Redox Reactions Test

Result

Redox Reactions Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

\(H_2O_2\) reduces \(MnO_4^-\) ion to

A
\(Mn^+\)

B
\(Mn^{2+}\)

C
\(Mn^{3+}\)

D
\(Mn^-\)

Solution

\(2MnO^\ominus_4+5H_2O_2 +6H^+\) \(\to\,Mn^{2+} +5O_2+8H_2O\)
Question 2
1 / -0

When a sulphur atom becomes a sulphide ion

A
There is no change in the composition of atom

B
It gains two electrons

C
The mass number changes

D
None of these

Solution

\(S +2e^-\to S^{2-}\)
Question 3
1 / -0

When P reacts with caustic soda, the products are \( PH_3\) and \(NaH_2PO_2\). This reaction is an example of

A
Oxidation

B
Reduction

C
Oxidation and reduction (Redox)

D
Neutralization

Solution

\(\overset{o}{P_4} + 3NaOH + 3H_2O\to \underset{Sodium\,hypophosphite}{3NaH_2PO_2} + \overset{-3}{P}{H_3} \)

It shows oxidation and reduction (Redox) properties.
Question 4
1 / -0

In the course of a chemical reaction an oxidant

A
Loses electrons

B
Gains electrons

C
Both loses and gains electron

D
Electron change takes place

Solution

Any substance which is capable of oxidizing other substances and is capable of accepting/gaining electron during oxidation is called oxidizing agent or oxidant.
Question 5
1 / -0

When sodium metal is dissolved in liquid ammonia, blue colour solution is formed. The blue colour is due to

A
Solvated \(Na^+\)ions

B
Solvated electrons

C
Solvated \(NH^{-2}\)ions

D
Solvated protons

Solution

When sodium metal is dissolved in liquid ammonia to form coloured solution. Dilute solutions are bright blue in colour due to the presence of solvated electrons.

\(Na+(x+y)NH_3\to[Na(NH_3)_x]^+\)\(+\underset{Blue\,colour}{[e(NH_3)y]^-}\)
Question 6
1 / -0

Oxidation involves

A
Loss of electrons

B
Gain of electrons

C
Increase in the valency of negative part

D
Decrease in the valency of positive part

Solution

It is the process in which electrons are lost (de-electronation).
Question 7
1 / -0

One gas bleaches the colour of flowers by reduction while the other by oxidation

A
\(CO\,and\,Cl_2 \)

B
\(SO_2\,and\,Cl_2\)

C
\(H_2S\,and\,Br_2 \)

D
\(NH_3\,and\,SO_2\)

Solution

\(SO_2\) bleaches by reduction while chlorine bleaches colour of flowers by oxidation.
Question 8
1 / -0

When iron or zinc is added to \(CuSO_4\) solution, copper is precipitated. It is due to

A
Oxidation of \(Cu^{+2}\)

B
Reduction of \( cu^{+2}\)

C
Hydrolysis of \(CuSO_4 \)

D
Ionization of \(CuSO_4\)

Solution

\(\overset{o}{Zn}\,+\,\overset{+2}{CuSO_4} \) \(\to\,ZnSO_4\,+\,\overset{o}{Cu} \)

In this reaction \(Cu^{2+}\) change in \(Cu^0\), hence it is called as reduction reaction.
Question 9
1 / -0

In which of the following acid, which acid has oxidation reduction and complex formation properties

A
\(HNO_3\)

B
\(H_2SO_4\)

C
\(HCl\)

D
\(HNO_2\)

Solution

\(HNO_2\) shows both oxidation and reduction properties.
Question 10
1 / -0

The compound which could not act both as oxidising as well as reducing agent is

A
\(SO_2\)

B
\(MnO_2\)

C
\(Al_2O_3\)

D
\(CrO\)

Solution

\(Al_2O_3\) could not act as a oxidizing and reducing agent.
Question 11
1 / -0

For \(H_3PO_3 \) and \(H_3PO_4\) the correct choice is

A
\(H_3PO_3 \) is dibasic and reducing

B
\(H_3PO_3\) is dibasic and non-reducing

C
\(H_3PO_4\) is tribasic and reducing

D
\(H_3PO_3\) is tribasic and non-reducing

Solution

\(H\,-O\,-\overset{\overset{H}{|}}{P}\underset{\underset{O}{\downarrow}}\,-\,OH \)

