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Classification of Elements and Periodicity in Properties Test - 22

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Classification of Elements and Periodicity in Properties Test - 22
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  • Question 1
    1 / -0
    $$EA_{1}$$ values of the following element has highest values.

    I) Be  II) Br  III) Mg   IV) Cl

    The correct answer is :
    Solution
    The electron affinity of an atom or molecule is defined as the amount of energy released or spent when an electron is added to a neutral atom or molecule in the gaseous state to form a negative ion. 

    Now $$Br$$ and $$Cl$$ have positive electron affinity value as if an electron is added to them, they achieve stable full-filled configuration, thus releasing energy.

    Hence the correct option is B.
  • Question 2
    1 / -0
    Electron affinity of chlorine is -348 kJ/mol. Then the electron affinity of fluorine is ........... in kJ/mol
    Solution
    Electron affinity of chlorine is greater than fluorine because due to smaller size of fluorine, the affinity for electron is less in fluorine.
  • Question 3
    1 / -0
    Wurtz reaction involves the reduction of alkyl halide with
    Solution
    Wurtz reaction involves the reduction of alkyle halide with Na in ether. Wurtz reaction is a convenient method for the preparation of symmetrical alkanes (R-R)  i.e. alkane containing even the number of C atoms.

    Option D is correct.

  • Question 4
    1 / -0
    The pair of elements that have similar chemical properties are :
    Solution

    A diagonal relationship exists between certain pairs of diagonally adjacent elements in the second and third periods. These are the first 20 elements in the periodic table. 

    For example, pairs lithium (Li) and magnesium (Mg), beryllium (Be) and aluminium (Al), boron (B) and silicon (Si) exhibit similar properties. Boron and Silicon are both semiconductors. 

    Thus, Magnesium and Lithium have similar properties.

    Hence, the correct answer is option $$\text{A}$$.

  • Question 5
    1 / -0
    Elements of which of the following group form anions most easily?
    Solution
    As halogens get octet configuration just by accepting 1 electron, they can form anions easily.
  • Question 6
    1 / -0
    Regarding electron affinity, which of the following is wrong?
    Solution
    Neon has octet configuration so it is not willing to accept the electron. Hence, it has less electron affinity than flourine.
  • Question 7
    1 / -0
                 Column-I                                             Column-II
    (Atomic number of elements)                         (IUPAC name)
                 (A) $$105$$                                                    (P) Uun
                 (B) $$107$$                                                    (Q) Uns
                 (C) $$109$$                                                    (R) Unp
                 (D) $$110$$                                                    (S) Une

    The correct match for A, B, C, D are respectively:
    Solution
    $$105$$- Unnilpentium - Unp
    $$107$$-Unnilseptium- Uns
    $$109$$-Unnilennium-Une
    $$110$$-Ununnilium-Uun

    The elements with atomic number greater than $$100$$ are named according to IUPAC. For their name first letter of each number is taken . for example $$105$$ is named as $$Unp$$ . $$U$$ for $$un$$ , $$n$$ for nil and $$p$$ for pent . 

    Hence, the correct option is $$\text{C}$$
  • Question 8
    1 / -0
    What is the value of electron gain enthalpy of $$Na^+$$ if $$IE_{1}$$ of $$Na$$ = $$5.1\ eV$$?
    Solution
    $$Na\longrightarrow { Na }^{ + }+{ e }^{ - }\quad Q=+5.1eV$$

    Thus $$5.1eV$$ is the energy absorbed in this process.

    $$\therefore Na^{+}+{ e }^{ - }\longrightarrow Na\quad Q=-5.1eV$$

    i.e., the electron gain enthalpy of $${ Na }^{ + }$$ is $$-5.1eV$$

    Hence, the correct option is $$\text{B}$$
  • Question 9
    1 / -0
    Considering the elements $$F,\ Cl,\ O$$ and $$N$$ the correct order of their chemical reactivity in terms of oxidizing property is:
    Solution
    Considering the elements $$F,\ Cl,\ O$$ and $$N$$, the correct order of their chemical reactivity in terms of oxidizing property is $$F > O > Cl > N$$.
    $$N,\ O$$ and $$F$$ are present in the same period. On moving from left to right in a period, the oxidizing power generally increases.

    $$F$$ and $$Cl$$ are present in the same group.
    On moving from top to bottom in a group, the oxidizing power generally decreases.

    Oxidizing property of O is more than Cl.
  • Question 10
    1 / -0
    The following are some statements about diagonal relationship.
    i) It is due to nearly same size, electronegativity and same polarising power
    ii) $$Li$$ has similar properties with $$H_{2}$$
    iii) $$BeO$$, $$Al_{2}O$$ are amphoteric in nature
    iv) All $$d$$-block elements are stable
    Solution
    Such relationship occurs because crossing and descending the periodic table have opposite effects.We have many like silicon and boron and so on.
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