Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

The atomic number of element Unq is:

A
$$102$$

B
$$103$$

C
$$104$$

D
$$105$$

Solution

The atomic number of element $$Unq$$ is $$104$$. Its name is Unnilquadium. Its IUPAC official name is Rutherfordium. Its IUPAC symbol is $$Rf$$.
Question 2
1 / -0

The number of elements known in Mendeleev's presented periodic table is:

A
$$50$$

B
$$90$$

C
$$63$$

D
$$102$$

Solution

In Mendeleev’s periodic table, elements were placed based on the atomic mass, and chemical properties. During Mendeleev’s work, only 63 elements were found. After studying the properties of all elements, he found that the properties of elements were related to atomic mass.
Hence, correct option is C.
Question 3
1 / -0

Total number of groups in Mendeleev's table are:

A
$$8$$

B
$$9$$

C
$$7$$

D
$$10$$

Solution

Mendeleev’s periodic table is based on atomic masses. The elements in his periodic table are arranged in increasing order of their atomic masses. Elements with similar properties were placed directly one after another.
There are a total of 8 groups and 7 periods in Mendeleev's periodic table.
Hence, the correct option is A.
Question 4
1 / -0

The magnitude of electron affinity depends upon :

A
atomic radius

B
polarising power

C
ionization potential

D
the nuclear charge

Solution

The magnitude of electron affinity depends upon the nuclear charge. The halogens, which are one electron short of a completely filled outer subshell have the greatest attraction for an electron.
The greater the attraction for the electron, the more exothermic the process.
Question 5
1 / -0

Which of the following compound has no existence?

A
$$\mathrm{C}\mathrm{F}_{4}$$

B
$$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$

C
$$\mathrm{K}\mathrm{r}\mathrm{F}_{4}$$

D
$$\mathrm{H}\mathrm{e}\mathrm{F}_{4}$$

Solution

$$He$$ has electronic configuration of $$1{s}^{2}$$ so it cannot form four bond. Therefore $$HeF_4$$ cannot exists.
Question 6
1 / -0

Which pair of elements of atomic numbers given below will have similar chemical properties?

A
$$13, 22$$

B
$$3, 11$$

C
$$4, 24$$

D
$$2, 4$$

Solution

The elements with the atomic number $$3$$ and $$11$$ have the same properties because both elements have same valence shell configuration, i.e., $$ns^1$$.
Question 7
1 / -0

The total number of elements in VII A group of the periodic table is:

A
3

B
5

C
7

D
9

Solution

The VII group is halogen family and it comprises 5 elements $$F,\ Cl,\ Br,\ I$$ and $$At$$.
Question 8
1 / -0

The number of elements in the third period of the periodic table is :

A
2

B
8

C
18

D
32

Solution

The third period starts from Na (atomic number 11) and it ends at Ar (atomic number 18). So this period has 8 elements.
Question 9
1 / -0

Correct order of $$1^{st}$$ IP among following elements Be, B, C, N, O is:

A
B < Be < C < O < N

B
B < Be < C < N < O

C
Be < B < C < N < O

D
Be < B < C < O < N

Solution

The 1st Ionisation Potential increases across a period as atomic size decreases. Given elements are Be,B, C, N, O.
1st Ionisation Potential order is $$B<Be<C <O<N$$.
Question 10
1 / -0

If an element X is placed in group 14, the formula its chloride is:

A
$$XCl$$

B
$$XCl_{2}$$

C
$$XCl_{3}$$

D
$$XCl_{4}$$

Solution

As it is in group 14 it will have 4 electrons in the outer most shell. Hence it can share 4 electrons with 4 chlorine's because each chlorine can share only one electron. $$XCl_{4}$$ it forms this compound. Here as we mentioned that it shares because it cannot donate or accept 4 electrons rather than sharing is far better than that. Hence it is a covalent bond.

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Re-Attempt Weekly Quiz Competition

Classification of Elements and Periodicity in Properties Test - 14

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Classification of Elements and Periodicity in Properties Test - 14

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SHARING IS CARING

Question 1

$$102$$

$$103$$

$$104$$

$$105$$

Solution

Question 2

$$50$$

$$90$$

$$63$$

$$102$$

Solution

Question 3

$$8$$

$$9$$

$$7$$

$$10$$

Solution

Question 4

atomic radius

polarising power

ionization potential

the nuclear charge

Solution

Question 5

$$\mathrm{C}\mathrm{F}_{4}$$

$$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$

$$\mathrm{K}\mathrm{r}\mathrm{F}_{4}$$

$$\mathrm{H}\mathrm{e}\mathrm{F}_{4}$$

Solution

Question 6

$$13, 22$$

$$3, 11$$

$$4, 24$$

$$2, 4$$

Solution

Question 7

3

5

7

9

Solution

Question 8

2

8

18

32

Solution

Question 9

B < Be < C < O < N

B < Be < C < N < O

Be < B < C < N < O

Be < B < C < O < N

Solution

Question 10

$$XCl$$

$$XCl_{2}$$

$$XCl_{3}$$

$$XCl_{4}$$

Solution

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