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Structure of Atom Test - 25

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Structure of Atom Test - 25
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  • Question 1
    1 / -0
    The $$d_{z^{2}}$$ orbital can give room only to:
    Solution
    Any orbital can give room only to 2 electrons (maximum)
  • Question 2
    1 / -0
    After completion of ‘$$np$$’ level, the electron enters into which level according to $$(n+p)$$ rule?
    Solution
    Energy of nd level would be higher than $$(n+1)s$$.
    $$nd=n+2$$,  $$(n+1)s=n+1$$.
    So, electron will enter into lower energy level.
    i.e, $$(n+1)s$$
    Let us take an example of $$'4p'$$ orbital. As per Moeller diagram, the orbital that will be filled after $$'4p'$$ orbital is $$'5s'$$. Hence, $$(n+1)s$$ orbital will be filled after $$'np'$$ orbital.
  • Question 3
    1 / -0
    Which of the following properties are similar for isotopes?
    Solution
    Isotopes have same atomic numbers but different mass numbers. This also means that the isotopes have the same number of electrons. 
    Chemical properties are determined by electronic configuration. So, with the same electronic configuration, they have similar chemical properties. 
  • Question 4
    1 / -0
    To which of the following is Bohr's theory applicable:
    I) $$He^{+}$$ 
    II) $$Li^{2+}$$
    III) Tritium  
    IV) $$Be^{2+}$$
    The correct combination is:
    Solution
    Bohr's atomic model explains the spectra of single-electron atoms like $$H$$-atom. It does not explain the spectra of multi-electron atoms. 

    So the atoms which are isoelectronic and have the same electronic configuration are well explained by this atomic model.

    $$He^+$$, $$Li^{2+}$$ and tritium $$_{ 1 }{ H }^{ 3 }$$ have same number of electrons as that of hydrogen atom i.e. $$1$$ while $$Be^{2+}$$ is formed by losing $$2e$$. So, it is a two-electron system.

    Option D is correct.
  • Question 5
    1 / -0
    Which of the following energy state is filled by an electron after the completion of $$4p$$ orbital?
    Solution
    When $$4p$$ orbital in any atom are filled completely, the next electron goes in $$5s(n+l=5+0=5)$$ not in $$4d(n+l=4+2=6)$$,electron first enters into the subshell which is having less $$(n+l)$$ value (energy). Hence the $$5s$$ is filled first than $$4d$$.
  • Question 6
    1 / -0
    The atomic number at which filling of a g-orbital is likely to begin is:
    Solution
    The above question can be answered on the basis of reasoning from analogy. We note that two periods have to pass before d-orbitals begin to fill. This is also true of the spot where f-orbitals commence filling. The second row where f-orbitals fill happens to be row #7 (the one starting with Fr). The first element where 5f-orbitals enter in is actinium (Ac, Z = 89). Adding 32 to this would give element #121 termed as Unbiunium, the first Super-Actinide.
  • Question 7
    1 / -0
    The best evidence that electrons are arranged in definite orbits or energy levels is based on the observation that:
    Solution
    The best evidence that electrons are arranged in definite orbits or energy levels is based on the observation that the spectral lines of hydrogen atom consist of discrete lines and not continuous bands.
  • Question 8
    1 / -0
    The band spectrum is caused by:
    Solution
    Hint: Band spectrum arises because of electron transition between the valence band and conduction band.

    Explanation:
    The band spectrum is caused by molecules. The energy levels of molecules are so close to each other that they combine to form a band. The valence band and conduction band are two types of bands. Electron transition between these two bands forms band spectrum.

    For example a spectrum of air. The bright bands are due to molecular oxygen (O2), molecular nitrogen (N2), and other molecules

    So from the above example, it is clear that Option A is the answer.

  • Question 9
    1 / -0
    In the lowest energy level of hydrogen atom, electron has an angular momentum equal to:
    Solution
    The angular momentum$$ L$$ $$=m_{e}vr$$ is on integer multiple of $$\dfrac{h}{2\pi }$$

    $$mvr=\dfrac{nh}{2\pi}$$ 

    For, $$n=1$$

    $$mvr=\dfrac{h}{2\pi}$$
  • Question 10
    1 / -0
    In potassium, the order of energy levels is:
    Solution
    The "4s" orbital is having lower energy than "3d" orbital. 

    The (n+l) value of "4s" orbital is lower than that of "3d" orbital.

    Option B is correct.
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