Waves Test - 52...

The displacement of a particle in SHM is $$x =3 sin(20\pi t) +4 cos (20\pi t)$$ cm.Its amplitude of oscillation is

A progressive wave moves with a velocity of $$36m/s$$ in a medium with a frequency of $$200Hz$$. The phase difference between two particles separated by a distance of $$1cm$$ is:

Two identical sinusoidal waves each of amplitude $$5 mm$$ with a phase difference of $$\dfrac{\pi}{2}$$ are travelling in the same direction in a string. The amplitude of the resultant wave (in mm) is:-

$$x_1 = A\sin(\omega t - 0.1x)$$ and $$x_2 = A\sin(\omega t - 0.1x - \dfrac{\phi}{2})$$. The resultant amplitude of combined wave is:-

The value of phase, at maximum displacement from the mean position of a particle, in SHM is ?

The phase difference between two waves represented by 
$${y_1} = {10^{ - 6}}\sin \left[ {100t + \frac{x}{{50}} + 0.5} \right]m$$
$${y_2} = {10^{ - 6}}\cos \left[ {100t + \frac{x}{{50}}} \right]m$$
where x is expressed in metres and t is expressed in seconds is approximately

Two parallel beams of light of wavelength $$\lambda $$, inclined to each other at angle $$\theta \ ( <  + 1)$$ are inclined on a plane at near normal incidence. The fringe width will be. 

The amplitude of a particle due to superposition of following S.H.Ms. Along the same line is 
$${ X }_{ 1 }=2sin50\pi t\quad ;\quad { X }_{ 2 }=10sin\left( 50\pi t+{ 37 }^{ } \right) $$
$${ X }_{ 3 }=-4sin50\pi t\quad ;\quad { X }_{ 4 }=-12sin50\pi t$$

Equation of  two S.H.M. $$ x_1 = 5 sin ( 2 \pi t + \pi /4), $$  $$ x_2 =   5\sqrt { 2 } (sin\quad 2\pi t+cos2\pi t)$$ ratio of amplitude & phase difference will be

A progressive wave  moves with a velocity of $$36 \mathrm { m } / \mathrm { s }$$ in a medium with a frequency of 200Hz. The phase difference betveen two particles seperated by a distance of $$1$$ $$cm$$ is