Thermal Propert...

50 gm of copper is heated to increase its temperature by $${ 10 }^{ \circ  }C$$ . If the same quantity of heat is given to 10gm of water, the rise in its temperature is ( Specific heat of copper = $$420\quad Joule-{ kg }^{ -1 }{ C }^{ -1 }$$ )

Three slabs of equal area and thickness are arranged as shown in the figure. Find the value of $$T_1$$ and $$T_2$$ in steady state:

An ideal gas with pressure $$P$$, volume $$V$$ and temperature $$T$$ is expanded isothermally to a volume $$2V$$ and a final pressure $${P}_{I}$$. The same gas is expanded adiabatically to a volume $$2V$$, the final pressure is $${P}_{A}$$. In terms of the ratio of the two specific heats for the gas $$\gamma$$, the ratio $${P}_{I}/{P}_{A}$$ is:

The value of the gas constant (R) calculated from the perfect gas equation is $$8.32 \,Joule/gm \,mol \,K$$, whereas its value calculated from the knowledge of $$C_p$$ and $$C_v$$ of the gas is $$1.98 \,cal/gm \,mole \,K$$. from this data, the value of $$J$$ is

One mole  of gas ''A'' and 2 moles of S$${ O }_{ 2 }$$ are placed in a container,gaseous can be:

A solid whose volume does not change with temperature floats in a liquid. For two different temperatures $$  t_{1}  $$ and$$  t_{2}  $$ of the liquid, fractions $$  f_{1}  $$ and $$  f_{2}  $$ of the volume of the solid remain submerged in the liquid. The coefficient of volume expansion of the liquid is equal to

When the temperature difference between in side and outside of a room is $$20 $$ the rate of heat flow through a window is 273 J/s. If the temperature difference becomes 20K, the rate of flow of heat through the same window will be: 

When water is heated from $$0^0$$C to $$10^0$$C, its volume -

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are $${39^\circ }\,W$$  and $${239^\circ }\,W$$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $${39^\circ }$$ on the Celsius scale?

For $$N_2$$the value of $$C_p-C_v$$=