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Statistics Test - 20

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Statistics Test - 20
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  • Question 1
    1 / -0
    If t is the standard deviation of x, y, z then the standard deviation of x + 5, y + 5, z + 5 is
    Solution
    $$\text{Standard deviation is invariant under change of origin}$$
    $$\text{Hence, standard deviation of x+5,y+5, z+5 is same as x, y, z}$$
    $$\Rightarrow \text{ standard deviation of x+5,y+5, z+5 is t}$$.
    Option C is correct.
  • Question 2
    1 / -0
    If the Arithmetic mean of $$8, 6, 4, x, 3, 6, 0$$ is $$4$$; then the value of $$x =$$
    Solution
    Arithmetic mean $$= \cfrac{\text{sum of all observations}}{\text{no. of observations}}$$
    $$\Rightarrow 4=\cfrac { 8+6+4+x+3+6+0 }{ 7 } \\ \Rightarrow 28=27+x\\ \Rightarrow x=1$$
  • Question 3
    1 / -0
    Lowest value of variance can be:
    Solution
    We know that $$Var(x)=E(X^2)-(E(x))^2$$

    Variance is non-negative because the squares are positive or zero.

    Therefore, $$Var(X)\geq 0$$

    Hence, the lowest value of variance is $$zero$$
  • Question 4
    1 / -0
    Which of the following is not a measure of central location?
    Solution
    Mean, median and mode give us the knowledge about the central value.
    But the Variance will give us the deviations from the central tendencies.
  • Question 5
    1 / -0
    If $$\mu$$ is the mean distribution of $$\left (Y_{i}, f_{i}\right )$$, then $$\sum f_i(i - \mu)$$ is equal to.
    Solution
    $$\mu $$ is mean distributaion of $$({ y }_{ i },{ f }_{ i })$$
    $$\Sigma $$ $${ f }_{ i }(i-\mu )$$ $$=$$ Mean deviation
    $$\therefore $$   MD.
  • Question 6
    1 / -0
    The largest of $$50$$ measurements is $$3.84$$kg. If the range is $$0.46$$kg, find the smallest measurement.
    Solution
    $$\Rightarrow$$  Here, $$L=3.84$$ and $$R=0.46$$
    $$\Rightarrow$$  $$R=L-S$$
      $$0.46=3.84-S$$
      $$S=3.84-0.46$$
    $$\therefore$$  $$S=3.38\,kg$$
    $$\therefore$$   Smallest measurement is $$3.38\,kg$$
  • Question 7
    1 / -0
    What is the standard deviation of $$7,9,11,13,15$$?
    Solution
    Given numbers are $$ 7,9,11,13,15$$
    Mean of given numbers $$=\dfrac { 7+9+11+13+15 }{ 5 } =11$$
    Standard deviation$$=\dfrac { |7-11|+|9-11|+|11-11|+|13-11|+|15-11| }{ 5 } =2.4$$
    Option A is true
  • Question 8
    1 / -0
    Find the range and coefficient of range of the following data. $$59, 46, 30, 23, 27, 40, 52, 35, 29$$
    Solution
    $$\Rightarrow$$  The given numbers are $$59,46,30,23,27,40,52,35,29$$.
    $$\Rightarrow$$  Here, the largest value $$=x_m=59$$ and the smallest value $$=x_0=23$$.
    $$\Rightarrow$$  $$Range=x_m-x_0$$
                       $$=59-23$$
                       $$=36$$
    $$\Rightarrow$$  $$Coefficient\,of\,range=\dfrac{x_m-x_0}{x_m+x_0}$$

                                                    $$=\dfrac{59-23}{59+23}$$

                                                    $$=\dfrac{36}{82}$$

                                                    $$=0.44$$
  • Question 9
    1 / -0
    The wickets taken by a bowler in a one-day cricket match are $$4, 5, 6, 3, 4, 0, 3, 2, 3, 5.$$ The mode of the data is ...............
    Solution
    Mode of the set of data is the observation which occurs the most.
    $$4$$ and $$6$$ occurs $$2$$ times each, $$6,~2$$ and $$0$$ occurs $$1$$ time each, whereas $$3$$ occurs $$3$$ times. 
    Thus, the number $$3$$ occurs the maximum number of times i.e., $$3$$. 
    Therefore, mode of the data is $$3$$.
  • Question 10
    1 / -0
    What is the variance of the first $$11$$ natural numbers?
    Solution
    Sum of first $$11$$ natural numbers $$=\dfrac { n(n+1) }{ 2 } =\dfrac { 11\times 12 }{ 2 } =66$$

    So, mean $$ =\dfrac { 66 }{ 11 } =6$$

    Variance $$= { \dfrac { (1-6)^{ 2 }+(2-6)^{ 2 }+(3-6)^{ 2 }+........+(11-6)^{ 2 } }{ 11 }  }$$

    $$= { \dfrac { 25+16+9+4+1+0+1+4+9+16+25 }{ 11 }  }=\dfrac { 110 }{ 11 } =10$$

    Hence, A is correct.
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