Classification of Elements and Periodicity in Properties Test

Result

Classification of Elements and Periodicity in Properties Test - 25

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Mendeleev classified elements in:

A
increasing order of atomic groups.

B
seven periods and eight groups.

C
seven periods and nine groups

D
eight periods and seven groups.

Solution

Mendeleev kept elements in increasing order of atomic weights in seven periods and eight groups.
Therefore, option $$B$$ is correct.
Question 2
1 / -0

The total number of elements in the group $$IB$$ is:

A
4

B
5

C
7

D
9

Solution

Group 11 or IB or 1B, consisting of copper $$(Cu)$$, silver $$(Ag)$$, and gold $$(Au)$$. Roentgenium $$(Rg)$$.
Hence, option $$A$$ is correct.
Question 3
1 / -0

Identify the electronic configuration of an element whose atomic radii is determined by taking half the internuclear distance between like atoms.

A
$$[He] 2s^2 2p^5$$

B
$$[Ar] 4s^2$$

C
$$[Ne]3s^2$$

D
$$[Kr] 4d^5 5s^2$$

Solution

The atomic radii of non-metallic elements are determined by taking half the internuclear distance between like atoms. The only non-metal in the given options is option A, which is Flourine.
Question 4
1 / -0

Barium (Ba) belongs to group:

A
III A

B
IA

C
IB

D
lI A

Solution

Barium $$(Ba)$$ is alkali earth metal and belongs to group $$IIA$$
Question 5
1 / -0

To which block is an element, having electronic configuration $$1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$$, related in the periodic table?

A
$$s-$$block

B
$$p-$$block

C
$$d-$$block

D
$$f-$$block
Question 6
1 / -0

Arrange $$S,\ O$$ and $$Se$$ in ascending order of their electron affinity.

A
$$Se < S < O$$

B
$$O< Se<S$$

C
$$S < O < Se$$

D
$$S < Se < O$$
Solution
Hint: Electron affinity generally decreases down the period.

Explanation:
$$S$$, $$O$$ and $$Se$$ are all $$16^{th}$$ group elements.
Since electron affinity generally decreases down the period. So, the expected order would be $$O>S>Se$$
But this is not the observed case. The reason for this is that the oxygen atom is extremely small.
Therefore it cannot hold a negative charge in such a small space. Thus, its electron affinity is the lowest in its group. So, the correct order will be: $$O<Se<S$$
Final answer: Option $$B$$
Question 7
1 / -0

An element with $$Z = 46$$ belongs to :

A
9 group

B
10 group

C
11 group

D
12 group

Solution

Atomic number is 46 then it has 46 electrons.
It's configuration -$$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{8}$$
Hence, maximum principal quantum number is 5 whereas group number is 10.
Question 8
1 / -0

Ratio of radii of K, L, M shells of hydrogen atom is :

A
$$1 : 2: 3$$

B
$$1:\frac{1}{4}:\frac{1}{9}$$

C
1 : 4: 9

D
$$1:\frac{1}{2}:\frac{1}{3}$$

Solution

$$Radius \: of \: orbit=0.529\times n^2$$
$$Ratio =0.529\times 1^2:0.529\times 2^2:0.529\times 3^2=1 : 4: 9$$
Question 9
1 / -0

Atomic radii of $$3$$ non-metals $$A, B, C$$ belonging to the same group are in the order $$A < B < C$$. Predict the order of electron affinity values.

A
$$A>B>C$$

B
$$A< B< C$$

C
$$A< B> C$$

D
$$A> B< C$$

Solution

Electron affinity decreases from top to bottom within a group. This is caused by the increase in atomic radius. so answer is A>B>C
Question 10
1 / -0

Number of elements in 6th period are:

A
28

B
26

C
34

D
32

Solution

In period Six, there is Lanthanides series which contains $$14$$ element & generally periods contains $$18$$ element.
So $$18+14=32$$ element

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Classification of Elements and Periodicity in Properties Test - 25

Result

Classification of Elements and Periodicity in Properties Test - 25

Score

-

Rank

-

SHARING IS CARING

Question 1

increasing order of atomic groups.

seven periods and eight groups.

seven periods and nine groups

eight periods and seven groups.

Solution

Question 2

4

5

7

9

Solution

Question 3

$$[He] 2s^2 2p^5$$

$$[Ar] 4s^2$$

$$[Ne]3s^2$$

$$[Kr] 4d^5 5s^2$$

Solution

Question 4

III A

IA

IB

lI A

Solution

Question 5

$$s-$$block

$$p-$$block

$$d-$$block

$$f-$$block

Question 6

$$Se < S < O$$

$$O< Se<S$$

$$S < O < Se$$

$$S < Se < O$$

Solution

Question 7

9 group

10 group

11 group

12 group

Solution

Question 8

$$1 : 2: 3$$

$$1:\frac{1}{4}:\frac{1}{9}$$

1 : 4: 9

$$1:\frac{1}{2}:\frac{1}{3}$$

Solution

Question 9

$$A>B>C$$

$$A< B< C$$

$$A< B> C$$

$$A> B< C$$

Solution

Question 10

28

26

34

32

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.