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Classification of Elements and Periodicity in Properties Test - 15

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Classification of Elements and Periodicity in Properties Test - 15
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  • Question 1
    1 / -0
    How many periods are there in the long form of the periodic table?
    Solution
    There are seven horizontal rows in the periodic table corresponding to seven periods.
  • Question 2
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    The short periods and the long periods are________
    Solution
    Periods 2 and 3 are called short periods because we could find elements with s and p orbitals hence only 8 electrons fit in that where as in case of periods 4 and 5 it has even d orbitals hence more 10 electrons would be there in these periods compared to 2 and 3.

    Hence Short periods -2 and 3 with 8 elements each.

    Long periods - 4 and 5 with 18 elements each.

    Option C is correct.
  • Question 3
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    In periodic table, metallic elements appear :
    Solution
    Alkali and alkaline earth elements are metal and they belongs to I and II group so they are in the left-hand columns of table.
  • Question 4
    1 / -0
    What is the electronic configuration of lithium [ Atomic no. = 3, Mass no. = 7]?
  • Question 5
    1 / -0
    In long form, shortest period is____________.
    Solution
    In the long form of periodic table, the first period has $$2$$ elements, second and third have $$8$$ elements; fourth and fifth have $$18$$ elements and sixth period has $$32$$ elements with seventh period being incomplete. Thus the shortest among these is first period. Hence correct answer is first period.
  • Question 6
    1 / -0
    The electron configuration of $$_{11}Na^{23}$$ is
    Solution
    The electronic configuration of $$_{11}Na^{23}$$ is $$1s^{2},2s^{2},2p^{6},3s^{1}$$. It can also be written as $$[Ne]3s^1$$.
    Two electrons are present in the first shell, 8 electrons are present in the second shell and 1 electron is present in the last shell.

  • Question 7
    1 / -0
    $$4^{th}$$ period ends with :
    Solution
    $$[Ar] 3d^{10} 4s^{2} 4p^{6}$$ is the electronic configuration of last element of fourth period. The element is krypton.
  • Question 8
    1 / -0
    The pair of atomic numbers belonging to the same group are:
    Solution
    $$Z = 13 \:[Ne]\:3s^23p^1$$
    $$Z = 31 \:[Ar]\:3d^{10}4s^24p^1$$
    As valence electronic configuration is same, they belong to same group.
  • Question 9
    1 / -0
    Example of noble gas is
    Solution
    From periodic table all the options have last shell fully filled & are non reactive hence all are Nobel gas
  • Question 10
    1 / -0
    The atomic number of an element x is 12. The element left to it and right to it in same period of periodic table are :
    Solution
    Na has atomic number 11. Aluminium has atomic number 13.
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