Self Studies
Selfstudy
Selfstudy

Hydrocarbons Test - 74

Result Self Studies

Hydrocarbons Test - 74
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following has the highest boiling point
    Solution
    The boiling point of n-heptane is 98.42 degrees celsius.

    The boiling point of n-butane is -1 degrees celsius.

    The boiling point of neopentane is 9.5 degrees celsius.

    The boiling point of isobutane is -11.7 degrees celsius.

    So $$ n-heptane$$ has the highest boiling point.
  • Question 2
    1 / -0
    The $$IUPAC$$ name of the compound 
    $$CH_3-CH(C_2H_5)-CH=CH-CH_3$$ is
  • Question 3
    1 / -0
    Methane and ethane both can be obtained in single step from 
    Solution
    Methyl iodide on wurtz reaction gives ethane and on reduction gives methane.

    $$CH_3I + 2H \xrightarrow[]{Zn/HCl} CH_4 + HI$$

    $$CH_3I + 2Na +ICH_3 \xrightarrow[\text{Ether}]{\text{Dry}} CH_3 - CH_3 + 2NaI$$
  • Question 4
    1 / -0
    Name the alkane with molecule formula $$C_{10}H_{20}$$
    Solution

  • Question 5
    1 / -0
    Ortho-dihydroxy benzene is 
    Solution
    o-dihydroxy benzene or catechol.

  • Question 6
    1 / -0
    Reaction $$C_2H_5I + C_5H_{11}I + 2Na \rightarrow C_2H_5 - C_5H_{11} + 2NaI$$ is called
    Solution
    this type reaction is called Wurtz reaction

  • Question 7
    1 / -0
    1,2,3-trihydroxybenzene is also known as:
    Solution
    1,2,3-Trihydroxybenzene, also known as pyrogallic acid or Pyrogallol. it's IUPAC name is benzene-1,2,3-triol.
    Hence, option $$A$$ is correct.

  • Question 8
    1 / -0
    Which one of the following characteristics apply to both ethene and ethyne?
    Solution
    Both ethene and ethyne decolourise Baeyer's reagent giving a brown precipitate.

    $$CH_{2}=CH_{2} + \underset{alk.}{KMnO_{4}}\xrightarrow [H_{2}O]{[O]}\underset{colourless}{\underset{OH}{\underset{|}{CH_{2}}}-\underset{OH}{\underset{|}{CH_{2}}}} + \underset{Brown}{MnO_{2}}$$

    $$CH\equiv CH + \underset{alk.}{KMnO_{4}}\xrightarrow{[O]}\underset{Oxalic\  acid}{\underset{COOH}{\underset{\!\!\!\!\!\!\!\!|}{COOH}}} + \underset{Brown}{MnO_{2}}$$
  • Question 9
    1 / -0
    $$R-CH_{2}-CCl_{2}-R\xrightarrow[]{Reagent}R-C\equiv C-R$$

    The reagent is
    Solution
    $$R-CH_{2}-CCl_{2}-R\xrightarrow[]{KOH+C_{2}H_{5}OH}R-C\equiv C-R+2HCl$$

    This reaction is an example of dehydrohalogenation. Hence, alcoholic $$KOH$$ is used as a reagent.
  • Question 10
    1 / -0
    Acetylene is obtained by the electrolysis of
    Solution
    Acetylene is obtained by the electrolysis of Potassium fumarate.

    $$\begin{matrix} CH & - & COOK & + \ 2H_{2}O\xrightarrow {Electrolysis} & CH & + \ 2CO_{ 2} \\ \!\!\!\! || &  &  &  & \!\!\!\! ||| &  \\ CH & - & COOK &  & CH &  \end{matrix}+2KOH+H_{2}$$

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now