Classification of Elements and Periodicity in Properties Test

Result

Classification of Elements and Periodicity in Properties Test - 45

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following element will show almost same reactivity like $$Ca$$ ?

A
$$Cr$$

B
$$Mn$$

C
$$Sc$$

D
$$Na$$

Solution

A diagonal relationship is said to exist between certain pairs of diagonally adjacent elements in the second and third periods of the periodic table. Diagonal relationships occur because of the directions in the trends of various properties as you move across or down the periodic table. Many of the chemical properties of an element are related to the size of the atom.
$$ Ca $$ and $$ Na $$ show diagonal relationship hence, similar properties. Hence, they show almost same reactivity.
Question 2
1 / -0

Which of the following does not represent the correct order of the properties indicated?

A
$$O^{-2} > Ne > Mg^{2+} > Al^{3+}$$ (Size)

B
$$N^{3-} > O^{2-} < F^- < Na^+$$ (Nuclear charge)

C
$$Li > Be > B > C$$ (Electron gain enthalpy)

D
$$Li < Na > K > Cs $$ (IE)$$_1$$

Solution

In any group zero group elements i.e inert gases have greatest size as their van der Waal's radius is measured instead of covalent, so $$O^{2-}>Ne>Mg^{2+}>Al^{3+}$$ size order is incorrect.
Question 3
1 / -0

What is the IUPAC symbol of Rutherfordium?

A
Rt

B
Ru

C
Rf

D
Rd

Solution

Rutherfordium is a chemical element with symbol Rf and atomic number 104, named in honor of physicist Ernest Rutherford. It is a synthetic element (an element that can be created in a laboratory but is not found in nature) and radioactive; the most stable known isotope, 267 Rf, has a half-life of approximately 1.3 hours.
Question 4
1 / -0

What is the atomic number of the element with symbol Uus?

A
117

B
116

C
115

D
114

Solution

Ununseptium have atomic number 117 having symbol $$Uus$$.
U stands for 1,
u stands for 1,
s stands for 7.

Hence, the correct option is $$A$$.
Question 5
1 / -0

For the properties mentioned, the correct trend for the different species is :

A
inert pair effect - $$Al > Ga > In$$

B
first ionization enthalpy - $$B > Al > Tl$$

C
strength as Lewis acid - $$B{ Cl }_{ 3 } > Al{ Cl }_{ 3 } > Ga{ Cl }_{ 3 }$$

D
oxidising property - $${ Al }^{ +3 } > { In }^{ +3 } > { Tl }^{ +3 }$$

Solution

On moving down in group tendency to accept lone pair decreases. Therefore, lewis acid strength decreases $$BCl_3>AlCl_3>GaCl_3$$
Question 6
1 / -0

An element with atomic number $$17$$ is placed in the group $$17$$ of the long from periodic table. Element with atomic number $$9$$ is placed above and with atomic number $$35$$ is placed below it. Element with atomic number $$16$$ is placed left and with atomic number $$18$$ is placed right to it. Which of the following statements are correct?

a) Valency of the element with atomic number $$18$$ is zero.

b) Elements with same valency will have atomic number $$16$$, $$17$$ and $$18$$.

c) Valency of element with atomic number $$9$$, $$17$$ and $$35$$ is one.

d) Element with atomic number $$17$$ is more electronegative than element with atomic number $$16$$ and $$35$$.

A
(a), (b) and (c)

B
(a), (c) and (d)

C
(b), (c) and (d)

D
(a), (b) and (d)
Solution
1. The element with the atomic number 18 is argon. It is a noble gas and belongs to zero group or 18th group. It has its octet complete and so the valency is zero.
2. Elements with atomic umber 9, 17 and 35 are F, Cl and Br. They are all halogens and belongs to group 17. All halogens have valency 1.
3. As the atomic size increases, electronegativity decreases. In a period electronegativity increases and in a group it decreases. Thus 17 is more electronegative than 16 and 35.
4. Hence, the correct option is $$B$$.
Question 7
1 / -0

Group $$15$$ elements have more electron gain enthalpy than group $$16$$ elements. The correct reason for this is:

A
half-filled stability of gp. $$15$$ elements

B
poor shielding in gp. $$15$$ elements

C
poor shielding in gp. $$16$$ elements

D
half-filled stability of gp. $$16$$ elements

Solution

The atoms having half-filled and fully filled orbitals are comparitively more stable, hence more energy is required to remove.the electron from such atoms. Therefore group $$15$$ have more I.E than gp.$$16$$ elements.
Question 8
1 / -0

Which of the following atoms should have the highest 1st electron affinity?

