Structure of Atom Test

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Structure of Atom Test - 42

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Weekly Quiz Competition

Question 1
1 / -0

A sample of water is vaporized and tested in a mass spectrometer. There are $$3$$ isotopes of hydrogen, $$^{1}H, ^{2}H$$ and $$^{3}H$$. There are $$2$$ isotopes of oxygen, $$^{15}O$$ and $$^{16}O$$.
How many peaks would be expected to be found on the mass spectrum?

A
$$3$$

B
$$4$$

C
$$5$$

D
$$6$$

Solution

Various isotopes of water with different mass possible are:
$$^1H^1H^{ 15 }O(17)$$
$$^1H^1H^{ 16 }O(18),\ ^1H^2H^{ 15 }O(18)$$
$$^1H^2H^{ 16 }O(19),\ ^1H^3H^{ 15 }O(19),\ ^2H^2H^{ 15 }O(19)$$
$$^1H^3H^{ 16 }O(20),\ ^2H^3H^{ 15 }O(20),\ ^2H^2H^{ 16 }O(20)$$
$$^3H^3H^{ 15 }O(21),\ ^2H^3H^{ 16 }O(21)$$
$$^3H^3H^{ 16 }O(22)$$
Therefore total of 5 peaks will be present in the mass spectrum.
Hence, option $$C$$ is correct.
Question 2
1 / -0

Maximum number of electrons that an M-shell contain is/are _____________.

A
32

B
2

C
8

D
18

Solution

The general formula for number of electrons in nth shell is given by $$2(n^2)$$.
Now M shell is 3rd shell i.e, n = 3.
Therefore maximum number of electron $$=2(n^2)$$
$$=2\times 3^2$$
$$=2\times 9=18$$ electrons.
Question 3
1 / -0

Beer's Law allows the measurement of the progress of a reaction by measuring the change of which of the following?

A
Temperature

B
Surface Area

C
Concentration

D
All of the above

Solution

Beer's law stated that absorbance is proportional to the concentrations of the attenuating species in the material sample.
$$\therefore $$ Beer's law allows the measurement of the progress of a reaction by measuring the change of concentration.
Question 4
1 / -0

Which of the following is true about electrons in cobalt?

A
The last orbital to gain electrons as well as the first orbital to loose electrons is 4s

B
The last orbital to gain electrons as well as the first orbital to loose electrons is 3d

C
The last orbital to gain electrons is 3d while the first orbital to loose electrons is 4s

D
The last orbital to gain electrons is 4s while the first orbital to loose electrons is 3d

Solution

The electron configuration of cobalt is $$[Ar]3d^{7}4s^{2}$$
We know that $$4s$$ orbitals are lower in energy than $$3d$$
Therefore, $$4s$$ orbitals are filled first and then the $$3d$$ orbitals. So, the last orbital to gain electron is $$3d$$ whereas $$4s$$ orbitals are lost first during ionization. The electrons lost will come from the highest energy level furthest from the influence of nucleus. Since $$4s$$ is farthest from the nucleus, it is the first orbital to lose electrons.

Hence, option $$C$$ is correct.
Question 5
1 / -0

How would fingerprints on a cuvette during a visible spectrometry lab affect the concentration reading?

A
Concentration would be lower, since more light is being reflected and not detected by the spectrometry light sensor.

B
Concentration would be higher since more light is being reflected or absorbed, increasing the absorbance reading.

C
Concentration will stay the same since the fingerprints will only deflect the light slightly and not enough to affect the absorbance measurements.

D
Concentration will be increase since more light is absorbed by the solution, resulting in a decrease in the absorbance measurement.

Solution

Fingerprints on a cuvette would affect absorbance and concentration calculation by the fact that fingerprints absorb and scatter light slightly, despite not be readily visible. A cuvette (with fingerprints on it) will give a slightly higher absorbance reading and the measured concentration will be significantly higher than the actual concentration.
Hence the required answer is- (B) Concentration would be higher since more light is being reflected or absorbed, increasing the absorbance reading.
Question 6
1 / -0

What are isotopes?

