Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 37

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Weekly Quiz Competition

Question 1
1 / -0

Electronic configuration of $$Si$$ in ground state is _____________.

A
$$2, 8, 1$$

B
$$2, 8, 2$$

C
$$2, 8, 4$$

D
$$2, 8, 3$$
Question 2
1 / -0

Which of the following sets does not belong to the same group?

A
$$Li,Na,K$$

B
$$N,O,F$$

C
$$Be,Mg,Ca$$

D
$$He,Ne,Ar$$

Solution

N,O,F belongs to same period not same group.
Question 3
1 / -0

What are the electronic configuration of $$Na^{+}$$ and $$Cl^{-}$$ ions?

A
$$Na^{+}=2, 8, 2$$ and $$Cl^{-}=2, 8, 7$$

B
$$Na^{+}=2, 8$$ and $$Cl^{-}=2, 8, 8$$

C
$$Na^{+}=2, 8, 2$$ and $$Cl^{-}=2, 8, 6$$

D
$$Na^{+}=2, 8$$ and $$Cl^{-}=2, 8, 7$$

Solution

Atomic number of $$Na = 11$$ and thus atomic no. of $$Na^{+}$$ $$=$$10 and E.C $$= 2, 8$$
Atomic number of Cl $$=$$ 17 and thus atomic no. of $$Cl^{-}$$ $$=$$ 18 and E.C $$=$$ 2, 8, 8
Question 4
1 / -0

Which element of 2nd period forms most acidic oxide?

A
Flourine

B
Nitrogen

C
Boron

D
Carbon

Solution

The acidity of the oxides increases along the $$II$$ period from left to right. Thus the oxide of Florine is most acidic in nature
Question 5
1 / -0

The electronic configuration of a dipositive metal ion $$M^{2+}$$ is $$2, 8, 14$$ and its ionic weight is $$56$$. The number of neutrons in its nucleus would be:

A
$$30$$

B
$$32$$

C
$$34$$

D
$$42$$

Solution

Dipositive ion has $$24$$ electrons and hence atom of the metal will have $$26$$ electrons and $$26$$ protons.

No. of neutrons = Atomic wt. - No. of protons

$$= 56-26$$

$$= 30$$

Hence, option $$A$$ is correct.
Question 6
1 / -0

Who was the first to classify the elements into metals and non-metals?

A
Meyer

B
Mendeleev

C
Lavoisier

D
None of the above

Solution

Antoine Lavoisier first classified the elements into different categories based on their chemical and physical properties. These categories of elements include metals, nonmetals and metalloids, and noble gases.
Hence, option C is correct.
Question 7
1 / -0

Which is the correct electronic configuration of $$Cr$$(Chromium)?

A
$$1s^2 2s^22p^63s^23p^64s^1 3d^5$$

B
$$1s^22s^22p^63s^23p^64s^23d^4$$

C
$$1s^22s^22p^63s^23p^64s^23d^6$$

D
$$1s^22s^22p^63s^23p^64s^13d^8$$

Solution

Atomic number of $$Cr = 24$$
Electronic configuration of $$Cr= 1s^2, 2s^2,2p^6,3s^2,3p^6,4s^1,3d^5$$
Exactly half-filled and d orbitals give extra stability to $$Cr$$ atom.
Question 8
1 / -0

Which of the following is correct for electron affinity?

A
$$F > Cl > Br > l$$

B
$$CI > F > Br > I$$

C
$$CI > Br > I > F$$

D
None of these

Solution

Electron affinity is the amount of energy released when an electron is added to isolated gaseous atom. Electron affinity decreases down the group.
The electron affinity of fluorine is less than chlorine due to its smaller size.

So the correct order for electron affinity is $$CI > F > Br > I$$.

Hence, the correct option is $$\text{B}$$
Question 9
1 / -0

The correct order of electron affinities of $$S,\ N,\ O$$ and $$Cl$$ is:

A
$$O = Cl < S = N$$

B
$$O < S < Si < N$$

C
$$N < O < S < Cl$$

D
$$O < N < Cl < S$$

Solution

Electron affinity is the tendency is attract shared pair of electron towards itself. Its value decreases in a group and increases in a period. The correct order of electron affinities is as follows $$N < O < S < Cl$$.
Question 10
1 / -0

Number of electrons in $$M$$ shell of an element with atomic number $$28$$ is _______.

A
18

B
16

C
8

D
2

Solution

Atomic number 28 represent electronic configuration K, L, M -2, 8, 18. Hence, M shell of the element contain 18 electrons.

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Classification of Elements and Periodicity in Properties Test - 37

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Classification of Elements and Periodicity in Properties Test - 37

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Question 1

$$2, 8, 1$$

$$2, 8, 2$$

$$2, 8, 4$$

$$2, 8, 3$$

Question 2

$$Li,Na,K$$

$$N,O,F$$

$$Be,Mg,Ca$$

$$He,Ne,Ar$$

Solution

Question 3

$$Na^{+}=2, 8, 2$$ and $$Cl^{-}=2, 8, 7$$

$$Na^{+}=2, 8$$ and $$Cl^{-}=2, 8, 8$$

$$Na^{+}=2, 8, 2$$ and $$Cl^{-}=2, 8, 6$$

$$Na^{+}=2, 8$$ and $$Cl^{-}=2, 8, 7$$

Solution

Question 4

Flourine

Nitrogen

Boron

Carbon

Solution

Question 5

$$30$$

$$32$$

$$34$$

$$42$$

Solution

Question 6

Meyer

Mendeleev

Lavoisier

None of the above

Solution

Question 7

$$1s^2 2s^22p^63s^23p^64s^1 3d^5$$

$$1s^22s^22p^63s^23p^64s^23d^4$$

$$1s^22s^22p^63s^23p^64s^23d^6$$

$$1s^22s^22p^63s^23p^64s^13d^8$$

Solution

Question 8

$$F > Cl > Br > l$$

$$CI > F > Br > I$$

$$CI > Br > I > F$$

None of these

Solution

Question 9

$$O = Cl < S = N$$

$$O < S < Si < N$$

$$N < O < S < Cl$$

$$O < N < Cl < S$$

Solution

Question 10

18

16

8

2

Solution

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