Thermodynamics ...

For the reaction, $$X_{2}O_{4}(l) \rightarrow 2XO_{2}(g)\ \triangle U = 2.1\ k\ cal, \triangle S = 20\ cal K^{-1}$$ at $$300\ K$$. Hence, $$\triangle G$$ is:

For the reaction at $$25, X_{ 2 }O_{ 4 } { O }_{ 4_{ (l) } } \longrightarrow 2X { O }_{ 2_{ (g) } }$$.
$$\Delta H =$$2.1 kcal and $$\Delta S =$$20 cal $${ K }^{ -1 }$$. The reaction would be:

Consider the following processes :-
$$ \delta H (kJ/mol)$$
$$\frac{1}{2} A \rightarrow B + 150$$
$$ 3B + 2C + D - 125$$
$$E + A \rightarrow 2D + 350$$
For $$B + D \rightarrow E + 2C$$ $$\Delta$$$$H$$ will be:

Consider the following process
$$\Delta H(kJ/mol)$$
$$\frac{1}{2}A\rightarrow B +50$$
$$3B \rightarrow 3C +D -125$$
$$E + A \rightarrow 2D + 350$$
For $$B + D \rightarrow E +2C, \Delta H $$will be:

For the reaction given below the values of standard Gibbs free energy of formation at 298 K are given.
What is the nature of the reaction?
$$I_2 + H_2S \rightarrow 2HI + S$$
$$\Delta G_f^0 (HI) = 1.8 \ kJ\ mol^{-1}$$, $$\Delta G_f^0 (H_2S) = 33.8 \ kJ\ mol^{-1}$$

$${ NH }_{ 2 }{ CN }_{ \left( s \right)  }+\dfrac { 3 }{ 2 } { O }_{ 2\left( g \right)  }\rightarrow { N }_{ 2\left( g \right)  }+{ CO }_{ 2\left( g \right)  }+{ H }_{ 2 }{ O }_{ \left( l \right)  }$$
This reaction is carried out in a bomb calorie-meter. The heat released was $$743\ KJ\ { mol }^{ -1 }$$. The value of $${ \Delta H }_{ 300 }$$ for this reaction would be:

For the combustion of $$CH_4$$ at 1 atm pressure & 300 K, which of the following options is correct?

For a given reaction, $$\Delta H = 35.5 kJ mol^{-1}$$ and $$\Delta S = 83.6 kJ mol^{-1}$$. The reaction is spontaneous at: (Assume that $$\Delta H $$ and $$\Delta S$$ do not vary with temperature)

C (diamond) $$\rightarrow$$ C (graphite)
$$\triangle S_{300K} = 10 cal K^{-1}$$
C (diamond) + $$O_{2}$$ $$\rightarrow$$ $$CO_{2}$$
$$\triangle$$ H = -91 cal $$mol^{-1}$$ at 300 K
C (graphite) + $$O_{2}$$ $$\rightarrow$$ $$CO_{2}$$
$$\triangle$$ H = X at 300 K
X is:

Which thermochemical law is represented by the following figure?