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Waves Test - 19

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Waves Test - 19
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  • Question 1
    1 / -0
    The relation between frequency $$\upsilon$$, wavelength $$\lambda$$ and velocity of propagation of wave $$\nu$$ is
    Solution
    Velocity of the wave,
    $$\nu = \upsilon \lambda$$ or $$\upsilon = \dfrac{\nu}{\lambda}$$
  • Question 2
    1 / -0
    Ultrasonic waves produced by a vibrating quartz crystal are:
    Solution
    Ultrasonic waves produced by a vibrating quartz crystal are longitudinal.
  • Question 3
    1 / -0
    Regarding open organ pipe, which of following is correct?
    Solution
    Regarding open pipe both ends are pressure nodes.
    So, option $$C$$ is correct.

  • Question 4
    1 / -0
    A simple harmoinic motion is represented by $$F(t) = 10 \, \sin(10\tau + 0.5)$$. The amplitude of the S.H.M. is
    Solution
    We know that SHM is represented  by 
       $$F(x,t)=Asin(wt-kx)$$
    Here,
        $$A=amplitute$$
        $$w=frequency$$
       Given,
      $$F(t)=10sin(10t+0.5)$$
    By comparing  both the equation we get
       $$A=10$$
    Correct option is C.
  • Question 5
    1 / -0
    In the equation $$y=A\sin{(kx-\omega t+{\phi}_{0})}$$ the term phase is defined as:
    Solution
    Given,
    $$y=Asin(kx-\omega t+\phi_0)$$
    In the equation, the term phase is defined as $$\phi_0$$.
    The correct option is A.
  • Question 6
    1 / -0
    Displacement time equation of a particle executing SHM is x = A sin(wt + /6). Time taken by the particle to go directly from x = - A/2  to x = +A/2 is
    Solution

    At t =0, the particle was at x = A sin (0 + /6) = A/2. 


    The particle reaches equilibrium at $$t= t_1$$. Thus $$0 = A sin (wt_1 + /6) or  t_1 = -T/12$$. Since time taken cannot be negative, $$t_1 = T/12$$. 


    Similarly same time will be used to travel from mean position to +A/2. Thus, total time taken is $$2(T/12) = T/6 = \dfrac{\pi} {3w}$$


    The correct option is (c)

  • Question 7
    1 / -0
    The equation of a simple harmonic motion is given by, $$ x=8 \,sin (8 \pi t)+6 cos (8 \pi t)$$, the initial phase angle is 
  • Question 8
    1 / -0
    Two wave have amplitude ratio 10 : 1 then $$v_{1}/v_{2}$$ is (Approx) - 
  • Question 9
    1 / -0
    A particle starts oscillating from position equal to half the amplitude. What is its initial phase?
  • Question 10
    1 / -0
    A single wave is called
    Solution
    A single wave is known as a pulse

    The correct option is (a)
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