0
    Which of the following reactions does not occur in practice?
    Solution
    Option a does not occur in practice. Since the hydrogen attached to Carbon in triphenyl methane is not feasible, the reaction does not occur in practice.

  • Question 5
    1 / -0
    Major product is:

    Solution

  • Question 6
    1 / -0
    Which of the following compounds can be best prepared by Wurtz-reaction?
    Solution

  • Question 7
    1 / -0
    The number of alkene(s) which can produce-$$2$$-butanol by the successive treatment of (I) $$B_2H_6$$ in tetrahydrofuran solvent and (II) Alkaline $$H_2O_2$$ solution is _________.
    Solution
    $$CH_3-CH=CH-CH_3\overset{(1)B_2H_6}{\underset{(2)H_2O_2/OH^-}{\rightarrow}}\underset{Butan-2-ol}{CH_3-\underset{OH}{\underset{|}{C}}H-CH_2-CH_3}$$.

    Option A is correct.
  • Question 8
    1 / -0
    Product (A) is.

    Solution

  • Question 9
    1 / -0
    .

    Solution

  • Question 10
    1 / -0
    Find the product.

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