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Classification of Elements and Periodicity in Properties Test - 42

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Classification of Elements and Periodicity in Properties Test - 42
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  • Question 1
    1 / -0
    Among the following which one has the greatest affinity for electrons?
    Solution
    Since chlorine is the most electronegative with highest tendency to gain one electron with 2,8,7 electronic configuration forming a complete octet.So it has the highest affinity for electrons.
  • Question 2
    1 / -0
    Which is the chemically most active element?
    Solution
    Fluorine is chemically the most active element, reacting with virtually every element. It even reacts with the noble gases at high temperatures and pressures. Fluorine has 7 valence electrons so, it only needs one more to complete the octet which it needs to be stable. Fluorine is most electronegative element. This makes it very easy for fluorine to bond with almost any other element.
  • Question 3
    1 / -0
    The outermost configuration of the least reactive element is:
    Solution
    The outermost configuration of the least reactive element is $$ns^2\;np^6$$.
    Because, it has fully filled electrons in outermost shell. 
    So, answer is $$D$$.
  • Question 4
    1 / -0
    From Electronic configuration from $$1{ s }^{ 2 }2{ s }^{ 2 }2{ p }^{ 6 }3{ s }^{ 2 }3{ p }^{ 6 }4{ s }^{ 1 }$$ to $$1{ s }^{ 2 }2{ s }^{ 2 }2{ p }^{ 6 }3{ s }^{ 2 }3{ p }^{ 5 }4{ s }^{ 2 }$$ an electron would:
    Solution
    When the electron is moved from 3p subshell to 4s an electron move to the excited state by absorption of energy. 

    Electrons orbit the nucleus in seven distinct regions called energy levels. 

    When the atom is in the ground state, the electron is as close to the nucleus as it can get (the first energy level, n = 1) and an electron has the least amount of energy possible for an electron. 

    When the atom absorbs energy the electron can jump up to a higher energy level (n = 2,  or n = 3) When this happens we say the atom is in an excited state.

    Hence, the correct option is $$\text{A}$$
  • Question 5
    1 / -0
    Number of orbits present in argon is:
    Solution
    Atomic number of argon = $$18$$
    Therefore, number of electrons = $$18$$
    Thus, electronic configuration of argon is $$K(2), L(8), M(8)$$
    Number of orbit in argon = $$3$$
  • Question 6
    1 / -0
    In a group, basic nature __________ from top to bottom.
    Solution
    As we move down the group, the IE decreases and thus metallic character increases. 

    As a result, the basic character of the elements increases down the group with increasing metallic nature (decreases IE and increases size). 

    Thus In a group, basic nature increases from top to bottom. 

    Hence, the correct option is $$\text{A}$$
  • Question 7
    1 / -0
    After the classification of elements study of elements become____________.
    Solution
    After the classification of elements study of elements become $$\text{easy}$$.
    Classification of elements helps us to approach a systematic study of various elements found in nature without which it would be really difficult to study the properties of elements in a streamlined manner.
  • Question 8
    1 / -0
    Classification of elements makes the study of physical and chemical properties of elements ________ and __________.
    Solution
    Periodic classification of elements is the method by which elements are grouped on the basis of their characteristics. Classification of elements makes the study of physical and chemical properties of elements simple and organised.
  • Question 9
    1 / -0
    Identify less reactive element from the following :
    Solution
    Out of given options $$_{ 10 }{ Y }^{ 20 }$$ has inert gas configuration. Thus $$_{ 10 }{ Y }^{ 20 }$$ is least reactive as it has a stable electronic configuration (completed octate).
  • Question 10
    1 / -0
    Which valence shell electrons arrangement is that of a metallic element?
    Solution
    Answer : $$2, 1$$
    (1) $$2, 1$$ valence shell electrons arrangement for Lithium metal. (electronic configuration is $$1s^{2} 2s^{1}$$
    (2) Other valence shell $$e^{\ominus}$$ are $$p-$$block elements of which is generally non-metals of metalloids.
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