Redox Reactions Test

Result

Redox Reactions Test - 9

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following is not an example of redox reaction?

A
\(CuO+H_2\rightarrow Cu+H_2O\)

B
\(Fe_2O_3+3CO\rightarrow 2Fe+3CO_2\)

C
\(2K+F_2\rightarrow2KF\)

D
\(BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl\)

Solution

Oxidation no. of all the elements remains unchanged.
Question 2
1 / -0

The more positive the value of \(E^{\ominus}\), the greater is the tendency of the species to get reduced. Using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent.

\(E^{\ominus}\) values: \(Fe^{3+}\)/\(Fe^{2+}\) = +0.77; \(I_2\)(s)/\(I^-\) = +0.54;

\(Cu^{2+}\)/Cu = +0.34; \(Ag^+\)/Ag = +0.80V

A
\(Fe^{3+}\)

B
\(I_2(s)\)

C
\(Cu^{2+}\)

D
\(Ag^+\)

Solution

\(Ag^+\)/Ag has highest value of reduction potential.
Question 3
1 / -0

\(E^{\ominus}\) values of some redox couples are given below. On the basis of these values choose the correct option.

\(E^{\ominus}\) values: \(Br_2\)/\(Br^-\) = +1.90; \(Ag^+\)/Ag(s) = +0.80

\(Cu^{2+}\)/Cu(s) = +0.34; \(I_2(s)\)/\(I^-\) = +0.54

A
Cu will reduce \(Br^-\)

B
Cu will reduce Ag

C
Cu will reduce \(I^-\)

D
Cu will reduce \(Br_2\)

Solution

\(Br_2\) is better oxidizing agent than \(Cu^{2+}\).
Question 4
1 / -0

Using the standard electrode potential, find out the pair between which redox reaction is not feasible.

\(E^{\ominus}\) values: \(Fe^{3+}\)/\(Fe^{2+}\) = +0.77; \(I_2\)/\(I^-\) = +0.54;

\(Cu^{2+}\)/Cu = +.034; \(Ag^+\)/Ag = +0.80 V

A
\(Fe^{3+}\) and \(I^-\)

B
\(Ag^+\) and Cu

C
\(Fe^{3+}\) and Cu

D
Ag and \(Fe^{3+}\)

Solution

\(E^0_{cell}\) will be negative for the pair Ag and \(Fe^{3+}\). Hence the reaction is not feasible.
Question 5
1 / -0

Thiosulphate reacts differently with iodine and bromine in the reactions given below:

\(2S_2O^{2-}_3+I_2\) → \(S_4O^{2-}_6+2I^-\)

\(S_2O^{2-}_3+2Br_2+5H_2O\) → \(2SO^{2-}_4+2Br^-+10H^+\)

Which of the following statements justifies the above dual behaviour of thiosulphate?

A
Bromine is a stronger oxidant than iodine

B
Bromine is a weaker oxidant than iodine

C
Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions

D
Bromine undergoes oxidation and iodine undergoes reduction in these reactions

Solution

Standard reduction potential of bromine is higher than Iodine.
Question 6
1 / -0

Which of the following statement(s) is/are not true about the following decomposition reaction.

\(2KClO_3\) → 2KCl + 3\(O_2\)

(i) Potassium is undergoing oxidation

(ii) Chlorine is undergoing oxidation

(iii) Oxygen is reduced

(iv) None of the species are undergoing oxidation or reduction

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

Potassium remains in same oxidation state and oxygen is being oxidized.
Question 7
1 / -0

In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): Among halogens fluorine is the best oxidant.

Reason (R): Fluorine is the most electronegative atom.

A
Both A and R are true and R is the correct explanation of A

B
Both A and R are true but R is not the correct explanation of A

C
A is true but R is false

D
Both A and R are false

Solution

Fluorine is most electronegative element that is why it is best oxidant among halogens.

Question 8

1 / -0

Match Column I with Column II for the oxidation states of the central atoms.

