Thermal Properties of Matter Test

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Thermal Properties of Matter Test - 31

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Question 1
1 / -0

Assertion: In Joules bulb apparatus, as reservoir is moved up, the mercury level raises into the bulb.
Reason: The pressure on the enclosed gas increases.

A
Both assertion (A) and reason (R) are correct and R gives the correct explanation

B
Both assertion (A) and reason (R) are correct but R doesnt give the correct explanation

C
A is true but R is false

D
A is false but R is true

Solution

Due to increment in pressure, to balance forces, mercury level in bulb must rise.Increment in height will necessarily ensure that Joules bulb apparatus has been in equilibrium condition
Question 2
1 / -0

PV = n RT holds good for :
a) Isobaric process b) Isochoric process
c) Isothermal process d) Adiabatic process

A
a & b

B
a,b & c

C
a,b & d

D
all

Solution

PV=nRT
is ideal gas equation it is valid for each and every process neglecting the non idealities.
Question 3
1 / -0

Which of the following processes will quadruple the pressure
a) Reduce V to half and double T
b) Reduce V to 1/8th and reduce T to half
c) Double V and half T
d) Increase both V and T to double the values

A
b,c

B
a,b

C
c,d

D
a,d.

Solution

(a) First we half the volume at constant T pressure will become double now we double our temperature keeping volume same it will again double the pressure and finally pressure will become quadruple.
(b)When we make volume V/8 keeping temperature constant pressure becomes 8 times now when we half the temperature pressure also gets halved and become 4 times
(c)When we double V and half T pressure will become 1/4 times
(d) if we increase both V and T to double then pressure will not change.
Therefore only (a) & (b) are correct
Therefore option(B) is correct
Question 4
1 / -0

Assertion:PV/T=constant for 1 mole of gas. This constant is same for all gases.
Reason:1 mole of different gases at NTP occupy same volume of 22.4 litres.

A
Both assertion (A) and reason (R) are correct and R gives the correct explanation

B
Both assertion (A) and reason (R) are correct but R doesnt give the correct explanation

C
A is true but R is false

D
A is false but R is true

Solution

For 1 mole
PV/T=R
and universal gas constant R is constant for every gas
therefore 1 mole of gas at NTP will also occupie 22.4 L of volume
Assertion is true reason is true
and reason is correct explaination
option(A)
Question 5
1 / -0

Figure shows a cylindrical tube of cross-sectional area A filled with two frictionless pistons. The pistons are connected through wire. The tension in the wire if the temperature rises from T$$_{0}$$ to 2T$$_{0}$$ is (Initial pressure is P$$_{0}$$, atmospheric pressure)

A
$$P_{0}A$$

B
$$\frac{P_{0}A}{2}$$

C
$$2P_{0}A$$

D
$$\frac{2P_{0}A}{3}$$

Solution

Since the wired would be taut, there would be no change in the volume of enclosed gas, so $$\dfrac{P}{T}=constant$$
$$\implies \dfrac{P}{2T_0}=\dfrac{P_0}{T_0}$$
$$\implies P=2P_0$$
Thus, an equilibrium to exist, the difference in inside and outside forces must be balanced by the tension in the wire.
Thus, $$T=2P_0A-P_0A=P_0A$$
Question 6
1 / -0

Assertion: PV/T=constant for 1 gram of gas. This constant varies from gas to gas.
Reason:1 gram of different gases at NTP occupy different volumes.

A
Both assertion (A) and reason (R) are correct and R gives the correct explanation

B
Both assertion (A) and reason (R) are correct but R doesnt give the correct explanation

C
A is true but R is false

D
A is false but R is true

Solution

As different type of gases will have different molecular mass therefore, gases will occupy different volumes also
Hence assertion is true and reason is correct explaination
option (A)
Question 7
1 / -0

Match List I with List II
List-I                                               List-II
a) 0.00366/$$^{0}$$ C                   e) Avagadros Number
b) 6.023x10$$^{23}$$ molecules   f) Universal gas constant
c) -273$$^{0}$$ C g) Pressure coefficient of gas
d) 8.31 J/K-mole h) Intercept of V-T graph at
                                                  constnat pressure

A
a-g, b-e, c-h, d-f.

B
a-f, b-g c-e,d-h.

C
a-g,b-e,c-f, d-h.

D
a-g,b-f, c-e, d-h.

