Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 60

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Weekly Quiz Competition

Question 1
1 / -0

Consider the following statements:

(A) Electron density in the $$xy-$$ plane in $$3d_{x^2−y^2}$$ orbital is zero.
(B) Electron density in the $$xy-$$ plane in $$3d_{z^2}$$ orbital is zero.
(C) $$2s-$$ orbital has one nodal surface.
(D) For $$2p_x-$$ orbital $$yz$$ is the nodal plane.

Which are the correct statements?

A
(C) and (D)

B
(B) , and (C)

C
Only (B)

D
All are correct

Solution

(A) Electron density in the $$xy-$$ plane in $$3d_{x^2−y^2}$$ orbital is non-zero.
(B) Electron density in the $$xy-$$ plane in $$3d_{z^2}$$ orbital is non-zero.
(C) $$2s-$$ orbital has one nodal surface.
(D) For $$2p_x-$$ orbital $$yz$$ is the nodal plane.

Option C and D are correct.
Question 2
1 / -0

The electronic configuration of four elements are :
I. $$[Kr]5s^1$$
II.$$[Rn]5f^{14}6d^{1}7s^2 $$
III.$$[Ar]3d^{10}4s^24p^5$$
IV.$$[Ar]3d^64s^2$$.
Consider the following statements :
I show variable oxidation state
II is a d-block element
The compound formed between I and Ill is covalent
IV shows a single oxidation state
Which statement is True (T) or False (F)?

A
FTFF

B
FTFT

C
FFTF

D
FFFF

Solution

(I) $$[Kr]5s^1$$, shows only single oxidation state +1
(II)$$[Rn]5f^{14}6d^{1}7s^2 $$, it is f-block element ($$Z = 103$$)
(III)The compound formed between I and Ill is ionic.
(IV)$$[Ar]3d^64s^2$$, ($$Z = 26$$) Fe shows variable oxidation state.

thus, D is the correct answer.
Question 3
1 / -0

Which one of the following statements is incorrect?

A
Greater is the nuclear charge, greater is the electron gain enthalpy

B
Nitrogen has almost zero electron gain enthalpy

C
Electron gain enthalpy decreases from fluorine to iodine in the group

D
Chlorine has the highest electron gain enthalpy

Solution

The order of electron gain enthalpy is $$Cl > F > Br > I$$
The electron gain enthalpy of fluorine is less than chlorine because of
1) small $$2p$$ subshell in fluorine
2) The interelectronic repulsion between electrons of fluorine in $$2p$$ subshell
Question 4
1 / -0

Electronic configuration of $$Al^{3+}$$ is

A
$$2, 8, 3$$

B
$$2, 8, 8$$

C
$$2, 8$$

D
$$2, 8, 8, 3$$

Solution

The arrangement of electrons in different energy levels around a nucleus is called electronic configuration. The periodicity in properties of elements in any group is due to repetition in the same valence shell electronic configuration after a certain gap of atomic numbers such as 2, 8, 8, 18, 18, 32.

The atomic number of Al is 13 and its electronic configuration is 2,8,3. So, the electronic configuration of Al$$^{3+}$$ is 2,8.
Question 5
1 / -0

The element with electronic configuration (Ar) $$ 3d^{2} 4s^{2} $$ belongs to which block ?

A
s - block

B
p - block

C
d - block

D
f- block

Solution

The element with electronic configuration $$(Ar) \;3d^24s^2$$ is $$Titanium$$, which belongs to $$d-block$$
hence option (C) is correct.
Question 6
1 / -0

The outermost electron configuration of an element in this is $$2s^2\ 2p^6$$. This represents:

A
Excited state

B
Ground state

C
Anion form

D
Cationic form
Question 7
1 / -0

The atom of which of the following elements forms dual closed shell configuration by receiving one electron?

A
$$He$$

B
$$H$$

C
$$Li$$

D
$$B$$

Solution

Hydrogen has one electron in its valence shell. It gains one electron and forms a dual closed shell configuration like helium.
Question 8
1 / -0

Which of the following will not have $$18$$ electrons?

A
$$K^+$$

B
$$Cl^-$$

C
$$K$$

D
$$Ca^{2+}$$

Solution

Atomic number of $$K$$ is $$19$$. Thus, it has $$19$$ electrons.
Question 9
1 / -0

How many electron are there in chloride ion?

A
$$17$$

B
$$18$$

C
$$16$$

D
$$8$$

Solution

Chloride ion $$(Cl^{-})$$ is formed when chlorine atom $$(17)$$ gains one electron. It thus has $$18$$ electrons.
Question 10
1 / -0

Which of the following statements is not correct for the element having electronic structure $$2,8,8,2$$?

A
Its valency is $$2$$

B
It is in fourth period

C
It is in group $$II$$

D
Its atom forms negative ion

Solution

The element having electronic configuration as $$2,8,8,2$$ has valency of $$2$$. It has tendency of losing two electrons and thus, it forms a positive ion.

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Re-Attempt Weekly Quiz Competition

Classification of Elements and Periodicity in Properties Test - 60

Result

Classification of Elements and Periodicity in Properties Test - 60

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Rank

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SHARING IS CARING

Question 1

(C) and (D)

(B) , and (C)

Only (B)

All are correct

Solution

Question 2

FTFF

FTFT

FFTF

FFFF

Solution

Question 3

Greater is the nuclear charge, greater is the electron gain enthalpy

Nitrogen has almost zero electron gain enthalpy

Electron gain enthalpy decreases from fluorine to iodine in the group

Chlorine has the highest electron gain enthalpy

Solution

Question 4

$$2, 8, 3$$

$$2, 8, 8$$

$$2, 8$$

$$2, 8, 8, 3$$

Solution

Question 5

s - block

p - block

d - block

f- block

Solution

Question 6

Excited state

Ground state

Anion form

Cationic form

Question 7

$$He$$

$$H$$

$$Li$$

$$B$$

Solution

Question 8

$$K^+$$

$$Cl^-$$

$$K$$

$$Ca^{2+}$$

Solution

Question 9

$$17$$

$$18$$

$$16$$

$$8$$

Solution

Question 10

Its valency is $$2$$

It is in fourth period

It is in group $$II$$

Its atom forms negative ion

Solution

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