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Structure of Atom Test - 32

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Structure of Atom Test - 32
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  • Question 1
    1 / -0
    Determine the number of electron in the isotope of 'H' (mass no. 2).
    Solution
    The isotope has atomic number 1 and thus no. of protons is equal to no. of electrons = 1.
  • Question 2
    1 / -0
    For the energy levels in an atom, which one of the following statement is correct?
    Solution
    Hint: There are four types of quantum numbers. 

    Correct Answer: Option $$C$$

    Explanation for correct option :

    (C): The principal energy level N can have a maximum of 32 electrons:
    The principal energy level N can have a maximum of $$32$$ electrons.
    The maximum number of electrons present in a particular shell is calculated by 

    $$\text Formula = 2\times n^{2}$$

    Here " $$\mathrm{n}$$ " represents the shell number. 
    For instance, $$\mathrm{K}$$ shell is the first shell and it can hold up to $$2(1)^{2}=2$$ electrons. 
    Similarly, the $$L$$ shell is the second shell and it can hold up to $$2(2)^{2}=8$$ electrons. 
    This formula helps to calculate the maximum number of electrons that an orbit can accommodate.
    Principal energy level can have maximum $$2 \mathrm{n}^{2}$$ electron.
    For $$\mathrm{n}=4$$, it have maximum electron of $$2 * 4^{2}=32$$.
    Hence, the statement is true

    Explanation for incorrect options:

    (A): There are seven principal electron energy levels
    There are infinite principal electron energy levels.
    Hence, the statement is False.

    (B): The second principal energy level has four sub- energy levels and contains a maximum of eight electrons
    The second principal energy level has only two sub- energy levels and contains a maximum of eight electrons.
    For $$\mathrm{n}=2$$, it have maximum electron of $$2 *2 ^{2}=8$$.
    Hence, the statement is False.

    (D): The $$4s$$ sub-energy level has high energy than the $$3d$$ sub energy level.
    Energy of the orbits is decided by $$(n+l)$$ rule.
    $$n$$ is called principal quantum number. $$n=(1,2,3,4 \ldots . .)$$
    $$l$$ is known as azimuthal quantum number. $$l=(0,1,2 \ldots \ldots n-1)$$
    Solve the question step by step-
    $$4 s ; n=4$$ and for $$s, l=0$$
    Energy level of $$4 s$$ is decided by $$(n+l)$$ rule.
    So, energy level is $4+0 \Rightarrow 4$
    For $$3 d ; n=3$$ and $$l=2$$
    Energy level is $$(n+l) \Rightarrow(3+2) \Rightarrow 5$$
    $$3 d$$ is at a higher energy level than $$4 s$$.
    Hence, the statement is false.

  • Question 3
    1 / -0
    If Aufbau rule is not followed in filling of sub orbitals, then block of the element will change in :
    Solution
    If Aufbau rule is not followed,
    electronic configuration is K:
    1s$$^2$$ 2s$$^2$$ 2p$$^6$$ 3s$$^2$$ 3p$$^6$$ 3d$$^1$$.
    Last electron is in 3d(instead of $$4s$$),
    hence d block (but it is of $$s$$ block)
    in all other cases valence electron doesnt changes its position so block doesnt changes in those cases.
  • Question 4
    1 / -0
    Which of the following properties can only be a whole number?
    Solution
    Mass number is a whole number as it is sum of no protons and neutrons.
  • Question 5
    1 / -0
    Bohr's atomic model can explain the spectrum of:
    Solution
    Bohr's atomic model can explain the spectrum of atoms or ions which are uni-electron. It cannot explain the spectrum of the multi-electron system.
  • Question 6
    1 / -0
    If the energy of the second Bohr's orbit in H-atom is $$- 328 \ kJ$$ $$mol^{-1}$$, then what is the energy of the fourth Bohr orbit?
    Solution
    If energy of an electron in the $$n^{th}$$ orbit is $$E_n$$, according to the Bohr's atomic model is 

    $$E_n \propto \dfrac{Z^2}{n^2}$$, 

    Thus, $$\dfrac{E_4}{E_2}=\dfrac{2^2}{4^2}=\dfrac{1}{4}$$

    Now, $$E_2=-328 \ kJ \ {mol}^{-1}$$,

    $$E_4=\dfrac{1}{4} \times E_2 =-82 \ kJ \ {mol}^{-1}$$

    Hence, option $$A$$ is correct.
  • Question 7
    1 / -0
    When 3d orbital is completely filled, the next electron will enter the :
    Solution
    When 3d orbital is completely filled, the next electron will enter the 4p - orbital

    e order of filling is said to be obtained by starting at the top of the diagram and following the arrows. This process gives the order of filling of orbitals with electrons according to this sequence: 

    $$1s > 2s > 2p > 3s > 3p > 4s > 3d > 4p > 5s > 4d $$

  • Question 8
    1 / -0
    In 'Aufbau principle', the term Aufbau represents :
    Solution
    Aufbau principle originates from the German term Aufbau meaning building up or construction. It is used to determine the electronic configuration of an atom, molecule or ion.
  • Question 9
    1 / -0
    When 3d orbital is complete, the next entering electron goes into :
    Solution
    When 3d orbital is complete the next entering electron goes into 4p level.
    The order of increasing energies is $$\displaystyle  1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d ,5p, 6s$$
  • Question 10
    1 / -0
    The electron should be filled in the orbital in accordance with the increasing order of their energy. This statement is related with :
    Solution
    The electron should be filled in the orbital in accordance with the increasing order of their energy. This statement is related with Aufbau principle.
    According to Aufbau principle (also known as (n+l) rule), electrons are filled in different orbitals from lower (n+l) value orbital to higher (n+l) value orbital.
    In case (n+l) value is same, electron is filled first in orbital with lower value of n.
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