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Organisation of Data Test - 7

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Organisation of Data Test - 7
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  • Question 1
    1 / -0

    Convert the following inclusive series into exclusive series.

    50-59,60-69

    Solution

    To convert the inclusive series into exclusive series, we can use following steps :
    (i) First, we find the difference of the upper limit of class interval and the lower limit of the next class interval
    (ii) Half of that difference is added to the upper limit of class interval and half is subtracted from the lower limit of the class interval.

  • Question 2
    1 / -0

    Find out the class interval from the following mid-points.

    Mid-value Frequency
    12.5 7
    17.5 12
    Solution

    When the mid-values of class-intervals are given the class-intervals are found by first finding out the difference between two mid-values and then subtracting half of it from each mid-value to find the lower limit and adding it to each mid-value to find the upper limit of the class-intervals.

  • Question 3
    1 / -0

    Mid point of Class interval 10-20 is

    Solution

    Mid point of a class interval can be obtained by adding lower class and upper class and dividing by 2.

  • Question 4
    1 / -0

    Calculate the range of class interval 15-35

    Solution

    The Range is the difference between the lowest and highest values. 

  • Question 5
    1 / -0

    Convert the following into simple frequency.
    5 students obtained less than 3 marks
    12 students obtained less than 6 marks

    Solution

    0-3, implies no.of all students obtaining marks below 3 but greater than 0. Similarly, for other class greater than 3 but less than 6. 

  • Question 6
    1 / -0

    Calculate the mid-value of class interval 99.5-109.5

    Solution

    The mid-points of class-intervals of various class group are called mid-values. MV= (Lower limit + Upper limit) /2

  • Question 7
    1 / -0

    Which of the following is expressed in open –ended class

    Solution

    If, in a frequency distribution, the initial class interval is indeterminate at its beginning and/or the final class interval is indeterminate at its end, the distribution is said to possess “open ended” classes.

  • Question 8
    1 / -0

    Refer the table given below calculate that how many workers get a daily wages of 109 and below. Options are

    Daily wages (Rs) No. of workers
    90-99 5
    100-109 9
    110-119 3
    Solution

    The total frequencies of a particular class and all classes prior to that particular class is called the Less than type cumulative frequency of that class or simply the Cumulative frequency of that class. Here the no of workers who got wages below 109 equals 5+9=14

  • Question 9
    1 / -0

    Refer the table given below calculate that how many workers get a daily wages of 100 and above. Options are

    Daily wages(Rs) No of workers
    90-99 5
    100-109 9
    110-119 3
    Solution

    The cumulative frequency of a particular class and all the classes after that class is called the "greater than" type cumulative frequency.  Here we take the frequency of the class 100 onwards ie., 9+3=12

  • Question 10
    1 / -0

    Calculate the class interval of the class 94.5-99.5

    Solution

    Class interval refers to the numerical width of any class in a particular distribution. Mathematically it is defined as the difference between the upper class limit and the lower class limit.

    Class Interval= Upper Class limit – Lower class limit

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