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Structure of Atom Test - 54

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Structure of Atom Test - 54
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  • Question 1
    1 / -0
    Energy of the third orbit of Bohr's atom is:
    Solution
    $$E_n = - 13.6\times(z^2/n^2)eV$$
    $$E_3 = - 13.6\times1/9eV$$
    $$ = - 1.5eV$$
  • Question 2
    1 / -0
    Which element with lowest atomic number .
    Solution
    The atomic number is defined as the number of protons present in an element.

    In sodium atom, the number of protons present  = $$11$$

    So, its atomic number is $$11$$

    Which is least from the rest of the given elements.

    Hence, the correct option is $$C$$
  • Question 3
    1 / -0
    What is the ratio of time periods $$(\dfrac{T_1}{T_2})$$ in $$2^{nd}$$ orbit of hydrogen atom to third orbit of $$He^+$$ ion?
    Solution
    $$\dfrac{T_H}{T_{He}}=\dfrac{n_1^3t_2^2}{n_2^3t_1^2}$$ 

    $$= \dfrac{8\times4}{3^3}=\dfrac{32}{27}$$ 

    The ratio is $$32:27$$.
  • Question 4
    1 / -0
    The carbonate of a metal is isomorphous (similar formula) with magnesium carbonate and contains 6.091 percent of carbon. The atomic weight of metal is:
    Solution
    Let the formula of unknown carbonate= $$XCO_3$$

    Molecular weight= $$x+12+48=(60+x)gmol^{-1}$$

    % of composition of carbon= $$\left [\dfrac{12}{(60+x)} \right]\times 100$$

    $$\Rightarrow 6.091= \cfrac {12}{60+x}\times 100$$

    $$\Rightarrow 0.06091(60+x)=12$$

    $$\Rightarrow x=137.01$$

    $$\therefore$$ The atomic weight of metal is $$137 g/mol$$.

    Hence, option $$C$$ is correct.
  • Question 5
    1 / -0
    A single electron orbits a stationary nucleus of charge $$+Z$$, where $$Z$$ is a constant. It requires 47.2 eV to excite electron from second Bohr orbit to third Bohr orbit, find the value of $$Z$$.
    Solution
    Position is $$n_1=2 \ \Rightarrow n_2=3$$ and $$\Delta E=47.2eV$$
    We have $$\Delta E=13.6z^2(\dfrac{1}{n_1^2}− \dfrac{1}{n_2^2})eV$$
    $$47.2=13.6z^2(\dfrac{1}{2^2}− \dfrac{1}{3^2})$$
    $$z=5$$
  • Question 6
    1 / -0
    Multiple of fine structure of spectral lines is due to:
    Solution
    It is because of sub energy levels. Previously the energy of sub energy levels was considered to be equal but it actually differs by about $$10^{-4}$$ eV. Hence fine spectral lines are observed
  • Question 7
    1 / -0
    If the speed of electrons in Bohr's first obtain of hydrogen is $$'X'$$ the speed of electrons in third orbit is:
    Solution
    We know,
    $$v = v_0 z/n$$    here $$ v_0 = X = $$ velocity of elctron in first orbit of hydrogen or velocity constant 
    for third orbit of hydrogen atom value of n is 3 and z is 1
    So $$ v = \dfrac{X }{3}$$
  • Question 8
    1 / -0
    What happens to the atomic number during a chemical reaction?
  • Question 9
    1 / -0
    Which of the following parameters are not same for all hydrogen like atoms and ions in their state?
    Solution

    As we know,

    $$r \propto n^2$$

    $$E \propto -\dfrac{z^2}{n^2}$$

    $$V\propto \dfrac{z}{n}$$

    $$mur=nh^2 \pi$$

    So, independent of $$z$$ so it will remain same.

    So, orbital angular momentum of electron

  • Question 10
    1 / -0
    Boron has 2 stable isotopes, $$10-B$$$$(19$$%) and $$11-B$$($$81$$%) the atomic mass that should appear for boron in the periodic table is:
    Solution

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