A
$$F$$

B
$$O$$

C
$$N$$

D
$$Cl$$

Solution

Electron affinity of $$'F' $$ is the $$2nd $$ highest among periodic table after $$Cl$$.
Question 9
1 / -0

The spin only magnetic moment of $$[ZCl_{4}]^{2-}$$ is $$3.87\ BM$$ where $$Z$$ is:

A
$$Mn$$

B
$$Ni$$

C
$$Co$$

D
$$Cu$$

Solution

$$\mu=3.87=\sqrt{n(n+2)}\quad \Rightarrow n=3$$

$$[ZCl_{4}]^{2-}$$; oxidation state of $$Z$$ is $$+2$$

No. of unpaired electrons is $$3$$.

Hence, $$Z^{2+} = d^{7}$$

So, element is $$Co$$.
Question 10
1 / -0

What is the electronic configuration of neutral $$Mg$$ and $$Cl$$ ?

A
$$Mg ; [Ne]3s^2$$ ; $$Cl : [Ne]3s^2 3p^5$$

B
$$Mg ; [Ne]3s^1$$ ; $$Cl : [Ne]3s^2 3p^5$$

C
$$Mg ; [Ne]3s^2$$ ; $$Cl : [Ne]3s^2 3p^4$$

D
$$Mg ; [Ne]3s^2$$ ; $$Cl : [Ne]3s^2 3p^6$$

Solution

The electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals.
For example: $$ [Ne]=1{ s }^{ 2 }2{ s }^{ 3 }2{ p }^{ 6 } $$
Therefore, the electronic configuration of $$ Mg $$ = $$ [Ne]3{ s }^{ 2 } $$
The electronic configuration of $$ Cl $$ = $$ [Ne]3{ s }^{ 2 }3{ p }^{ 5 } $$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Classification of Elements and Periodicity in Properties Test - 45

Result

Classification of Elements and Periodicity in Properties Test - 45

Score

-

Rank

-

SHARING IS CARING

Question 1

$$Cr$$

$$Mn$$

$$Sc$$

$$Na$$

Solution

Question 2

$$O^{-2} > Ne > Mg^{2+} > Al^{3+}$$ (Size)

$$N^{3-} > O^{2-} < F^- < Na^+$$ (Nuclear charge)

$$Li > Be > B > C$$ (Electron gain enthalpy)

$$Li < Na > K > Cs $$ (IE)$$_1$$

Solution

Question 3

Rt

Ru

Rf

Rd

Solution

Question 4

117

116

115

114

Solution

Question 5

inert pair effect - $$Al > Ga > In$$

first ionization enthalpy - $$B > Al > Tl$$

strength as Lewis acid - $$B{ Cl }_{ 3 } > Al{ Cl }_{ 3 } > Ga{ Cl }_{ 3 }$$

oxidising property - $${ Al }^{ +3 } > { In }^{ +3 } > { Tl }^{ +3 }$$

Solution

Question 6

(a), (b) and (c)

(a), (c) and (d)

(b), (c) and (d)

(a), (b) and (d)

Solution

Question 7

half-filled stability of gp. $$15$$ elements

poor shielding in gp. $$15$$ elements

poor shielding in gp. $$16$$ elements

half-filled stability of gp. $$16$$ elements

Solution

Question 8

$$F$$

$$O$$

$$N$$

$$Cl$$

Solution

Question 9

$$Mn$$

$$Ni$$

$$Co$$

$$Cu$$

Solution

Question 10

$$Mg ; [Ne]3s^2$$ ; $$Cl : [Ne]3s^2 3p^5$$

$$Mg ; [Ne]3s^1$$ ; $$Cl : [Ne]3s^2 3p^5$$

$$Mg ; [Ne]3s^2$$ ; $$Cl : [Ne]3s^2 3p^4$$

$$Mg ; [Ne]3s^2$$ ; $$Cl : [Ne]3s^2 3p^6$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.