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Classification of Elements and Periodicity in Properties Test - 34

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Classification of Elements and Periodicity in Properties Test - 34
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  • Question 1
    1 / -0
    Fluorine is the most reactive among all the halogens, because of it's:
    Solution
    Fluorine is the most reactive among all the halogens, because of it's low dissociation energy of $$F - F$$ bond. The dissociation energies (kcal/mol) in $$F_2, Cl_2, Br_2$$ and $$I_2$$ are 38, 57, 45.5 and 35.6 respectively.

    In the case of fluorine: 
    (a) short bond length and larger repulsion between non-bonding electrons lead to low dissociation energy. 
    (b) absence of multiple bonding leads to low dissociation energy.
  • Question 2
    1 / -0
    Element of which atomic number has highest electron affinity?
    Solution
    The element of atomic number 17 (chlorine) has the highest electron affinity.
    Chlorine has the most negative electron affinity of $$-348.3\ kJ/mol$$.
  • Question 3
    1 / -0
    Amongst the elements B, Al, C and Si
    the element having most negative electron gain enthalpy is:
    Solution
    Among the elements B, Al, C and Si, the element having most negative electron gain enthalpy is C.
    On moving from left to right in a period, the electron affinity increases as $$Z_{eff}$$ increases and size decreases.
    Hence, $$\displaystyle E.A _{C} > E.A _{B}$$.
    On moving down the group, the electron affinity decreases as $$Z_{eff}$$ decreases and size increases.
    Hence, $$\displaystyle E.A _{C} > E.A _{Si}$$.
  • Question 4
    1 / -0
    The correct order of electron affinity of $$B, C, N, O$$ is :
    Solution
    The correct order of electron affinity of B, C, N, O is $$\displaystyle O>C>B>N $$.

    On moving left to right in a period, the electron affinity becomes more negative.

    N has positive electron affinity due to extra stability of exactly half-filled p orbitals.

    Hence, the correct option is $$\text{C}$$
  • Question 5
    1 / -0
    The correct order of electron affinity for the different families is:
    Solution
    The correct order of electron affinity for the different families is $$\displaystyle Halogen>oxygen>carbon>nitrogen $$

    On moving from left to right in a period, the electron affinity increases (becomes more negative). This is due to decrease in size and increase in nuclear charge.

    The electron affinity of nitrogen is lower than the electron affinity of carbon due to the extra stability of half-filled p orbitals in nitrogen.
  • Question 6
    1 / -0
    Which is most acidic oxide ?
    Solution

    Hint :As oxidation state of central atom increases acidic nature increases.

    Correct Answer : $$D$$

    Explanation of Correct Option:
    The acidic nature increases with increase of percentage of oxygen and oxidation number of central atom. Therefore, the increasing order of the acidic character will be

                                                     $$ Cl_2O < Cl_2O_3 < Cl_2O_6 < Cl_2O_7$$.
    Oxidation number of $$Cl:$$     $$+1$$         $$+3$$           $$+6$$            $$+7$$

    More the positive charge on chlorine atom greater is the acidic nature of oxide, therefore, $$\mathrm{Cl}_{2} \mathrm{O}_{7}$$ is most acidic oxide.

    Explanation of Incorrect Option:
    In other oxides the oxidation state of chlorine less than $$+7$$ hence less acidic than $$\mathrm{Cl}_{2} \mathrm{O}_{7}$$
  • Question 7
    1 / -0
    Highest electron affinity is associated with the configuration :
    Solution
    Highest electron-affinity is associated with the configuration $$2s^2, 2p^2$$. When an electron is added to this, stable electronic configuration $$2s^2, 2p^3 $$ is obtained in which 2s sub-shell  is completely filled and 2p sub-shell is half filled. Hence, maximum amount of energy is released.
  • Question 8
    1 / -0
    Which of the following is affected by stable configuration of an atom?
    (a) Electronegativity
    (b) Ionisation potential
    (c) Electron affinity
    Correct answer is___________.
    Solution
    All of the following is affected by stable configuration of an atom.
    (a) Electronegativity. Inert gases have zero electronegativity.
    (b) Ionisation potential. Inert gases have very high value of ionisation energy as the removal of electron breaks the stable configuration.
    (c) Electron affinity
    .  Inert gases have positive value of the electron affinity due to presence of stable electronic configuration.
  • Question 9
    1 / -0
    Strongest reducing agent among the following is :
    Solution
    Strongest reducing agent among the halide ions is $$I^{\circleddash }$$. Tendency to lose electrons and reducing power are directly related to each other. Large sized iodide ion has maximum tendency to lose electrons and has maximum reducing power.
  • Question 10
    1 / -0
    Which of the following configuration will have least electron affinity?
    Solution
    The electron configuration $$ns^2np^3$$ will have least electron affinity. The np orbital is half filled which results in extra stability.
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