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Redox Reactions Test - 59

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Redox Reactions Test - 59
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  • Question 1
    1 / -0
    Balance the following equation and choose the quantity which is the sum of the coefficients of reactants and products:
                 ......... $$ PtCl_4 $$ + ........... $$ XeF_4 \rightarrow PtF_{6} $$ +  ....$$ClF $$ + ....$$Xe $$ 
    Solution
    Balanced reaction is 
    $$ PtCl_4 + 5XeF_4 \rightarrow PtF_{6} + 4ClF + 5Xe $$ 
    $$ \therefore $$ Sum of stoichiometric coefficients
    $$ = 1 + 5 + 1 + 4 + 5 = 16 $$ 
  • Question 2
    1 / -0
    Oxidation number of carbon in $$CH_2Cl_2$$ is:
    Solution
    $$CH_2Cl_2$$

    Let the oxidation number of C is $$x$$.

    $$\to x+2(+1)+2(-1)=0$$

    $$\Rightarrow x=0$$
  • Question 3
    1 / -0
    The value of coefficients to balance the following reaction are
    $$Cr(OH)_3+ClO^-+OH^- \rightarrow CrO_4^{2-}+Cl^-+H_2O$$
    Solution

  • Question 4
    1 / -0
    Oxidation number of iodine in $$IO_3^-, IO_4^- , KI$$ and $$I_2$$ respectively is:
    Solution
    $$IO_3^- \to x+3(-2)=-1\Rightarrow x=+5$$

    $$IO_4^-\to x+4(-2)=-1\Rightarrow x=+7$$

    $$KI \to +1+x=0\Rightarrow x=-1$$

    $$I_2 \to 0 \Rightarrow x=0$$
  • Question 5
    1 / -0
    Oxidation state of Osmium (Os) in $$ \mathrm{OsO}_{4} $$ is
    Solution
    $$ +8 $$
  • Question 6
    1 / -0
    The reaction, $$ 3 \mathrm{ClO}^{-}(a q) \rightarrow $$ $$ \mathrm{ClO}_{3}^{-}(a q)+2 \mathrm{Cl}^{-}(a q) $$ is an example of
    Solution
    Disproportionation reaction
  • Question 7
    1 / -0
    Oxidation number of sodium in sodium amalgam is
    Solution
    Sodium amalgam is a homogenous mixture of Na and $$ \mathrm{Hg} $$ and as such Na exists in the elemental state and hence its O.N. is zero.
  • Question 8
    1 / -0
    The oxidation number of phosphorus in $$ \mathrm{Ba}\left(\mathrm{H}_{2} \mathrm{PO}_{2}\right)_{2} \ \mathrm{is} $$
    Solution
    c. $$+1 $$
  • Question 9
    1 / -0
    If a half cell reaction, $$ A+e^{-} \longrightarrow A^{-} $$ has a large negative reduction potential, it follows that
    Solution
    $$\text{Large negative potential for the reaction, } A + e ^ { - }  \rightarrow \mathrm{A}^{-} $$ implies that the reverse reaction occurs,i.e., $$ A^{-} $$ is readily oxidised.
  • Question 10
    1 / -0
    In which of the following pairs, there is the greatest difference in the oxidation number of the underlined elements?
    Solution
    d.$$ \underline{\mathrm{S}} \mathrm{O}_{2} $$ and $$ \underline{\mathrm{S}}O_{3} $$
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