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Sets Test - 40

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Sets Test - 40
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  • Question 1
    1 / -0
    In a universal set x,$$n\left( x \right) = 50$$ ,$$n\left( A \right) = 35$$ , $$n\left( B \right) = 20$$ , $$n\left( {A' \cap B'} \right) = 5$$ ,then $$n\left( {A \cup B} \right),n\left( {A \cap B} \right)$$ are repsectively 
    Solution
    Given $$n\left(X\right) = 50$$,
    $$n\left(A\right) = 35$$,
    $$n\left(B\right) = 20$$
    $$n\left({A}^{\prime}\cap\,{B}^{\prime}\right) = 5$$

    $$(i)\,n\left(A \cup B\right)$$  
    $$n\left({A}^{\prime}\cap\,{B}^{\prime}\right) = n\left(X\right) - n\left(A\cup\,B\right)$$
    $$n\left(A\cup\, B\right) = n\left(X\right) - n\left({A}^{\prime}\cap\,{B}^{\prime}\right)$$
    $$n\left(A\cup\, B\right) = 50 - 5= 45$$

    $$(ii) n\left(A \cap B\right)$$
    $$n\left(A\cup B\right) = n\left(A\right) + n\left(B\right) - n\left(A\cap B\right)$$
    $$n\left(A\cap\, B\right) = n\left(A\right) + n\left(B\right) - n\left(A\cup\, B\right)$$
    $$n\left(A\cap\, B\right) = 35 + 20 - 45= 10$$
  • Question 2
    1 / -0
    If  $$A$$  and  $$B$$  are two non empty sets then  $$( A \cup B ) ^ { C } = ?$$
    Solution
    If A and B are two no empty sets then $${ \left( A\cup B \right)  }^{ C }={ A }^{ C }\cap { B }^{ C }$$
  • Question 3
    1 / -0
    Let $$S={1,2,3,.....10}$$ and $$P={1,2,3,4,5}$$ The number of subsets $$'Q'$$ of $$S$$ such that $$p \cup Q=S$$, are.....
  • Question 4
    1 / -0
    The statement that is true among the following is 
    Solution

  • Question 5
    1 / -0
    Let  $$Q$$  be a non empty subset of  $$N$$  and  $$q$$  is a statement as given below :
    $$q:$$  There exists an even number  $$a \in Q$$  Negation of the statement  $$q$$  will be :
    Solution
    Let $$Q$$ be a non empty subset of $$N$$ and $$q.$$ There exists even number $$a\in Q$$ negation of statement $$q.$$ There does not exist a even number in set Q.
    Hence, the answer is there is no even number in the set $$Q.$$

  • Question 6
    1 / -0
    In a battle $$70$$% of the combatants lost one eye, $$80$$% an ear, $$75$$% an arm, $$85$$% a leg, $$x$$% lost all the four limbs the minimum value of $$x$$ is
    Solution
    $$70\%$$ of the combatants lost one eye, $$80\%$$ an ear, $$75\%$$ an arm and $$85\%$$ a leg.
    Now, 
    $$\Rightarrow$$  The combatants who lost one eye and one ear $$=(70+80-100)\%$$
                                                                                          $$=50\%$$

    $$\Rightarrow$$  The combatants who lost one eye, one ear and one erm $$=(50+75-100)\%$$
                                                                                                          $$=25\%$$

    $$\Rightarrow$$  The combatants who lost one eye, one ear one arm and one leg $$=(25-85-100)\%$$ 
                                                                                                                        $$=10\%$$
    $$\therefore$$  Combatant who lost all the four limbs $$=10\%$$
    $$\therefore$$  $$x=10\%$$
  • Question 7
    1 / -0
    The value of set $$(A\cup B\cup C)\cap(A\cap B^1\cap C^1)^1\cap C^1$$ is equal to  
    Solution

  • Question 8
    1 / -0
    Two sets A and B are defined as follows
    $$A=\left\{ \left( x,y \right) :y={ e }^{ 2x },x\in R \right\} $$ and 
    $$B=\left\{ \left( x,y \right) :y={ x }^{ 2 },x\in R \right\} $$, then
    Solution
    $$\begin{array}{l} A=\left\{ { \left( { x,\, y } \right) \, :\, y={ e^{ 2x } },\, x\in R } \right\} \, and \\ B=\left\{ { \left( { x,\, y } \right) \, :\, y={ x^{ 2 } },\, x\in R } \right\}  \\ then, \\ A=\left( { { e^{ \circ  } },\, { e^{ 1 } },\, { e^{ 2 } },....,\, { e^{ \infty  } } } \right)  \\ =\left( { 1,\, { e^{ 1 } },\, { e^{ 2 } },....... } \right)  \\ and, \\ B=\left( { 0,\, 1,\, 4,\, ..... } \right)  \\ \therefore A\subset B \\ Hence,\, the\, option\, A\, is\, the\, correct\, answer. \end{array}$$
  • Question 9
    1 / -0
    If two sets $$P$$ and $$Q,n\left(P\right)=5,n\left(Q\right)=4$$ then $$n\left(P\times Q\right)=$$
    Solution
    $$\begin{aligned} n(P \times Q) &=n(P) \times n(Q) \\ &=5 \times 4 \\ &=20 \end{aligned}$$
    $$\therefore$$ option $$A$$ is correct.
  • Question 10
    1 / -0
    If A= {1, 2, 5} and B= {3, 4, 5, 9}, then $$A \bigcup B$$ is equal to :
    Solution
    $$A=\left\{ 1,2,5 \right\} \quad B=\left\{ 3,4,5,9 \right\} $$
    $$A\cup B=\left\{ 1,2,3,4,5,9 \right\} $$
    Option C.
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