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Equilibrium Test - 68

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Equilibrium Test - 68
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  • Question 1
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    The dissociation constant of an acid HA is $$1 \times 10 ^ { - 5 }$$. The pH of 0.1 molar solution of the acid will be approximately:
    Solution

  • Question 2
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    The percentage of pyridine $$\left( { C }_{ 5 }{ H }_{ 5 }N \right) $$ that forms pyridinium ion $$\left( { C }_{ 5 }{ H }_{ 5 }{ N }^{ + }H \right) $$ in a 0.10 m aqueous pyridine solution $$\left( K_{ b } \ for\ { C }_{ 5 }{ H }_{ 5 }N=1.7\times { 10 }^{ -9 } \right) $$ is:
  • Question 3
    1 / -0
    Densities of diamond and graphite are 3.5 and 2.3 gm/mL 

        $$C(diamond)\rightleftharpoons C(graphite);{ \triangle  }_{ r }H=-1.9KJ/mol$$

    Favourable condtitions for the formation of graphite are :
    Solution

  • Question 4
    1 / -0
    In the reaction, $$2SO_{ 2 }(g)\rightleftharpoons 2SO +O_2$$, an inert gas introduced at constant temperature and volume. The dissociation of $$SO$$ is:
  • Question 5
    1 / -0
    A weak acid react with strong base, ionisation constant of weak acid is $${ 10 }^{ -4 }$$. Find out equilibrium constant for this reaction. 
    Solution

  • Question 6
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    For the reaction: $$ \cfrac {1}{2} N_{2(g)} + \cfrac {1}{2} O_{2(g)}  \leftrightharpoons NO_{2(g)} $$
    If pressure is increased by reducing the volume of the container, then:
    Solution

  • Question 7
    1 / -0
    At $$25^oC,$$ $$K_b$$ for $$BOH=1.0\times10^{-12}.$$  The concentration of hydroxyl ions in 0.01 M aqueous solution of the base would be:
  • Question 8
    1 / -0
    Consider the following equilibrium.
    Liquid $$\rightleftharpoons$$ Vapour
    Which of the following relation is correct?
  • Question 9
    1 / -0
    In the reaction: $$CO\left( g \right) +{ H }_{ 2 }O\left( g \right) \leftrightharpoons { CO }_{ 2 }\left( g \right) +{ H }_{ 2 }\left( g \right) +x\ kJ$$, the equilibrium will shift in the forward direction if:
  • Question 10
    1 / -0
    The self ionisation constant of $$\mathrm { NH } _ { 3 }$$ at $$50 ^ { \circ } \mathrm { C }$$  is given by $$\mathrm { K } _ { \mathrm { NH } _ { 3 } } = \left[ \mathrm { NH } _ { 4 } ^ { + } \right] \left[ \mathrm { NH } _ { 2 } ^ { - } \right] = 10 ^ { - 30 }$$. How many $$N H _ { 2 } ^ { - }$$ ions are present per $$\mathrm { cm } ^ { 3 }$$ of pure liquid $$\mathrm { NH } _ { 3 }$$?
    Solution

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