Waves Test

Directions For Questions

Dolphins emit high frequency sound waves typically $$10^5\space Hz$$ and use the echos for guidance and for hunting. The corresponding wave length in water is $$1.48\space cm$$ with this sonar system they can sense objects as small as (roughly) the wavelength. Ultrasonic imaging is a medical technique that uses exactly the same physical principle, sound waves of very short wavelength (or high frequency) called ultrasound are scanned over the human body the echos from the interior organs are used to create image. Ultrasound is more sensitive than x-rays in distinguishing various kinds of tissues and does not have the radiation hazards associated with the x-rays. Ultra sound is used for the study of heart valve action, detection of tumors and prenatal tests.

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Waves Test - 71...

Question 1

$$\displaystyle \frac{\pi}{2}$$ radian

$$\pi$$ radian

$$\displaystyle \frac{\pi}{4}$$ radian

$$\displaystyle \frac{\pi}{8}$$ radian

Question 2

$$\dfrac{6}{5}$$

$$\dfrac{2}{3}$$

$$\dfrac{1}{7}$$

$$\dfrac{5}{9}$$

Question 3

336 m/sec

320 m/sec

340 m/sec

350 m/sec

Question 4

$$\dfrac{5}{\pi} cm$$

$$\dfrac{\pi}{2}cm$$

$$\dfrac{10}{\pi}cm$$

$$2\pi cm$$

Question 5

Waves

Packets

Straight Lines

None of these

Question 6

the maximum intensity that can be achieved at a point is twice the intensity of either wave and occurs if $$\displaystyle \phi=0 $$

the maximum intensity that can be achieved at a point is four times the intensity of either wave and occurs if $$\displaystyle \phi=0 $$

the maximum amplitude that can be achieved at the point its twice the amplitude of either wave and occurs at $$\displaystyle \phi=0 $$

When the intensity is zero the net amplitude is zero and at this point $$\displaystyle \phi=\pi/4 $$

Question 7

$$\displaystyle a=\left [ \frac{v^{3}x_{1}^{3}-u^{2}x_{2}^{2}}{v^{2}-u^{2}} \right ]^{1/2}$$

$$\displaystyle a=\left [ \frac{v^{2}x_{1}^{2}-u^{2}x_{2}^{2}}{v^{2}-u^{2}} \right ]^{1/2}$$

$$\displaystyle a=\left [ \frac{v^{3}x_{1}^{2}-u^{3}x_{2}^{2}}{v^{3}-u^{3}} \right ]^{1/2}$$

$$\displaystyle a=\left [ \frac{v^{4}x_{1}^{2}-u^{4}x_{2}^{2}}{v^{4}-u^{4}} \right ]^{1/2}$$

Question 8

A and D

B and F

C and E

B and G

Question 9

0.148 mm

0.3 mm

0.5 mm

0.1 mm

Question 10

Matter

Particles

Energy

Water

User

Question Analysis

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