Column I	Column II
(i) \(Cr_2O^{2-}_7\)	(a) +3
(ii) \(MnO^-_4\)	(b) +4
(iii)\(VO^-_3\)	(c) +5
(iv) \(FeF^{3-}_6\)	(d) +6
	(e) +7

(i)→ (d) (ii)→ (e) (iii) → (c) (iv)→(b)

(i)→ (d) (ii)→ (e) (iii) → (c) (iv)→(a)

(i)→ (d) (ii)→ (e) (iii) → (a) (iv)→(c)

(i)→ (e) (ii)→ (d) (iii) → (c) (iv)→(a)

Question 9
1 / -0

Identify the correct statement (s) in relation to the following reaction:

Zn + 2HCl → Zn\(Cl_2\) + \(H_2\)

(i) Zinc is acting as an oxidant

(ii) Chlorine is acting as a reductant

(iii) Hydrogen ion is acting as an oxidant

(iv) Zinc is acting as a reductant

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

Zinc is oxidized in the reaction and hydrogen is reduced.
Question 10
1 / -0

The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?

A
The oxidation number of hydrogen is always +1

B
The algebraic sum of all the oxidation numbers in a compound is zero

C
An element in the free or the uncombined state bears oxidation number zero

D
In all its compounds, the oxidation number of fluorine is -1

Solution

In ionic hydrides hydrogen exist in -1 oxidation state because the hydrogen acquires negative charge in the presence of its companion.
Question 11
1 / -0

In which of the following compounds, an element exhibits two different oxidation states.

A
\(NH_2OH\)

B
\(NH_4NO_3\)

C
\(N_2H_4\)

D
\(N_3H\)

Solution

Nitrogen exists in two different oxidation states i.e., +5 and -3.
Question 12
1 / -0

The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds?

(i) 3\(s ^1\)

(ii) 3\(d ^1\)4\(s ^2\)

(iii) 3\(d ^2\)4\(s ^2\)

(iv) 3\(s ^2\)3\(p ^3\)

A
(i),(iv)

B
(iii),(iv)

C
(ii),(iii)

D
(i),(ii)

Solution

In option (iii) electron can be removed from 4s as well as 3d. Similarly, in option (iv) electron can be removed from 3p and 3s both.
Question 13
1 / -0

Which of the following arrangements represent increasing oxidation number of the central atom?

A
\(CrO^-_2,ClO^-_3,CrO^{2-}_4,MnO^-_4\)

B
\(ClO^-_3,CrO^{2-}_4,MnO^-_4,CrO^-_2\)

C
\(ClO^-_2,ClO^-_3,MnO^-_4,CrO^{2-}_4\)

D
\(CrO^{2-}_4,MnO^-_4,CrO^-_2,ClO^-_3\)

Solution

Oxidation no. of central element increases as +3, +5, +6, +7.
Question 14
1 / -0

The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number?

A
\(3d^14s^2\)

B
\(3d^34s^2\)

C
\(3d^54s^1\)

D
\(3d^54s^2\)

Solution

Total no. of electrons present in d and s subshell = 7
Question 15
1 / -0

Identify the correct statements with reference to the given reaction:

\(P_4\) + \(3OH^-\) + \(3H_2O\) → \(PH_3\) + \(3H_2\)\(PO^-_2\)

(i) Phosphorus is undergoing reduction only

(ii) Phosphorus is undergoing oxidation only

(iii) Phosphorus is undergoing oxidation as well as reduction

(iv) Hydrogen is undergoing neither oxidation nor reduction

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

This is a kind of disproportionation reaction in which phosphorous is being reduced as well as oxidized whereas hydrogen remains same in +1 oxidation state.
Question 16
1 / -0

In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): In the reaction between potassium permanganate and potassium iodide, permanganate ions act as oxidising agent.

Reason (R): Oxidation state of manganese changes from +2 to +7 during the reaction

A
Both A and R are true and R is the correct explanation of A

B
Both A and R are true but R is not the correct explanation of A

C
A is true but R is false

D
Both A and R are false

Solution

As permanganate ion changes to \(MnO_2\).
Question 17
1 / -0

Which of the following electrodes will act as anodes, when connected to Standard Hydrogen Electrode?

