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Thermal Properties of Matter Test - 61

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Thermal Properties of Matter Test - 61
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  • Question 1
    1 / -0
    The temperature below which a gas should be cooled, before it can be liquified by pressure only is termed as 
    Solution
    Critical temperature is the temperature of a gas in its critical state, above which it cannot be liquefied by pressure alone. Critical pressure is the pressure of gas corresponds to its critical state. 
    Thus option (𝗗) is correct. 
  • Question 2
    1 / -0
    The velocity of heat radiation in vacuum is 
    Solution
    The velocity of heat radiation in the vacuum is $$equal$$ to that of light. 
  • Question 3
    1 / -0
    Four rods of identical cross-sectional area and made from the same the metal form the sides of square. The temperature of two diagonally opposite points and $$T$$ and $$2T$$ respective in the steady-state. Assuming that only heat conduction takes place, what will be the temperature difference between the other two points 
    Solution

  • Question 4
    1 / -0
    A thermos flask is polished well
    Solution
    The polished surface reflects all the radiation. And a thermos flask is used to keep the heat out so the well-polished surface reflects all radiation from outside.
  • Question 5
    1 / -0
    Three rods of the same dimension have thermal conductivities 3K,2K3K,2K. The temperature of their junction is 

    Solution
    Let the temperature of junction be θθ then according to the following figure. 
    $$H=H_1+H_2$$
    $$\dfrac{3K \times A(100-\theta)}{l}=\dfrac{2KA(\theta-50)}{l}+\dfrac{2KA(\theta-20)}{l}$$\
    $$300-3 \theta=3 \theta -120$$
    $$\theta=70$$

  • Question 6
    1 / -0
    At constant volume the specific heat of a gas is $$ \dfrac{3R}{2} $$ , then the value of $$\gamma $$ will be 
    Solution

  • Question 7
    1 / -0
    At a given volume and temperature , the pressure of a gas
    Solution

  • Question 8
    1 / -0
    At NTP the mass of one litre of air is $$1.293\,gm$$. The value of specific gas constant will be 
    Solution

  • Question 9
    1 / -0
    For matter to exist simultaneously in gas and liquid phases 
    Solution

  • Question 10
    1 / -0
    Beryllium has roughly one-half the specific heat of water $$(H_2O)$$. Rank the quantities of energy input required to produce the following changes from the largest to the smallest. In your ranking, note any cases of equality.
    Solution
    Rankings (e) >(a) =(b) =(c) > (d). We think of the product $$mc\Delta T$$ in each case, with c =1 for water and about 0.5 for beryllium: (a) 1. 1. 6 =6, (b) 2. 1. 3 =6, (c) 2. 1. 3 =6, (d) 2(0.5)3 =3, (e) >6 because a large quantity of energy input is required to melt the ice.
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