Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 41

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Weekly Quiz Competition

Question 1
1 / -0

The number of electrons in different shells of sodium(Atomic no. - 11) are :

A
$$2,9$$

B
$$1,8,2$$

C
$$2,8,1$$

D
$$2,7,2$$

Solution

Atomic number of sodium is 11.
Number of protons = number of electrons = 11
First shell can accommodate 2 electrons so $$K = 2$$.
Second shell can accommodate maximum of 8 electrons so $$L = 8$$
Now remaining 1 electron will be accommodated in M i.e 1
So the configuration is $$2,8,1$$
Question 2
1 / -0

The number of electrons in different shells of chlorine(Atomic no. - 17) are :

A
$$2, 7, 8$$

B
$$1, 7 ,10$$

C
$$2, 8, 7$$

D
$$2, 9, 6$$

Solution

Atomic number of chlorine is 17. Number of protons=number of electrons = 17
First shell can accommodate 2 electrons so $$K = 2$$.
Second shell can accommodate maximum of 8 electrons so $$L = 8$$
Third shell can accommodate 7 electrons. Therefore configuration is $$2,8,7$$
Question 3
1 / -0

Which of the following elements mentioned has the lowest electronegativity?

A
Mg

B
Al

C
Na

D
P

Solution

An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus. The higher the associated electronegativity number, the more an element or compound attracts electrons towards it. So in moving across a period from $$Na, Mg, Al, P$$ in a period the electronegativity increases as the atomic size decreases and the electrons are attracted towards the nucleus.The element Phosphorous has highest while Na has lowest electronegativity.
Question 4
1 / -0

The ratio of the maximum number of electrons (starting from the innermost electrons) the shells can accommodate is :

A
$$1:4:9:16$$

B
$$4:9:1:16$$

C
$$1:2:3:4$$

D
$$2:5:8:11$$

Solution

Maximum number of electrons in $$K, L, M, N$$ are $$2,8,18,32$$ Ratio will be $$2:8:18:32$$. Simplifying this we get $$1:4:9:16$$.
Question 5
1 / -0

Which of the following relation is true?
(Max denotes the maximum number of electrons. K, L, M, N represent the shells)

A
$$Max(N)+Max(L)=2(Max(K)+Max(M))$$

B
$$Max(N)+Max(L)=Max(K)+Max(M)$$

C
$$2(Max(N)+Max(L))=Max(K)+Max(M)$$

D
$$Max(M)+Max(L)=(Max(K)+Max(N))$$

Solution

$$Max(M)=18, Max(N)=32, Max(L)=8, Max(K)=2$$.
Now substituting the value in A we get
$$LHS =32+8=40$$
$$RHS =20\times 2=40$$
Question 6
1 / -0

Find the ratio of the following: (Max (M) +Max (N)) / (Max (K) +Max (L))where Max denotes the maximum number of electrons. K, L, M, N represent the shells.

A
$$4$$

B
$$5$$

C
$$6$$

D
$$7$$

Solution

$$Max(M)=18, Max(N)=32, Max(L)=8, Max(K)=2$$.
Substituting the values of all these into the ratio we get,
$$\dfrac{(32+18)}{(2+8)}=5$$
Question 7
1 / -0

As atomic size increases, electron affinity :

A
increases

B
decreases

C
depends on elements

D
none of the above

Solution

A trend of decreasing electron affinity going down the groups in the periodic table is because the additional electron will be entering in an orbital farther away from the nucleus. Since this electron is far from the nucleus it experiences less attraction towards the nucleus and would release less energy when added.
Question 8
1 / -0

Which of the following can be found in the second period?

A
Potassium

B
Lithium

C
Uranium

D
Helium

E
Magnesium

Solution

Lithium can be found in the second period. The outer electronic configuration of Li is $$2s^1$$. Thus, the last electron enters 2s orbital.
Question 9
1 / -0

Which one of the following is least chemically reactive?

A
Ar

B
O

C
S

D
Ti

E
U

Solution

Noble gases ( group 18 elements) are chemically inert with low reactivity due to stable configuration (completely filled valence electron) with zero valency like He, Ne, Ar, Kr. So, noble gas does not combine with other elements. Argon is a noble gas so it is least chemically reactive.
Question 10
1 / -0

Element $$X$$ forms a chloride with the formula $$XCl_2$$, which is a solid with a high melting point. $$X$$ would most likely be in the same group of the Periodic Table as:

A
$$Na$$

B
$$Mg$$

C
$$Al$$

D
$$Si$$

Solution

Elements of group $$Na$$ form $$XCl$$ halide.
Elements of group $$Mg$$ form $$XCl_2$$ halide.
Elements of group $$Al$$ form $$XCl_3$$ halide.
Elements of group $$Si$$ form $$XCl_4$$ halide.

As an element, $$X$$ forms a chloride with the formula $$XCl_2$$, which is solid with a high melting point. $$X$$ would most likely be in the same group of $$Mg$$.

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Classification of Elements and Periodicity in Properties Test - 41

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Classification of Elements and Periodicity in Properties Test - 41

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Question 1

$$2,9$$

$$1,8,2$$

$$2,8,1$$

$$2,7,2$$

Solution

Question 2

$$2, 7, 8$$

$$1, 7 ,10$$

$$2, 8, 7$$

$$2, 9, 6$$

Solution

Question 3

Mg

Al

Na

P

Solution

Question 4

$$1:4:9:16$$

$$4:9:1:16$$

$$1:2:3:4$$

$$2:5:8:11$$

Solution

Question 5

$$Max(N)+Max(L)=2(Max(K)+Max(M))$$

$$Max(N)+Max(L)=Max(K)+Max(M)$$

$$2(Max(N)+Max(L))=Max(K)+Max(M)$$

$$Max(M)+Max(L)=(Max(K)+Max(N))$$

Solution

Question 6

$$4$$

$$5$$

$$6$$

$$7$$

Solution

Question 7

increases

decreases

depends on elements

none of the above

Solution

Question 8

Potassium

Lithium

Uranium

Helium

Magnesium

Solution

Question 9

Ar

O

S

Ti

U

Solution

Question 10

$$Na$$

$$Mg$$

$$Al$$

$$Si$$

Solution

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