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Redox Reactions...

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  • Question 1
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    When $$SO_2$$ is passed through a solution of $$K_2Cr_2O_7$$ turns green. The change in oxidation state of chromium and sulphur are ___________________ respectively.

  • Question 2
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    Amongst the following, identify the species with an atom in $$+6$$ oxidation state.

  • Question 3
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    Number of moles of acidic $$KMnO_4$$ needed for complete oxidation of $$1$$ mole equimolar mixture of $$FeSO_4$$ and $$FeC_2O_4$$ is:

  • Question 4
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    On passing $$CO_2$$ into aqueous yellow coloured $$CrO_4^{2-}$$ solution, an orange coloured $$Cr_2O_7^{2-}$$ solution is obtained. Is this oxidation or reduction? The reaction is given below:
    $$CrO_4^{2-} (aq) \xrightarrow []{CO_2} Cr_2O_7^{2-}$$

  • Question 5
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    Directions For Questions

    $$632$$ g of sodium thiosulphate $$(Na_2S_2O_3)$$ reacts with copper sulphate to form cupric thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound, sodium cuprous thiosulphate $$(Na_4[Cu_6(S_2O_3)_5]).$$ The reactions are as follows:

      $$CuSO_4+Na_2S_2O_3 \rightarrow CuS_2O_3+Na_2SO_4$$
      $$2CuS_2O_3+Na_2S_2O_3\rightarrow Cu_2S_2O_3+Na_2S_4O_6$$
      $$3Cu_2S_2O_3+2Na_2S_2O_3 \rightarrow Na_4(Cu_6(S_2O_3)_5]$$

    In this process, $$0.2$$ mole of sodium cuprousthiosulphate is formed (O=$$16$$, Na = $$23$$, S=$$32$$).

    ...view full instructions

    The average oxidation states of sulphur in $$Na_2S_2O_3$$ and $$Na_2S_4O_6$$ are, respectively :

  • Question 6
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    When $$KMnO_4$$ acts as an oxidising agent and ultimately forms $$MnO^{2-}_4$$,$$MnO_2$$, $$Mn_2O_3$$ and $$Mn^{2+}$$, then the number of electrons transferred per molecule of $$KMnO_4$$ in each case respectively, is:

  • Question 7
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    When $$(NH_4)_2 Cr_2O_7$$ is heated $$Cr_2O_3$$ is produced as a produnct and some other by product are also produced. What is the type of reaction?

  • Question 8
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     How many substances have underlined atoms of different nature?
    $$Na_2\underline{S_4}O_6,Na_2\underline{S_2}O_3,CaO\underline{Cl_2},\underline{N_2}H_4O_3,\underline{Fe_3}O_4,K\underline{I_3},Cr\underline{O_5},K_2\underline{Cr_2}O_7$$

  • Question 9
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    Oxidation state of  'S' in sodium tetrathionate is :

  • Question 10
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    Anhydride of an acid is formed by dehydration and oxidation number of central atom remains unchanged.
    Acid : $$H_2N_2O_2, HNO_2, HNO_3$$
    Anhydride : $$N_2O_5, N_2O, NO, N_2O_3$$
    Correct match of acid with its anhydride is

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