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Structure of Atom Test - 59

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Structure of Atom Test - 59
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  • Question 1
    1 / -0
    In hydrogen atom, the electron is making $$6.6\times 10^{15}rev/s$$ around the nucleus in an orbit of radius $$0.528A^0$$. The equivalent magnetic dipole moment is :
    Solution

  • Question 2
    1 / -0
    The velocity of the electron in 3rd orbit of hydrogen atom in $$cms^{-1}$$
    Solution
    For an electron,
    $$ e = 4.803 \times 10^{-10}esu$$

    $$m = 9.1\times 10^{-28}g$$

    $$ z  = 1 $$

    Radius of $$3rd$$ orbit = $$r_1\times n^2$$ = $$0.529 \times 10^{-8} \times 9$$

    $$V_n$$ = $$[ \dfrac{ze^2}{mr_n}]^{1/2}$$


    $$V_n $$ = $$7.29\times10^7cm sec^{-1}$$

    Hence,option C is correct.
  • Question 3
    1 / -0
    In a hydrogen like sample electron is in 2nd excited state,the energy of the 4th state of this sample is -13.6 eV,then the incorrect statement is:
    Solution

  • Question 4
    1 / -0
    A $$p -$$orbital can accommodate upto:
    Solution
    correct answer : 'B'

    the p-orbital can accommodate upto

    The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max. And the f sublevel has 7 orbitals, so can contain 14 electrons max
  • Question 5
    1 / -0
    The electron present in penultimate orbit of coinage metal atom are:-
    Solution

  • Question 6
    1 / -0
    The maximum number of electrons that can be contained in 
  • Question 7
    1 / -0
    A trend common to both group $$I$$ and $$VII$$ elements in the periodic table as atomic number increase is 
    Solution
    As we move down the group number of shells increases and hence atomic radius increases down the group.
  • Question 8
    1 / -0
    The $$71^{st}$$ electron of an element $$X$$ with an atomic number of $$71$$ enters into the orbital:
    Solution
    Electronic Configuration of Element X with atomic number 71 is $$[Xe] 4{f}^{14}  6{s}^{2} 5{d}^{1}$$.

    The Last electron will enter in 5d orbital. 

    Hence, the correct option is D.
  • Question 9
    1 / -0
    Electronic transition in $${\text{H}}{{\text{e}}^{\text{ + }}}$$ would emit light in which region when $${{\text{e}}^{\text{ - }}}$$ jumps from fourth orbit to second orbit :
    Solution

  • Question 10
    1 / -0
    The electron in hydrogen atom is in the first Bohr's orbit (n=1). The ratio of electronic transition energies, $$ \Delta E(n=1\rightarrow n=3)\  to \ \Delta E(n=1\rightarrow n=2)\  is $$:
    Solution

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