States of Matter Test

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States of Matter Test - 47

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Weekly Quiz Competition

Question 1
1 / -0

At $$250^{o}C$$ and $$1$$ atmosphere pressure, the vapour density of $$PCI_{5}$$ is $$57.9$$ . What will be the dissociation of $$PCI_{5}-$$

A
$$1.00$$

B
$$0.90$$

C
$$0.80$$

D
$$0.65$$

Solution
Question 2
1 / -0

If there unreactive gases having partial pressure $${P_A},{P_B}$$ and $${P_C}$$ and there moles are $$1,\,2$$ and $$3$$ respectively then their total pressure will be :

A
$$P = {P_A} + {P_B} + {P_C}$$

B
$$P = \cfrac{{{P_A} + {P_B} + {P_C}}}{6}$$

C
$$P = \cfrac{{\sqrt {{P_A} + {P_B} + {P_C}} }}{3}$$

D
None of these

Solution

According to Dalton's law of partial pressure,

Total pressure = sum of partial pressures of individual gases

$$P_{total} = P_a + P_b + P_c$$

Therefore, option A is correct.
Question 3
1 / -0

A solution $$X$$ of $$A$$ and $$B$$ contains $$30$$ mole $$\%$$ of $$A$$ & is in equilibrium with its vapour that contains $$40$$ mole $$\%$$ of $$B$$. The ratio of $$V.P$$ of pure, $$A$$ and $$B$$ will be?

A
$$2:7$$

B
$$7:2$$

C
$$3:4$$

D
$$4:3$$
Question 4
1 / -0

The vapour pressure of water at $$20^0C$$ is 17.54 mm. When 20 g of non-ionic, substance is dissolved in 100 g of water, the vapour pressure is lowered by 0.30 mm.What is the molecular weight of the substances.

A
210.2

B
208.16

C
215.2

D
200.8

Solution
Question 5
1 / -0

Consider the following statements
a. Kinetic energy of a molecule is zero at $$0^0C$$.
b. A gas in a closed container will exert much higher pressure due to gravity at the bottom than at the top
c. Between collisions, the molecules move in straight lines with constant velocities.
Choose the incorrect statement(s)

A
a, b & c

B
a & b

C
b & c

D
a & c
Question 6
1 / -0

One gram molecule of any gas at $$NTP$$ occupies $$22.4\ L$$. This fact was derived from:

A
Dalton's theory

B
Avogardro's hypothesis

C
Berzelius hypothesis

D
Law of gaseous volume

Solution

According to Avogadro's law, 1 mole of every gas occupies 22.4L at $$NTP$$.
From ideal gas equation,
$$PV=nRT$$. . . . . . .(1)
At $$NTP$$,
$$T=273K$$
$$P=1atm$$
$$n=1$$
$$R=0.0821atm L/K mol$$
from equation (1),
$$V=\dfrac{nRT}{P}$$
$$V=\dfrac{1\times 0.0821\times 273}{1}=22.4L$$
The correct option is B.
Question 7
1 / -0

Which of the following sets of variables give a staright line with negative slope when plotted ?
( P = Vapour pressure ; T = Temperature in K)
y- axis x -axis y -axis x-axis

A
$$ P\quad \quad \quad T $$

B
$$ log_{10}P\quad \quad \quad T $$

C
$$ log_{10}P\quad \quad \quad \frac{1}{T} $$

D
$$ log_{10}P \quad \quad \quad log_{10} \frac{1}{T} $$

Solution
Question 8
1 / -0

The sample of neon gas heated from 300 K to 390 K, percentage increases in K.E is:

A
$$10\%$$

B
$$20\%$$

C
$$30\%$$

D
$$40\%$$

Solution

Kinetic energy of gas is given by $$K.E = \dfrac{3}{2}nRT$$

therefore, kinetic energy is directly proportional to temperature.
so, if we find out percentage change in temperature , we can get percentage change in kinetic energy .

percentage change in temperature $$=\dfrac{\Delta T } {T}$$

$$= \dfrac{390 - 300}{90} \times 100$$
$$= \dfrac{90}{300}\times 100$$
$$= 30$$ %

hence, percentage change in kinetic energy of neon gas is 30%
Question 9
1 / -0

Equal amounts of two gases of molecular mass 4 and 40 are mixed. the pressure of the mixture is 1.1 atm. The partial pressure of the light gas in this mixture is :

A
0.55 atm

B
0.11 atm,

C
1 atm

D
o.12 atm

Solution

Assume 40 g each of two gases is present.

The number of moles of lighter gas are $$\displaystyle \frac {40}{4} = 10 $$.

The number of moles of heavier gas are $$\displaystyle \frac {40}{40} = 1 $$.

The mole fraction of the lighter gas is $$\displaystyle \frac {10}{10+1} = 0.9090 $$.

The partial pressure of the lighter gas is $$\displaystyle 0.9090 \times 1.1 = 1 \: atm $$.
Question 10
1 / -0

Mole fraction of A vapours above the solution in mixture of A and B ($$X_A=0.4$$)will be
[Given : $${ P }_{ A }^{ 0 }=100mmHg\quad and\quad { P }_{ B }^{ 0 }=200mmHg$$]

A
0.4

B
0.8

C
0.25

D
none of these

Solution

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States of Matter Test - 47

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States of Matter Test - 47

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Question 1

$$1.00$$

$$0.90$$

$$0.80$$

$$0.65$$

Solution

Question 2

$$P = {P_A} + {P_B} + {P_C}$$

$$P = \cfrac{{{P_A} + {P_B} + {P_C}}}{6}$$

$$P = \cfrac{{\sqrt {{P_A} + {P_B} + {P_C}} }}{3}$$

None of these

Solution

Question 3

$$2:7$$

$$7:2$$

$$3:4$$

$$4:3$$

Question 4

210.2

208.16

215.2

200.8

Solution

Question 5

a, b & c

a & b

b & c

a & c

Question 6

Dalton's theory

Avogardro's hypothesis

Berzelius hypothesis

Law of gaseous volume

Solution

Question 7

$$ P\quad \quad \quad T $$

$$ log_{10}P\quad \quad \quad T $$

$$ log_{10}P\quad \quad \quad \frac{1}{T} $$

$$ log_{10}P \quad \quad \quad log_{10} \frac{1}{T} $$

Solution

Question 8

$$10\%$$

$$20\%$$

$$30\%$$

$$40\%$$

Solution

Question 9

0.55 atm

0.11 atm,

1 atm

o.12 atm

Solution

Question 10

0.4

0.8

0.25

none of these

Solution

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