Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 49

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Weekly Quiz Competition

Question 1
1 / -0

Two elements $$X$$ and $$Y$$ contain only one electron in the outer level. Element $$X$$ is reactive and loses electron easily while element $$Y$$ is relatively unreactive and non-corrosive. The elements $$X$$ and $$Y$$ respectively are:

A
$$Cs$$ and $$Li$$

B
$$Rb$$ and $$Na$$

C
$$Li$$ and $$Cu$$

D
$$Ag$$ and $$Au$$

Solution

Alkali metals (such as $$Li$$) and coinage metals (such as $$Cu$$), have one valence electron each and belong to groups IA and IB respectively. Alkali metals are highly reactive while coinage metals are very less reactive.
Question 2
1 / -0

Who is father of the Periodic Table of Elements?

A
Johann Baeyer

B
Dmitri Mendeleev

C
Alfred Nobel

D
Johannes Van der Waals

Solution

Dmitri Mendeleev is known as father of periodic table of elements.
Question 3
1 / -0

$$A,\ B,\ C$$ are three elements with the atomic number $$Z-1, Z, Z+1$$ respectively. $$B$$ is an inert gas. Predict the group of $$A$$ and $$C$$.

A
Group 17 and group 1

B
Group 1 and group 17

C
Group 16 and group 17

D
Group 1 and group 2

Solution

$$A\quad B\quad C\longrightarrow$$ elements

$$(Z-1)\quad (Z)\quad (Z+1)\longrightarrow$$ atomic number
$$\downarrow$$
We know, inert gas
Group $$18$$ elements are Noble Gas elements which are inert in nature.
So, Group no. of $$A=17$$
$$B=18$$
$$C=1$$
Question 4
1 / -0

The correct oreder of electron affinity is :

A
$$F > Cl > O$$

B
$$F > O > Cl$$

C
$$Cl > F > O$$

D
$$O > F > Cl$$

Solution

$$Cl$$ tends to acquire a stable electronic configuration by gaining an $$e^-$$ in its' outermost shell.

$$Cl$$ has more $$e^-$$ affinity than $$F$$ because $$F$$ being small and high electronegative, repels the incoming $$e^-$$ and a lot of energy needed.

Therefore, it is difficult to accommodate and extra $$e^-$$ in the small size of $$F$$ whereas $$Cl$$ being bigger can accommodate the incoming $$e^-$$ very easily.

$$O$$ will have further less electron affinity to its' electronegativity than $$F$$ moreover by adding an $$e^-$$ to the outermost shell of $$F$$ it acquires fully filled stable state. Hence has more electron affinity than $$O$$.

Therefore, option C is correct.
Question 5
1 / -0

Element with similar chemical properties:

A
occur only within the same period

B
have identical atomic mass(weight)

C
have identical number of neutrons

D
have the same number of electrons in the outer shell

Solution

The elements of a group have similar chemical properties but in a period they have different chemical properties. For example, Sodium, potassium, lithium, rubidium, and caesium have similar chemical properties.

Therefore, Elements with similar chemical properties have (D) the same number of electrons in an outermost shell as the elements in the same group only have the same number of electrons in the outermost shell.

Hence, the correct option is $$\text{D}$$
Question 6
1 / -0

The amount of energy relased when $$10^o$$ atoms of iodine in vapour state are converted to $$I^-$$ ions is $$4.9\times 10^{-13}J$$. What is the electron affinity of iodine in eV per atom?

A
$$2.0$$

B
$$2.5$$

C
$$2.75$$

D
$$30.6$$

Solution

$$I+{e}^{-}\rightarrow {I}^{-} , E.A=4.9\times{10}^{-18} J .$$
$$\therefore E.A(eV)=(\cfrac {4.9\times{10}^{-18}}{1.602\times{10}^{-19}})=(\cfrac {4.9\times10}{1.6})=30.6 eV$$
Question 7
1 / -0

Which one of the following arrangement represents the correct order of electron gain enthalpy (with negative sign) of given atomic species?

