Self Studies
Selfstudy
Selfstudy

Classification of Elements and Periodicity in Properties Test - 36

Result Self Studies

Classification of Elements and Periodicity in Properties Test - 36
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    Which group of elements does not show diagonal relationship?
    Solution
    In addition to horizontal and vertical trends, there is a diagonal relationship between elements such as Li and Mg, Be and Al, B and Si.

    A diagonal relationship is said to exist between certain pairs of diagonally adjacent elements in the second and third periods of the periodic table.

    But $$C,\,P$$ doesn't show diagonal relationship.
  • Question 2
    1 / -0
    Which of the following properties is nearly same for two families?
    Family-1; Be, Mg, Ca, Sr........
    Family-2; He, Ne, Ar, Kr........
    Solution
    The electron affinity is nearly same for two families. 
    Family-1 Be, Mg, Ca, Sr........
    Family-2 He, Ne, Ar, Kr........
    Electron affinities of alkaline earth metals (group 2 metals) and noble gases (group 18 members) are positive.
    This is due to
    (a) stable configurations $$(ns^2)$$ of the valence shells of alkaline earth metals.
    (b) stable configuration $$(ns^2np^6)$$ of noble gases.
  • Question 3
    1 / -0
    Which one of the following order is not in accordance with the property stated against it?
  • Question 4
    1 / -0
    The electronic configuration of the element which is just above the element with atomic number 43 in the same periodic group is :
    Solution
    The element with atomic number 43 is Tc and the element just above this element is 43-18= 25 which is Mn$$[Ar]{ 3d }^{ 5 }{ 4s }^{ 2 }$$
  • Question 5
    1 / -0
    Many properties of an element and its compounds can be predicted from the position of that an element in the periodic table. What property could not be predicted this way?
    Solution
    $$\left( \ast  \right) $$ Many properties of an element from position of element in periodic table some properties.
    (i) Acidic or basic nature of oxide
    (ii) Oxidationstate
    (iii) Formula of oxide
    (iv) Metallic or non-metallic oxide.
    But it cannot tell number of isotopes it has.
    Ans :- C
  • Question 6
    1 / -0
    The given diagram represents _________.

    Solution
    The electronic configuration is defined as a distribution of electrons of an atom or molecule in the atomic or molecular orbital.
    A diagram shows the distribution of an electron in shells of the atom. There are total $$16$$ protons and $$16$$ neutrons. A number of protons are equal to an atomic number. So, the given diagram is of sulphur having one negative charge. In neutral atom Number of protons is equal to a number of electrons and this diagram has one electron more i.e. $$17$$ electron. Hence, it is $$S^-$$ represented by the diagram.
  • Question 7
    1 / -0
    According to Mendleev's periodic law which properties of the elements are the periodic function of their atomic masses?
    Solution
    According to Mendeleev's periodic law physical and chemical properties both of the elements are the periodic function of their atomic masses
  • Question 8
    1 / -0
    Which of the following statements is incorrect about the trends in periodic properties in the periodic table ?
    Solution
    Electron affinity of noble gases is zero as these are highly inert gases because of their completely filled shells they have no tendency to gain or lose electrons.
  • Question 9
    1 / -0
    An element M belongs to the group 1 and period 3 of the modern periodic table. Out of the following statement, which is the true about 'M'?
    Solution
    Group 1 elements are highly electropositive in nature as they can easily lose one electron which is present in their valence shell to attain stable configuration and so is electropositive.
  • Question 10
    1 / -0
    The element having electronic configuration $$[Kr]4d^{10}\, 4f^{14}\, 5s^2\, 5p^6\, 5d^1\, 6s^2$$ belongs to :
    Solution
    The last 4f subshell in which the electrons are filled in the electronic configuration of element states that the element belongs to f block.
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now