(i) Al/\(Al^{3+}\)   \(E^{\ominus}\) = -1.66

(ii) Fe/\(Fe^{2+}\)  \(E^{\ominus}\) = -0.44

(iii) Cu/\(Cu^{2+}\)  \(E^{\ominus}\) = +0.34

(iv) \(F_2\)(g)/2\(F^-\)(aq) \(E^{\ominus}\) = +2.87

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

Both has negative value of standard reduction potential.
Question 18
1 / -0

Identify disproportionation reaction

A
\(CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O\)

B
\(CH_4 + 4Cl_2 \rightarrow CCl_4 + 4HCl\)

C
\(2F_2 + 2OH^- \rightarrow 2F^- + OF_2 + H_2O\)

D
\(2NO_2 + 2OH^- \rightarrow NO_2^- + NO_3^- + H_2O\)

Solution

Oxidation no. of nitrogen decrease by 1 from \(NO_2\) to \(NO_2^-\) and increase by +1 from \(NO_2\) to \(NO_3^-\).
Question 19
1 / -0

Which of the following elements does not show disproportionation tendency?

A
Cl

B
Br

C
F

D
I

Solution

Fluorine is the most electronegative element.

Question 20

1 / -0

Match the items in Column I with relevant items in Column II.

Column I	Column II
(i) Ions having positive charge	(i) +7
(ii)The sum of oxidation number of all atoms in a neutral molecule	(ii) -1
(iii)Oxidation number of hydrogen ion (\(H ^+ \))	(iii) +1
(iv)Oxidation number of fluorine in NaF	(d) 0
(v) Ions having negative charge	(e) Cation
	(f) Anion

(i)→ (e) (ii) → (d) (iii) → (c) (iv) → (f) (v) → (b)

(i)→ (e) (ii) → (d) (iii) → (c) (iv) → (b) (v) → (a)

(i)→ (d) (ii) → (e) (iii) → (c) (iv) → (b) (v) → (f)

(i)→ (e) (ii) → (d) (iii) → (c) (iv) → (b) (v) → (f)

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Redox Reactions Test - 9

Result

Redox Reactions Test - 9

Score

-

Rank

-

SHARING IS CARING

Question 1

\(CuO+H_2\rightarrow Cu+H_2O\)

\(Fe_2O_3+3CO\rightarrow 2Fe+3CO_2\)

\(2K+F_2\rightarrow2KF\)

\(BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl\)

Solution

Question 2

\(Fe^{3+}\)

\(I_2(s)\)

\(Cu^{2+}\)

\(Ag^+\)

Solution

Question 3

Cu will reduce \(Br^-\)

Cu will reduce Ag

Cu will reduce \(I^-\)

Cu will reduce \(Br_2\)

Solution

Question 4

\(Fe^{3+}\) and \(I^-\)

\(Ag^+\) and Cu

\(Fe^{3+}\) and Cu

Ag and \(Fe^{3+}\)

Solution

Question 5

Bromine is a stronger oxidant than iodine

Bromine is a weaker oxidant than iodine

Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions

Bromine undergoes oxidation and iodine undergoes reduction in these reactions

Solution

Question 6

(i),(ii)

(ii),(iii)

(iii),(iv)

(i),(iv)

Solution

Question 7

Both A and R are true and R is the correct explanation of A

Both A and R are true but R is not the correct explanation of A

A is true but R is false

Both A and R are false

Solution

Question 8

(i)→ (d) (ii)→ (e) (iii) → (c) (iv)→(b)

(i)→ (d) (ii)→ (e) (iii) → (c) (iv)→(a)

(i)→ (d) (ii)→ (e) (iii) → (a) (iv)→(c)

(i)→ (e) (ii)→ (d) (iii) → (c) (iv)→(a)

Question 9

(i),(ii)

(ii),(iii)

(iii),(iv)

(i),(iv)

Solution

Question 10

The oxidation number of hydrogen is always +1

The algebraic sum of all the oxidation numbers in a compound is zero

An element in the free or the uncombined state bears oxidation number zero

In all its compounds, the oxidation number of fluorine is -1

Solution

Question 11

\(NH_2OH\)

\(NH_4NO_3\)

\(N_2H_4\)

\(N_3H\)

Solution

Question 12

(i),(iv)

(iii),(iv)

(ii),(iii)

(i),(ii)

Solution

Question 13