A
$$F < Cl < O < S$$

B
$$S < O < Cl < F$$

C
$$O < S < F < Cl$$

D
$$Cl < F < S < O$$

Solution

In chlorine and fluorine. $$Cl$$ has high electron gain enthalpy because the small size of $$F$$ and there is very high electronic repulsion among the electrons of fluorine. This makes incoming of another electron not very favourable.
In sulphur and oxygen, sulphur has high electron gain enthalpy than oxygen because of larger size and lower electron density.
So, $$O<S<F<Cl$$
The $$Cl$$ has a most negative electron gain enthalpy and $$O$$ has a least negative electron gain enthalpy.
By considering the negative sign, the more negative value will be small and less negative value will be large.
Thus, the correct order will be $$Cl<F<S<O$$
Question 8
1 / -0

Ionization enthalpy of $$F = 320 kJ mol^{-1}$$. The electron gain enthalpy of flourine would be:

A
$$-320 kJ mol^{-1}$$

B
$$-160 kJ mol^{-1}$$

C
$$320 kJ mol^{-1}$$

D
$$160 kJ mol^{-1}$$

Solution

The electron gain enthalpy is $$=-320$$ $$kJ/mol^{-1}$$
Since, I.P and E.A are equal in magnitude but opposite direction.

Question 9

1 / -0

Match the column:-

(A)	$${ 1s }^{ 2 }{ 2s }^{ 2 }{ 2p }^{ 6 }{ 3s }^{ 2 }3p^{ 4 } $$	(P)	s-block , II A, 2nd period
(B)	$$[Rn]6d^27s^2$$	(Q)	d -block, II B, 4th period
(C)	$$ { 1s }^{ 2 }{ 2s }^{ 2 }{ 2p }^{ 6 }{ 3s }^{ 2 }{ 3p }^{ 6 }{ 3d }^{ 10 }{ 4s }^{ 2 }$$	(R)	f-block , III B, 7th period
(D)	$$1s^22s^2 $$	(S)	p-block VI A, 3rd period

$$ A-Q, B-P, C-S, D-R $$

$$A-R, B-P , C-S , D-Q $$

$$A-S, B-R, C-Q,D-P $$

None of the above

Question 10
1 / -0

The number of electrons having $$n + s = 2.5$$ in sulphide ion is:

A
$$3$$

B
$$4$$

C
$$6$$

D
$$2$$

Solution

Electronic configuration of sulphide ion.
$${ 1s }^{ 2 }{ 2s }^{ 2 }{ 3s}{ 2 }{ 3p }^{ 3 }$$
Given that $$n+s=2.5$$
$$n=2$$, $$s=0.5=\dfrac { 1 }{ 2 } $$
$$n=2$$ means $${ 2s }^{ 2 }$$.
So, Two electrons having $$n+s=2.5$$.

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Classification of Elements and Periodicity in Properties Test - 49

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Classification of Elements and Periodicity in Properties Test - 49

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SHARING IS CARING

Question 1

$$Cs$$ and $$Li$$

$$Rb$$ and $$Na$$

$$Li$$ and $$Cu$$

$$Ag$$ and $$Au$$

Solution

Question 2

Johann Baeyer

Dmitri Mendeleev

Alfred Nobel

Johannes Van der Waals

Solution

Question 3

Group 17 and group 1

Group 1 and group 17

Group 16 and group 17

Group 1 and group 2

Solution

Question 4

$$F > Cl > O$$

$$F > O > Cl$$

$$Cl > F > O$$

$$O > F > Cl$$

Solution

Question 5

occur only within the same period

have identical atomic mass(weight)

have identical number of neutrons

have the same number of electrons in the outer shell

Solution

Question 6

$$2.0$$

$$2.5$$

$$2.75$$

$$30.6$$

Solution

Question 7

$$F < Cl < O < S$$

$$S < O < Cl < F$$

$$O < S < F < Cl$$

$$Cl < F < S < O$$

Solution

Question 8

$$-320 kJ mol^{-1}$$

$$-160 kJ mol^{-1}$$

$$320 kJ mol^{-1}$$

$$160 kJ mol^{-1}$$

Solution

Question 9

$$ A-Q, B-P, C-S, D-R $$

$$A-R, B-P , C-S , D-Q $$

$$A-S, B-R, C-Q,D-P $$

None of the above

Question 10

$$3$$

$$4$$

$$6$$

$$2$$

Solution

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