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Waves Test - 11

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Waves Test - 11
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The product of the time period of a wave and its frequency is
    Solution
    The relation between frequency (f) and time period(T) is
    $$f=1/T or f \times T=1$$

  • Question 2
    1 / -0
    Which of the following quantity decrease as sound wave travels through a medium :
    Solution
    When sound wave propagates through a medium, the amplitude of vibration decreases due to the energy dissipation due to the resistance of the medium.
  • Question 3
    1 / -0

    Two waves $${y_1} = {A_1}\sin (\omega t - {\beta _1}){y_2} = {A_2}\sin (\omega t - {\beta _2})$$ superimpose to form a resultant wave whose amplitude is

    Solution
    $$y=y_1 +y_2$$
    $$y=A  Sin  (wt  -  \beta)$$
    $$A=\sqrt{A_1^2  +  A_2^2  +  2A_1 A_2  Cos  (\beta_1- \beta_2)}$$
  • Question 4
    1 / -0
    When two plane progressive waves travelling in same direction superimpose over each other, the velocity of the resultant wave will
    Solution
    When two plane progressive waves travelling in same direction superimpose over each other, the velocity of the resultant wave will remain unchanged. Velocity depends on the medium only.
  • Question 5
    1 / -0
    What will be the wave velocity, if the radar gives 54 waves per min and wavelength of the given wave is 10 m?
    Solution
    $$v = v \displaystyle \lambda = \frac{54}{60}H_z \times 10 m = 9 m  s^{-1}$$
  • Question 6
    1 / -0
    The frequency of a man's voice is $$300\space Hz$$. If the velocity of sound waves is $$336\space ms^{-1}$$, the wavelength of the sound is
    Solution
    We are given, frequency $$f=300 Hz$$, and velocity $$v=336 ms^{-1}$$,

    From the relation $$v=f \times \lambda$$,

    $$\lambda = v/f =336/300=1.12 m$$

    Option "A" is correct.
  • Question 7
    1 / -0
    If the energy density and velocity of a wave are $$u$$ and $$c$$ respectively then the energy propagating per second per unit area will be
    Solution
    If the energy density and velocity of a wave are $$u$$ and $$c$$ respectively then the energy propagating per second per unit area will be $$uc.$$
  • Question 8
    1 / -0
    An ultrasonic source emits sound of frequency 220 kHz in air. If this sound meets a water surface, what is the wavelength of the reflected sound?
    Solution
    Here, $$v=220  kHz  = 220 \times 10^3$$
    $$=2.2 \times 10^5  Hz$$;
    Speed of sound in air, $$v_a = 352  m  s^{-1}$$
    Speed of sound in water, $$v_w = 1.496  m  s^{-1}$$
    The reflected sound: After reflection, the ultrasonic sound continues to travel in air. If $$\lambda_a$$ is wave length in air, then
    $$\lambda_a = \displaystyle \frac{v_a}{v} = \frac{352}{2.2 \times 10^5} = 1.6 \times 10^{-3} m$$
  • Question 9
    1 / -0
    A piezo - electric quartz plate is vibrating to produce wavelength of $$10^{-1}$$ m. Find the frequency if for quartz $$Y=8 \times 10^{10} N  m^{-2}$$ and $$\rho = 2.65 \times 10^3  kg  m^{-3}$$
    Solution
    We know that for longitudinal waves in solids,
    $$v = \displaystyle \sqrt{\frac{Y}{\rho}}$$, so, $$v = \displaystyle \sqrt{\frac{8 \times 10^{10}}{2.65 \times 10^3}}$$
    $$ = 5.5 \times 10^3 m/s$$
    So, $$10^{-2}m$$ 
    But as $$v=f \lambda$$, i.e.,    $$f = (\frac{v}{\lambda})$$
    so f $$[5.5 \times 10^3 / 10^{-2}] = 5.5 \times 10^5 Hz$$
    $$=550  kHz$$
  • Question 10
    1 / -0
    The particle of a medium vibrates about their mean position whenever a wave travels through that medium. The phase difference between the vibrations of two such particles
    Solution
    The phase difference between the vibrations of two particles of the medium is given by :
                $$\Delta \phi=\dfrac{2\pi}{\lambda}\Delta x$$ 
    it is clear that phase difference varies as the path difference between the particles varies, which is the distance, separating the particles.
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