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Classification of Elements and Periodicity in Properties Test - 57

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Classification of Elements and Periodicity in Properties Test - 57
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  • Question 1
    1 / -0
    Which configuration represents a noble gas
    Solution
    Coorect option is B. It has completely filled orbitals.
  • Question 2
    1 / -0
    Which of the following pair has elements containing same number of electrons in the outermost orbit
    Solution
    $$As$$ and $$Bi$$; both contains same number of electrons in outermost orbital since they belong to same group (i.e. $$group\ 15$$).
  • Question 3
    1 / -0
    The electronic configuration of an atom $$A$$ is $$1s^2 2s^2 2p^6 3s^2p^6 3d^{10} 4s^2 4p^3$$. The chemistry of $$A$$ is therefore likely to be similar to that of 
    Solution
    Nitrogen has similar electronic configuration since it has its valence electrons in $$2s^{2} 2p^{3}$$.
  • Question 4
    1 / -0
    Electron affinity is the 
    Solution
    Electron affinity is the energy released when an electron is added to an isolated atom in the gaseous state.
  • Question 5
    1 / -0
    In comparison with akali metals, the electron affinity of halogen is 
    Solution
    Electron affinity of halogen is very high because they can easily accept electrons inorder to have noble gas configuration.
  • Question 6
    1 / -0
    Nitrogen has lower electron affinity than its preceding element carbon because 
    Solution
    Since N has half-filled p-orbital which provides extra stability. So it has lower electron affinity than carbon.
  • Question 7
    1 / -0
    An element has the electronic configuration $$1s^22s^2 2p^6 3s^2 3p^6 3d^5 4s^1$$. It is a 
    Solution
    It belongs to d-block as d-orbital is not completley filled. The given electronic configuration belongs to Cr atom and it's a d-block element.
  • Question 8
    1 / -0
    The most important active step in the development of periodic table was taken by
    Solution
    The most important active step in the development of periodic table was taken by Mendeleev since though others have also made significant contributions towards classification of elements, he elevated the progress made in that direction much more than anyone else.
    Hence Correct option is $$A$$.
  • Question 9
    1 / -0
    Last element of group $$IV$$ is found to be
    Solution
    Down the group metallic character increases. Group IV shows variation from non-metallic character to weak metallic character as we move down the group.
  • Question 10
    1 / -0
    Which metal has $$2$$ electrons in the outermost orbit
    Solution
    Be has two electrons in outermost orbit. Electronic configuration of Be is $$1s^{2} 2s^{2}$$.
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