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Redox Reactions Test - 8

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Redox Reactions Test - 8
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  • Question 1
    1 / -0

    Standard electrode potential for Sn4+/Sn2+ couple is +0.15 V and that for the Cr3+ / Cr couple is –0.74 V. These two couples in their standard state are connected to make a cell. The cell potential will be

    Solution

    Ecell = Ecathod - Eanode

    Anodic half cell will be Cr3+/Cr.

    Cathodic half cell will be Sn4+/ Sn2+.

    So,  Ecell= 0.15+0.74 = +0.89 V

  • Question 2
    1 / -0

    Standard electrode potential of three metals X, Y and Z are –1.2 V, +0.5 V and –3.0 V respectively. The reducing power of these metals will be

    Solution

    E0x= –1.2 V; E0y=+0.5 V; E0z= -3.0 V

    Because higher the reduction potential, lesser the reducing power.

    Therefore, Z > X > Y

  • Question 3
    1 / -0

    The oxidation state of iron in K4[Fe (CN )6] is

    Solution

    K[Fe(CN)6]

    4(+1) + x + 6(-1) = 0

    Hence x = +2

  • Question 4
    1 / -0

    A metal in a compound can be displaced by another metal in the uncombined state. Which metal is a better reducing agent in such a case?

    Solution

    The metal causing displacement is a better reducing agent than the one that is being replaced. In simple words such a metal shows more capability to loose electrons as comparaed to the one that is reduced.

  • Question 5
    1 / -0

    Hydrogen is prepared from H2O by adding

    Solution

    Calcium is a silvery-white metal; it is relatively soft, but much harder than sodium metal.  Calcium is a member of the alkaline-earth metals (Group II on the periodic table); these metals react vigorously with water, although not as violently as the Group I metals such as sodium or potassium:

    Ca(s)  +  2H2O(l)  ——>  Ca(OH)2(aq)  +  H2(g)

  • Question 6
    1 / -0

    In the conversion of Br2 to Bro3- , the oxidation number of Br changes from

    Solution

    In Broxidation number of Br is 0 while in BrO-Br has oxidation number of +5 as each O carries -2 charge and net charge is -1.

  • Question 7
    1 / -0

    In the reaction 2H2O2→ 2H2O + O2

    Solution

    This is a dispropotionation reaction.(Disproportionation is a specific type of redox reaction in which an element from a reaction undergoes both oxidation and reduction to form two different products)

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