A
These are the forms of the same element having the same atomic number but different atomic masses due to different nuclear structure.

B
These are the forms of the same element having the different atomic number but different atomic masses due to different nuclear structure.

C
These are the forms of the same element having the same atomic number but same atomic masses due to different nuclear structure.

D
none of these

Solution

Isotopes are the forms of same element having the same atomic number but different atomic masses due to different nuclear structure.

So, the correct option is $$A$$
Question 7
1 / -0

Given there are $$3$$ isotopes of hydrogen $$(^{1}H, ^{2}H$$ and $$^{3}H$$) and $$2$$ isotopes of oxygen $$(^{15}O$$ and $$^{16}O)$$, how many peaks would be expected on a mass spectrum for the hydronium ion, $$H_{3}O^{+}$$?

A
$$6$$

B
$$7$$

C
$$8$$

D
$$9$$

Solution

Peaks would be expected on a mass spectrum for different masses of compound.
For hydronium ion production by isotope of oxygen $$O^{15},O^{16}$$ and isotope of hydrogen $$H^1,H^2,H^3$$ there are 8 different masses of hydronium ion produced,so 8 peaks are generated on mass spectrum.
Question 8
1 / -0

Watermelon model of atom was proposed by:

A
Rutherford

B
Thomson

C
Bohr

D
Sommerfeld

Solution

J. J. Thomson proposed the watermelon model of the atom which is also known as the plum pudding model in which electrons are present inside the atom-like plumb in the pudding.
Question 9
1 / -0

If $$E_P$$ and $$E_k$$ represent potential energy and kinetic energy respectively, of an orbital electron, then according to Bohr's theory:

A
$$E_k= -E_p/2$$

B
$$E_k= -E_p$$

C
$$E_k= -2E_p$$

D
$$E_k= 2E_p$$

Solution

Potential energy of an orbital electron $$E_p=-\dfrac{Ze^2}{r}$$
Kinetic energy of an electron$$E_k=\dfrac{Ze^2}{2r}$$, where Z=atomic number
So, $$E_k=-\dfrac{E_p}{2}$$
Question 10
1 / -0

Rutherford model could not explain:

A
maxwell's theory of elctrodynamics

B
line spectra of atom

C
both A and B

D
None of these

Solution

Two main drawbacks of the Rutherford's model was it was unable to explain Maxwell's theory and line spectra of multi electronic species.

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Structure of Atom Test - 42

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Structure of Atom Test - 42

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SHARING IS CARING

Question 1

$$3$$

$$4$$

$$5$$

$$6$$

Solution

Question 2

32

2

8

18

Solution

Question 3

Temperature

Surface Area

Concentration

All of the above

Solution

Question 4

The last orbital to gain electrons as well as the first orbital to loose electrons is 4s

The last orbital to gain electrons as well as the first orbital to loose electrons is 3d

The last orbital to gain electrons is 3d while the first orbital to loose electrons is 4s

The last orbital to gain electrons is 4s while the first orbital to loose electrons is 3d

Solution

Question 5

Concentration would be lower, since more light is being reflected and not detected by the spectrometry light sensor.

Concentration would be higher since more light is being reflected or absorbed, increasing the absorbance reading.

Concentration will stay the same since the fingerprints will only deflect the light slightly and not enough to affect the absorbance measurements.

Concentration will be increase since more light is absorbed by the solution, resulting in a decrease in the absorbance measurement.

Solution

Question 6

These are the forms of the same element having the same atomic number but different atomic masses due to different nuclear structure.

These are the forms of the same element having the different atomic number but different atomic masses due to different nuclear structure.

These are the forms of the same element having the same atomic number but same atomic masses due to different nuclear structure.

none of these

Solution

Question 7

$$6$$

$$7$$

$$8$$

$$9$$

Solution

Question 8

Rutherford

Thomson

Bohr

Sommerfeld

Solution

Question 9

$$E_k= -E_p/2$$

$$E_k= -E_p$$

$$E_k= -2E_p$$

$$E_k= 2E_p$$

Solution

Question 10

maxwell's theory of elctrodynamics

line spectra of atom

both A and B

None of these

Solution

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