Hence it is dibasic. It acts as reducing agent also.
Question 12
1 / -0

One mole of \(N_2H_4\) loses 10 mol of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of \(N_2\,in\,Y\) (There is no change in the oxidation state of hydrogen)

A
+3

B
-3

C
-1

D
+5

Solution

\(N_2^{2-}\to2Na^+\,+\,10e^-\)

\(2a\,-[2\times(-2)]\) = 10

a = +3
Question 13
1 / -0

\(HNO_2\) acts both as reductant and oxidant, while \(HNO_3\) acts only as oxidant. It is due to their

A
Solubility ability

B
Maximum oxidation number

C
Minimum oxidation number

D
Minimum number of valence electrons

Solution

In \(HNO_2\) oxidation number of N = + 3

In \(HNO_3\) oxidation number of N = + 5.
Question 14
1 / -0

Chlorine is in +1 oxidation state in

A
\(HCl\)

B
\(HClO_4\)

C
\(ICl\)

D
\(Cl_2O\)

Solution

In case of \(Cl_2O\) chlorine shows +1 oxidation state.
Question 15
1 / -0

The oxidation number of chlorine in HOCl

A
-1

B
0

C
+1

D
+2

Solution

In hypochlorous acid chlorine atom has + 1 oxidation number.
Question 16
1 / -0

Oxidation state of elemental carbon is

A
0

B
1

C
2

D
3

Solution

Every element always shows zero oxidation state.
Question 17
1 / -0

Oxidation number of C in \(C_6H_{12}O_6\) is

A
+ 6

B
- 6

C
0

D
+4

Solution

C has oxidation number = 0.
Question 18
1 / -0

Oxidation state of oxygen in hydrogen peroxide is

A
-1

B
+1

C
0

D
-2

Solution

In all peroxide oxygen shows - 1 oxidation state.
Question 19
1 / -0

Oxidation number of osmium (Os) in \(OsO_4 \) is

A
+4

B
+6

C
+7

D
+8

Solution

\(\overset{\ast}{O}sO_4\)

x+ 4(-2) = 0

x - 8 = 0

x = +8
Question 20
1 / -0

Which one of the following nitrates will leave behind a metal on strong heating

A
Ferric nitrate

B
Copper nitrate

C
Manganese nitrate

D
Silver nitrate

Solution

\(2AgNO_3\,\overset{\Delta}{\to}\,2Ag+2NO_2 + O_2\)

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Redox Reactions Test - 10

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Redox Reactions Test - 10

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Question 1

\(Mn^+\)

\(Mn^{2+}\)

\(Mn^{3+}\)

\(Mn^-\)

Solution

Question 2

There is no change in the composition of atom

It gains two electrons

The mass number changes

None of these

Solution

Question 3

Oxidation

Reduction

Oxidation and reduction (Redox)

Neutralization

Solution

Question 4

Loses electrons

Gains electrons

Both loses and gains electron

Electron change takes place

Solution

Question 5

Solvated \(Na^+\)ions

Solvated electrons

Solvated \(NH^{-2}\)ions

Solvated protons

Solution

Question 6

Loss of electrons

Gain of electrons

Increase in the valency of negative part

Decrease in the valency of positive part

Solution

Question 7

\(CO\,and\,Cl_2 \)

\(SO_2\,and\,Cl_2\)

\(H_2S\,and\,Br_2 \)

\(NH_3\,and\,SO_2\)

Solution

Question 8

Oxidation of \(Cu^{+2}\)

Reduction of \( cu^{+2}\)

Hydrolysis of \(CuSO_4 \)

Ionization of \(CuSO_4\)

Solution

Question 9

\(HNO_3\)

\(H_2SO_4\)

\(HCl\)

\(HNO_2\)

Solution

Question 10

\(SO_2\)

\(MnO_2\)

\(Al_2O_3\)

\(CrO\)

Solution

Question 11

\(H_3PO_3 \) is dibasic and reducing

\(H_3PO_3\) is dibasic and non-reducing

\(H_3PO_4\) is tribasic and reducing

\(H_3PO_3\) is tribasic and non-reducing

Solution

Question 12

+3

-3

-1

+5

Solution