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Redox Reactions Test - 27

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Redox Reactions Test - 27
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  • Question 1
    1 / -0
    The oxidation number of phosphorous in $$P{ O }_{ 4 }^{ 3- },\  { P }_{ 4 }{ O }_{ 10 }$$ and $${ P }_{ 2 }{ O }_{ 7 }^{ 4- }$$ is :
    Solution
    The oxidation number of phosphorous in $$P{ O }_{ 4 }^{ 3- },  { P }_{ 4

    }{ O }_{ 10 }$$ and $${ P }_{ 2 }{ O }_{ 7 }^{ 4- }$$ is +5.
    Let X be the oxidation number of P in $$P{ O }_{ 4 }^{ 3- }$$.
    $$\displaystyle X+4(-2) = -3 $$
    $$\displaystyle  X = +5$$
    Let X be the oxidation number of P in$$  { P }_{ 4.

    }{ O }_{ 10 }$$
    $$\displaystyle 4X +10(-2) =0 $$
    $$\displaystyle X = +5 $$
    Let X be the oxidation number of P in$${ P }_{ 2 }{ O }_{ 7 }^{ 4- }$$.
    $$\displaystyle 2X + 7(2-) =-4 $$
    $$\displaystyle X =+5 $$
  • Question 2
    1 / -0
    The change in the oxidation number of the underlined nitrogen atom in the following chemical reactions are :
    a.  Nitrous acid $$\left( H\underline { N } { O }_{ 2 } \right)$$ reduces $$Mn{ O }_{ 4 }^{ \ominus  }$$ in acid solution.
    b.  Nitrous acid $$\left( H\underline { N } { O }_{ 2 } \right)$$ oxidises $${ I }^{ \ominus  }$$ to $${ I }_{ 2 }$$ in acid solution.
    Solution
    The balanced reactions are as follows:
    i.  $$2Mn{ O }_{ 4 }^{ \ominus  } + 6{ H }^{ + } + 5N{ O }_{ 2 }^{ \ominus  } \longrightarrow 5N{ O }_{ 3 }^{ \ominus  } + 3{ H }_{ 2 }O + 2{ Mn }^{ 2+ }$$
    ii.  $$2HN{ O }_{ 2 } + 2{ H }^{ \oplus  } + 2{ I }^{ \ominus  } \longrightarrow 2NO + 2{ H }_{ 2 }O + { I }_{ 2 }$$
    Oxidation number of $$N$$ changes from +3 to +5 in (i).
    Oxidation number of $$N$$ changes from +3 to +2 in (ii).
  • Question 3
    1 / -0
    When $$kMnO_4$$ acts as an oxidising agent and ultimately forms $$MnO^{2-}_4,\  MnO_2,\, Mn_2O_3,$$ $$\, $$and$$\, Mn^{2+}$$, determine the number of electrons transferred in each case.
    Solution
    $$KMnO_4 \xrightarrow {1e^-} MnO_4^{2-}$$
    $$KMnO_4 \xrightarrow {3e^-} MnO_2$$
    $$KMnO_4 \xrightarrow {4e^-} Mn_2O_3$$
    $$KMnO_4 \xrightarrow {5e^-} Mn^{2+}$$
  • Question 4
    1 / -0
    The oxidation state of manganese in $${K}_{2}Mn{O}_{4}$$ is:
  • Question 5
    1 / -0
    The oxidation number of sulphur in $${H}_{2}{SO}_{4}$$ is :
    Solution
    For a compound $${H}_{2} \mathrm{SO}_{4}$$,

    As net charge on compound is $$0$$
    Charge on :  $$H =1$$ 
    $$~~~~~~~~~~~~~~~~~~~~S =x$$  
    $$~~~~~~~~~~~~~~~~~~~~O =-2$$ 
    $$1(2)+x+(-2)(4)=0$$
    $$2+x-8=0$$
    $$x=6$$

    Hence, option C is correct.
  • Question 6
    1 / -0
    Oxidation number of $$S$$ in $${S_2O_3}^{2-}$$ is:
    Solution
    Let Oxidation number of S in $$S_2O_3^{2-}$$ be x.
    Thus,
    2x+(-2*3)= -2 
    2x-6= -2 
    2x= -2+6 
    2x=4 
    x=4\2 
    x=2 
    so the oxidation state of sulfur is +2
  • Question 7
    1 / -0
    Which of the following does not represent redox reaction?
    Solution
    $$Cr_2O^{2-}_7\,+\,2 OH^-\,\rightarrow\, 2CrO^{2-}_4\,+\,H_2O$$ 
    Above reaction represents redox reaction since it does not undergoes oxidation or reduction.
  • Question 8
    1 / -0
    Determine oxidation number of iron in $$Na_2[Fe(CN)_5(NO)]$$.
    Solution
    $$CN$$ has a charge of $$-1$$, $$NO$$ is $$0$$, and $$Na$$ is $$+1$$. This makes $$Fe\ +3$$, since it has to combine with the overall $$+2$$ from the sodium ions to balance the overall $$-5$$ from the cyanide groups.

    $$2 \times (+1) +x + 5 \times (-1) + 0= 0$$

    $$x=+3$$

    Option B is correct. 
  • Question 9
    1 / -0
    Determine the oxidation state of Cr in $$[Cr(NH_3)_4Cl_2]Cl$$
    Solution
    $$NH_3$$ is 0 
    each $$Cl$$ inside the brackets is -1 
    the final $$Cl$$ is -1 
    sooxidation staate of $$Cr$$ is +3. 
  • Question 10
    1 / -0
    In $$\displaystyle HCN$$ oxidation number of carbon is?
    Solution
    $$HCN =H^+ + CN^{-}$$

    $$x-3=-1$$


    $$x=-1+3$$


    $$x=+2$$
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