Solution

(a)$$0.00366^{o}C$$ = $$\frac{1}{273}^{o}C$$ = pressure coefficient of gas
a - g
(b)$$6.023 \times {10}^{23}$$ is Avagadros Number.
b - e
(c)$$-273^{o}C$$ is Intercept of V-T graph at constnat pressure(as shown in image)
c - h
(d)8.31 J/K-mole is Universal gas constant(R).
d - f
Answer is A.
Question 8
1 / -0

The physical factor which distinguishes thermal radiation from visible light is :

A
wave length

B
pressure

C
temperature

D
amplitude

Solution

The wavelength of thermal radiation lies in the infrared region of the spectrum.
So wavelength is the characteristic that separated thermal radiation from the visible light.
Question 9
1 / -0

The process in which rate of transfer of heat is maximum is :

A
conduction

B
convection

C
radiation

D
in all these, heat is transferred with the same speed

Solution

$$\textbf{Step 1}$$:
There are three modes of transmission of heat. They are Conduction, convection and radiation.
Conduction: In this mode of transmission. heat dissipates from one place to another by molecular vibration. It is relevant to solid only. Conduction needs a medium to transfer heat.
Convection: Heat is transferred from one place to another by the transfer of molecules. It happens only in liquids or gases. It also needs a medium to transfer heat.
Radiation: It transfers heat in the form of electromagnetic waves. It can heat any form of material. It doesn't need any medium for the transfer of heat.
$$\textbf{Step 2}$$:
We know that radiation travels with the speed of light. So, the rate of heat transfer is maximum in radiation in the form of electromagnetic radiation.
Thus option C is correct.
Question 10
1 / -0

A wall has two layers $$A$$ and $$B$$, each of same thickness and same area of cross-section but made of different materials. The thermal conductivity of $$A$$ is three times that of $$B$$. The temperature difference across the wall is $$20$$$$^{o}$$C . In thermal equilibrium :

a) the temperature difference across the layer $$A$$ is 15$$^{o}$$C
b) the temperature difference across the layer $$B$$ is 15$$^{o}$$C
c) the rate of flow of heat across $$A$$ is more than across $$B$$
d) the rate of flow of heat across $$A$$ and $$B$$ are same

A
a, b correct

B
b, c correct

C
c, d correct

D
b, d correct

Solution

Heat transfer from the wall is given as:
$${Q}=\dfrac{{KA}({T}_{1}-{T}_{2})}{L}$$
Here, area and thickness of both the wall is equal, so for equilibrium condition equate both of them, also
$${K}_{1}={3K}_{2}$$
$${T}_{1}-{T}_{2}={20}^{\circ}C$$
$${T}_{2}={T}_{1}-{20}^{\circ}C$$
$${T}_{1}={T}_{2}+{20}^{\circ}C$$
Therefor temperature across 1:
$$\dfrac { { K }_{ 1}({ T }_{ 1 }-{ T }) }{ { l }_{ 1 } } =\dfrac { { K }_{ 2 }({ T }-{ T }_{ 2 }) }{ { l }_{ 2 } } $$
So on substituting the values in above equation we find:
$${ { 3K }_{ 2}({ T }_{ 1 }-{ T })} ={ { K }_{ 2 }({ T }-{ T }_{ 1 }+{20}) } $$
$${T}_{1}-{T}={5}^{\circ}C$$
For surface 2:
$${ { 3K }_{ 2}({20}+{ T }_{ 2 }-{ T })} ={ { K }_{ 2 }({ T }-{ T }_{ 2}) } $$
$${T}-{T}_{2}={15}^{\circ}C$$
$${Q}={K}({T}_{1}-{T}_{2})$$
So for surface 1:
$${Q} \propto {K}({T}_{1}-{T})={3K}({5})={15}^{\circ}C(K)$$
For surface 2: $${Q} \propto {K}({T}-{T}_{2})={K}({15})={15}^{\circ}C(K)$$
Same for both as both of them have same length and area.
NOTE: $${T}_{1}=A$$, $${T}_{2}=B$$

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Thermal Properties of Matter Test - 31

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Thermal Properties of Matter Test - 31

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Question 1

Both assertion (A) and reason (R) are correct and R gives the correct explanation

Both assertion (A) and reason (R) are correct but R doesnt give the correct explanation

A is true but R is false

A is false but R is true

Solution

Question 2

a & b

a,b & c

a,b & d

all

Solution

Question 3

b,c

a,b

c,d

a,d.

Solution

Question 4

Both assertion (A) and reason (R) are correct and R gives the correct explanation

Both assertion (A) and reason (R) are correct but R doesnt give the correct explanation

A is true but R is false

A is false but R is true

Solution

Question 5

$$P_{0}A$$

$$\frac{P_{0}A}{2}$$

$$2P_{0}A$$

$$\frac{2P_{0}A}{3}$$

Solution

Question 6

Both assertion (A) and reason (R) are correct and R gives the correct explanation

Both assertion (A) and reason (R) are correct but R doesnt give the correct explanation

A is true but R is false

A is false but R is true

Solution

Question 7

a-g, b-e, c-h, d-f.

a-f, b-g c-e,d-h.

a-g,b-e,c-f, d-h.

a-g,b-f, c-e, d-h.

Solution

Question 8

wave length

pressure

temperature

amplitude

Solution

Question 9

conduction

convection

radiation

in all these, heat is transferred with the same speed

Solution

Question 10

a, b correct

b, c correct

c, d correct

b, d correct

Solution

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