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Hydrocarbons Test - 75

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Hydrocarbons Test - 75
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  • Question 1
    1 / -0
    Which of the following does not give alkane? 
    Solution
    The reaction of ethyl chloride with alcoholic KOH does not give alkane.

    $$CH_3 - CH_2 - Cl + \underset{\text{(alc.)}}{KOH} \rightarrow \underset{\text{Ethene}}{CH_2 = CH_2} + KCl + H_2O$$
  • Question 2
    1 / -0
    Which statement is not true concerning alkanes
    Solution
    No alkanes are not soluble in water. Water is a polar solvent and has hydrogen bonding. For any compound to be soluble in water , it should be polar or have hydrogen bonding in it.
    Other then that option A, all option are correct. 
  • Question 3
    1 / -0
    Benzene cannot undergo
    Solution
    Benzene can undergo substitution. Example: Nitration and Suphonation of Benzene.

    Benzene can undergo addition reaction. Example : Bromo-Benzene

    Benzene can oxidise to Phenol, Catechol, etc

    So the culprit is Elimination reaction.
    Benzene cannot undergo Elimination reaction.
  • Question 4
    1 / -0
    B.P. of branched chain alkanes as compared to straight chain alkanes are
    Solution
    As the number of branches increases, surface area decreases, due to which Van der Waal forces of attraction decreases. Hence, the boiling point also decreases.
  • Question 5
    1 / -0
    One mole of each of the following alkenes is catalytically hydrogenated. The quantity of heat evolved will be the lowest in the case of
    Solution
    Heat of hydrogenation is directly related to stability alkene i.e. more is the stability of alkene smallest is the heat of hydrogenation per mole. Among the given molecules Symmetrical alkenes are highly stable. Furthermore, Trans-2-butene is more stable than cis-2-butene because in trans-2-butene the bulky methyl groups are far apart whereas in cis-2-butene the bulky groups are crowded together hence there are stearic repulsions. Hence,trans-2-butene has the lowest heat of hydrogenation per mole
  • Question 6
    1 / -0
    Necessary conditions for halogenation are
    Solution
    Option C is the correct answer . 
    Necessary condition for halogenation is presence of halogen carrier.

     Halogenation is done in dark without any catalyst then according to free radical mechanism new halide radical will be attached to benzylic carbon. This reaction is carried out in dark so that required energy is supplied in general if it would be carried out in light chlorine free radical would be formed but in dark we use heat and supply energy. For chlorination 1kcal , bromination 16 kcal and iodination 33 kcal.

    in presence of catalyst like lewis acid like $$AlCl_3$$ and $$FeCl_3$$ electrophilic substitution takes place. 

  • Question 7
    1 / -0
    $$ R - CH = CH_2 + CO + H_2 \xrightarrow[{\text{High Pressure }}]{{\text{High Temp}}} \, RCH_2CH_2CHO $$ 
    The above reaction is 
    Solution
    $$\text{when reaction between any alkene and water gas}$$$$(CO+H_2)$$ $$\text{is occur at high tempereture and high pressure the}$$ product will be $$\text{an aldehyde and this processis called oxo process.}$$

    $$\text{thus, correct answer is B.}$$
  • Question 8
    1 / -0
    Which reactions are most common in alkenes
    Solution
    $$\text{Electrophillic addition reactions are shown by alkenes or alkynes in these reactions attacking species is electrophiles}$$

    $$CH_{3}-CH=CH_{2}+H^{+}\xrightarrow{Slow}\underset{2^{o} \,carbonium \,ion}{CH_{3}-\overset{+}{CH}-CH_{3}}$$

    $$CH_{3}-\overset{+}{CH}-CH_{3}+Br^{-}\xrightarrow{Fast}CH_{3}-\!\!\!\!\!\underset{\underset{2-Bromo \,propane}{Br}}{\underset{|}{CH}}\!\!\!\!-CH_{3}$$
  • Question 9
    1 / -0
    $$ A\xleftarrow [ \Delta  ]{ CU } CH_{ 3 }CH_{ 2 }OH\xrightarrow [ \Delta  ]{ AL_{ 2 }O_{ 3 } } B. $$ A and B respectively are
    Solution
    $$ CH_3CHO \xleftarrow [ \Delta]{Cu} CH_3CH_2OH \xrightarrow [ \Delta]{Al_2O_3 } CH_2 =CH_2 $$

    Option C is correct.
  • Question 10
    1 / -0
    Point out the wrong statement in relation to the structure of benzene
    Solution
    (A) Benzene typically undergoes substitution reactions, a reaction not typical of alkenes. Benzene reacts with bromine, in the presence of iron(III) bromide as a catalyst, to give a single monosubstituted product, $$C_6H_5Br$$.This result indicates that all six hydrogen atoms of benzene are chemically equivalent. 

    $$\textbf{(B) }$$The six-membered ring in benzene is a perfect hexagon (all carbon-carbon bonds have an identical length of 1.40 Å). The cyclohexatriene contributors would be expected to show alternating bond lengths, the double bonds being shorter (1.34 Å) than the single bonds (1.54 Å).

    $$\textbf{(C) }$$Benzene is commonly seen in Organic Chemistry and it has a resonance form. Benzene has two resonance structures, showing the placements of the bonds. Another example of resonance is ozone. Ozone is represented by two different Lewis structures.

    $$\textbf{(D) }$$In benzene, the π electrons are delocalized over all six atoms of the ring. In β-carotene, the π electrons are delocalized over 22 carbon atoms. 
    So, The answer for ghis question is option B. 
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