Equilibrium Test

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Equilibrium Test - 15

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Weekly Quiz Competition

Question 1
1 / -0

For a system in equilibrium, $$\Delta G = 0$$ under conditions of constant:

A
temperature and pressure.

B
temperature and volume.

C
energy and volume.

D
pressure and volume.

Solution

When a system is at equilibrium under constant temperature and pressure, its free energy change is zero $$(\Delta G=0)$$.
Question 2
1 / -0

The degree of dissociation of an electrolyte does not depend on:

A
nature of electrolyte

B
catalytic action

C
dilution

D
temperature

Solution

Catalytic action has no effect on degree of dissoliation as catalyst only increases the speed of the reaction and does not change equilibrium concentration.
Hence, option B is correct.
Question 3
1 / -0

In the reaction $$N_{2} + 3H_{2} \Leftrightarrow 2NH_{3} + 21.8\ Kcal$$, the increase in pressure will result in:

A
an increase in the rate of forward reaction

B
an increase in the rate of backward reaction

C
no change in the reaction

D
an increase in the volume

Solution

In the reaction $$N_{2}(g) + 3H_{2}(g)\Leftrightarrow 2NH_{3}(g)$$, the number of moles decreases in the forward reaction from 4 to 2 . Also the number of moles increases in the reverse reaction form 2 to 4.

When the pressure is increased, the forward reaction will be favoured as the forward reaction occurs with decrease in the number of moles.

Thus, the position of the equilibrium will shift towards the products.

Thus, when pressure is increased the rate of the forward reaction is increased.

Option A is correct.
Question 4
1 / -0

When a catalyst is introduced into a reversible reaction;

A
Forward reaction rate increases

B
Backward reaction rate increases

C
Equilibrium is not changed

D
Attains equilibrium quickly

Solution
Question 5
1 / -0

100ml of a buffer of $$1M NH_3(aq)\: and\: {1M NH_{4}}^{+}(aq)$$ are placed in two half cells separately. A current of 1.5amp is passed through both half cells for 20min, if electrolysis of only water take place. The pH of :

A
Anode half cell will decrease

B
Cathode half cell will decrease

C
Both half cell will decrease

D
Both half cell remain same

Solution

As only the electrolysis of water take place so the conc. of $$H^+$$ ion in Anode compartment increases
Question 6
1 / -0

The pH value of blood does not appreciably change by a small addition of an acid or a base, because the blood

A
is a body fluid

B
can be easily coagulated

C
contains iron as a part of the molecule

D
contains serum protein which acts as buffer

Solution

The buffer system present in serum is $$H_{2}CO_{3}+NaHCO_{3}$$ and as we know that a buffer solution resist the change in pH therefore pH value of blood does not change by a small addition of an acid or a base.
Question 7
1 / -0

For the equilibrium reaction, $$H_{2}O(l) \rightleftharpoons H_{2}O(g),$$ what happens, if pressure is applied :

A
More water evaporates

B
The boiling point of water is increased

C
No effect on boiling point

D
None of the above

Solution

The equilibrium reaction is $$H_{2}O(l) \rightleftharpoons H_{2}O(g),$$ when pressure is applied, the equilibrium will shift to left as the value of $$\Delta n$$ is positive. Hence, for boiling to occur more temperature is required. So, it will increase the boiling point.
Question 8
1 / -0

Reaction $$BaO_{2}(s)\rightleftharpoons BaO(s)+O_{2}(g)$$ ; H = + ve. In equilibrium condition. Pressure of O$$_{2}$$ is depend on:

A
increase mass of BaO$$_{2}$$

B
increase mass of BaO

C
increase temperature on equilibrium

D
increase mass of BaO$$_{2}$$ and BaO both

Solution

The given reaction is:-
$${ BaO }_{ 2 }\left( s \right) \rightleftharpoons BaO\left( s \right) +{ O }_{ 2 }\left( g \right) \quad ;\quad H=+ive$$
Since $$H$$ is $$+ive$$ for this reaction. So, it is endothermic in nature. On increasing the temperature, by applying Le Chatelier's principle, we can see that the reaction proceeds in a forward direction on increasing temperature. So, the pressure of $${ O }_{ 2 }$$ will increase on increasing the temperature at equilibrium.
Question 9
1 / -0

What is the $$[OH^-]$$ in the final solution prepared by mixing $$20.0\ mL$$ of $$0.050\ M$$ $$HCl$$ with $$30.0\; mL$$ of $$0.10 \;M\; Ba(OH)_2$$?

A
$$0.12\ M$$

B
$$0.10\ M$$

C
$$0.40\ M$$

D
$$0.0050\ M$$

Solution

$$Ba(OH)_2 + 2HCl \rightarrow BaCl_2 + 2H_2O$$

2 m mol of HCl neutralize 1 m mole of $$Ba(OH)_2$$

1 m mol of HCl neutralize 0.5 m mol of $$Ba(OH)_2$$

$$Ba(OH)_2$$ left = 3 - 0.5 m mol = 2.5 m mol

$$[Ba(OH)_2] = \frac{2.5}{50}\;M = 0.05\; M$$

or $$[OH]^- = 2 \times 0.05 = 0.1\; M$$
Question 10
1 / -0

The rate of the reaction $$2NO+Cl_2\rightarrow 2NOCl$$ is given by the rate equation. rate = $$k[NO]^2[Cl_2]$$
The value of the rate constant can be increased by:

A
increasing the concentration of NO.

B
increasing the concentration of the $$Cl_2$$

C
increasing the temperature

D
doing all of these

Solution

Rate constant is only affected by the temperature, it does not get affected by the increase in concentration of $$NO$$ and $$C{ l }_{ 2 }$$ .Hence the answer is increasing the temperature

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Equilibrium Test - 15

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Equilibrium Test - 15

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SHARING IS CARING

Question 1

temperature and pressure.

temperature and volume.

energy and volume.

pressure and volume.

Solution

Question 2

nature of electrolyte

catalytic action

dilution

temperature

Solution

Question 3

an increase in the rate of forward reaction

an increase in the rate of backward reaction

no change in the reaction

an increase in the volume

Solution

Question 4

Forward reaction rate increases

Backward reaction rate increases

Equilibrium is not changed

Attains equilibrium quickly

Solution

Question 5

Anode half cell will decrease

Cathode half cell will decrease

Both half cell will decrease

Both half cell remain same

Solution

Question 6

is a body fluid

can be easily coagulated

contains iron as a part of the molecule

contains serum protein which acts as buffer

Solution

Question 7

More water evaporates

The boiling point of water is increased

No effect on boiling point

None of the above

Solution

Question 8

increase mass of BaO$$_{2}$$

increase mass of BaO

increase temperature on equilibrium

increase mass of BaO$$_{2}$$ and BaO both

Solution

Question 9

$$0.12\ M$$

$$0.10\ M$$

$$0.40\ M$$

$$0.0050\ M$$

Solution

Question 10

increasing the concentration of NO.

increasing the concentration of the $$Cl_2$$

increasing the temperature

doing all of these

Solution

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