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Structure of Atom Test - 11

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Structure of Atom Test - 11
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  • Question 1
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    When an electron from an excited hydrogen atom undergoes transition from energy level  n = 4  to  n = 2, the emission of radiations will give rise to 

    Solution

    The spectral lines which arise due to transition of electrons from higher energy levels to the second energy level will appear in visible region. Balmer series lie in the visible region of EM spectrum.

  • Question 2
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    Bohr’s model of atom could explain quantitatively the general features of the structure of  

    Solution

    Neils Bohr proposed a model of hydrogen atom based on the quantum theory and explained the atomic spectrum of hydrogen.

  • Question 3
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    The product of the uncertainties of the exact position and exact momentum (or velocity) of an electron. The product of their uncertainties is always

    Solution

    The uncertainty principle says that we cannot measure the position (x) and the momentum (p) of a particle with absolute precision. The more accurately we know one of these values, the less accurately we know the other. Multiplying together the errors in the measurements of these values (the errors are represented by the triangle symbol in front of each property, the Greek letter "delta") has to give a number greater than or equal to half of a constant called "h-bar". This is equal to Planck's constant (usually written as h) divided by 2π.

    Δx. Δp ≥  h/4π

  • Question 4
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    The orbital with quantum numbers n = 4, l = 3 is 

    Solution

    For n=4 the possible  values of l are  0,1, 2, 3. The orbital with l = 3 is f orbital

  • Question 5
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    Arrange the electrons present in the 4s, 3d, 4p and 3p orbitals in the order of their increasing energies

    Solution

    Energy of orbital is determined by the n+l value. The orbital having higher n+l value will have higher energy. If n+l value is same then orbital having higher n value will have higher energy.

  • Question 6
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    Give the name and atomic number of the inert gas atom in which the total number of d-electrons is equal to the difference between the numbers of total p and total s electrons.

    Solution

    Kr has atomic no. 36. And in Kr total number of d-electrons is equal to the difference between the numbers of total p and total s electrons.

    no. of d electrons is 10

    no of p electrons- no of s electrons= 18-8= 10

  • Question 7
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    If a cation B3+ has 18 electrons, the atomic number of element B will be

    Solution

    In the formation of a cation with 3charges the atom looses 3 elctrons.  

    The no of electrons in the atom will be 18 + 3 = 21.

     In a neutral atom the no.of protons is equal to the no. of electrons. So atomic no. is 21.

  • Question 8
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    Among the following pairs of orbitals 2s and 3s, 4d and 4f, 3d and 3p, the orbitals that will experience the larger effective nuclear charge will be

    Solution

    An electron is shielded from the attractive interactions of the nucleus by the electrons in the inner shells.The repulsive and attractive  interactions of an electron depend on the shell and the orbital in which the electron is present

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