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Introduction to Three Dimensional Geometry Test - 38

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Introduction to Three Dimensional Geometry Test - 38
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  • Question 1
    1 / -0
    If O and O' are circumcenter and orthocenter of a $$\Delta ABC$$ where $$\overline{OA} + \overline{OB} + \overline{OC}$$ is $$\lambda \overline{OO'}$$ then the value of $$\lambda$$ is
    Solution

  • Question 2
    1 / -0
    The distance between the orthocentre and circumcentre of the triangle formed by the points $$(1, 2, 3), (3, -1, 5), (4, 0, -3)$$ is
    Solution

  • Question 3
    1 / -0
    If $$R$$ divides the line segment joining $$P(2,3,4)$$ and $$Q(4,5,6)$$ in the ratio $$-3:2$$, then the parameter which represent $$R$$ is 
    Solution
    $$x=\cfrac { -3\times 4+2\times 2 }{ -1 } \quad \quad y=\cfrac { -3\times 5+2\times 3 }{ -1 }$$
    $$x=\cfrac { -12+4 }{ -1 } \quad \quad$$$$y =\cfrac { -15+6 }{ -1 } $$
    $$x=8\quad \quad y=9$$
    $$z=\cfrac { -3\times 6+2\times 4 }{ -1 } =\cfrac { -10 }{ -1 } $$
    $$z=10$$
    $$R=\left( 8,9,10 \right) $$

  • Question 4
    1 / -0
    In the $$xy-plane$$, the length of the shortest from $$(0, 0)$$ to $$(12, 16)$$ that does not go inside the circle $$(x - 6)^{2} + (y + 8)^{2} = 25$$ is
  • Question 5
    1 / -0
    Consider at three dimensional figure represented by $$xy{ z }^{ 2 }=2$$, then its minimum distance from origin is
    Solution

  • Question 6
    1 / -0
    Perpendicular distance from the origin to the line joining the points $$(a\cos{\theta},a\sin{\theta})(a\cos{\theta},a\sin{\theta})$$ is
  • Question 7
    1 / -0
    Q, R, S are the points $$(-2, -1), (0, 3) (4, 0)$$ respectively. Then the coordinates of P such that PQRS is a parallelogram is ________________.
  • Question 8
    1 / -0
    The point which is equidistant from the points $$(-1,1,3),(2,1,2),(0,5,6)$$ and $$(3,2,2)$$ is
    Solution

  • Question 9
    1 / -0
    Minimum distance between the curves
    $$y^{2}=4x$$ & $$x^{2}+y^{2} -12x+31=0$$ is -
    Solution

  • Question 10
    1 / -0

    Directions For Questions

    [passage-header]Let $$A(2,3,5),B(-1,3,2)$$ and $$C(\lambda ,5,\mu )$$ are the vertices of a triangle and its median through A meets side BC at D. AD is equally inclined with the axes. If E is the point on BC such that $$BE:EC=1:2.$$[/passage-header]

    ...view full instructions

    Let $$A(2,3,5),B(-1,3,2)$$ and $$C(\lambda ,5,\mu )$$ are the vertices of a triangle and its median through A meets side BC at D. AD is equally inclined with the axes. If E is the point on BC such that $$BE:EC=1:2.$$
    Project of BA on BC
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