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States of Matter Test - 29

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States of Matter Test - 29
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  • Question 1
    1 / -0
    The correct expression of partial pressure in terms of mole fraction is :
    Solution
    If $$x_{1}$$ and $$x_{2}$$ are mole fractions of two gases.
    Their partial pressures are $$p_{1} = x_{1} P_{total}, p_{2} = x_{2} P_{total}$$.
  • Question 2
    1 / -0
    The pressure of a $$1 : 4$$ mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?
    Solution

    Correct Option: Option C

    Hint: $$P_{partial} \propto n_{gas}$$

    Explanation

    Step 1: Preparing data

    • We know that, $$P_{partial} = \chi_{gas} \times P_{total}$$ where, …$$(1)$$
      $$P_{partial}=$$ Partial pressure of gas
      $$\chi_{gas}=$$ mole fraction of gas
      $$P_{total}=$$ Total pressure of mixture of gases
    • Also, $$\chi_{n_{1}} = \dfrac{n_{1}}{n_{1} + n_{2} + n_{3} + n_{n}}$$  …$$(2)$$
      where, $$\chi_{n_{1}} =$$ Mole fraction of gas $$1$$
      $$n_{1} , n_{2} , n_{3}$$ and $$n_{n}= $$ Moles of all gases in mixture
    • Given, $$P_{total} = 1$$ atm.
      And, $$\dfrac{n_{H_2}}{n_{O_2}} = \dfrac{1}{4}$$

    Step 2: Solving using equations

    • $$n_{H_2} = x$$ and $$n_{O_2} = 4x$$
    • Therefore, $$Moles_{(total)} = 5x$$
    • Thus, $$\chi_{H_2} = \dfrac{1}{5}$$ and $$\chi_{O_2} = \dfrac{4}{5}$$
    • Putting above values in equation $$(1)$$, we get:
      $$P_{partial} ({O_2}) = \dfrac{4}{5} \times 1$$ atm
    • Now, $$1$$ $$atm \approx 10^5$$ $$N/m^2$$
    • Therefore, $$P_{partial} ({O_2}) = \dfrac{4}{5} \times 1 \times 10^5$$ $$N/m^2$$

    Hence, $$ P_{O_{2}} = 8 \times 10^4$$ is the partial pressure of dioxygen.

  • Question 3
    1 / -0
    Dipole-dipole forces act between the molecules possessing permanent dipole. Ends of dipoles possess 'partial charges'. The partial charge is:
    Solution
    Partial charges are always less than the unit electronic charge $$(1.6\times 10^{-19}C)$$.
  • Question 4
    1 / -0
    According to kinetic theory of gases, the collisions between molecules of a gas:
    Solution
    Particles of a gas collide in a straight line in all possible directions.
  • Question 5
    1 / -0
    The kinetic theory of matter helped a great deal in understanding the behaviour of gases. Which of the following statements did not belong to it?
    Solution
     When molecules collide, they lose energy.
    The kinetic theory states that, no energy is gained or lost when molecules collide.
    Hence, statement D does not belongs to the kinetic theory of gas.
  • Question 6
    1 / -0
    Which scientist discovered that the same amount of space was occupied by equal numbers of molecules of gases, irrespective of whether it was hydrogen or chlorine or fluorine?
    Solution
    Avogadro first discovered it.
    It states that $$1$$ $$mole$$ of any element or compound have $$6.022\times 10^{23}$$ atoms or molecules present at any constant temperature and pressure.
  • Question 7
    1 / -0
    Which of the following assumptions is incorrect according to kinetic theory of gases?
    Solution
    Gases are made up of a large number of particles. They travel in a straight line until there take places a collision between them and an object  (eg: wall of the container). They don't have any force of attraction with walls of the container. The average kinetic energy depends on the temperature of the gas.
  • Question 8
    1 / -0
    Which of the following is correct?
    Solution
    Answer:- (A) van der waals radius of chlorine is bigger than nitrogen
    Van der waals radius of chlorine = 175 pm
    Van der waals radius of nitrogen =  155 pm
    Hence A is correct answer.
  • Question 9
    1 / -0
    Equal masses of helium and oxygen are mixed in a container at $$25^{\circ}C$$. The fraction of the total pressure exerted by oxygen in the mixture of gases is :
    Solution
    Mole fraction of $$O_{2} = \dfrac {\dfrac {w}{32}}{\dfrac {w}{32} + \dfrac {w}{4}} = \dfrac {w}{32}\times \dfrac {32}{9w} = \dfrac {1}{9}$$
    Partial pressure of oxygen $$= P \times x_{O_{2}}$$
    $$= P_{total}\times \dfrac {1}{9}$$ or $$\dfrac {1}{9}P_{total}$$.
  • Question 10
    1 / -0
    As the temperature increases, average kinetic energy of molecules increases. What would be the effect of increase of temperature on pressure provided the volume is constant?
    Solution
    Gay Lussac's law states that at constant volume, pressure of a fixed amount of a gas varies directly with the temperature.
     
        $$\therefore P\propto T$$ (at constant volume)

    Thus, if temperature is increased at constant volume pressure increases.
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