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Units and Measurements Test - 76

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Units and Measurements Test - 76
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  • Question 1
    1 / -0
    In the equation $${ S }_{ nth }=u+\dfrac { a }{ 2 } \left( 2n-1 \right) $$, the letters have their usual meanings. The dimensional formula of $$S_{nth}$$ is
    Solution
    The Dimensional Formula of $${S}_{nth}$$ is same as that of the Dimensional formula of $$u$$ (2 variables with same units can be added)

    So Dimensional Formula of $${S}_{nth}$$ = DImensional Formula of $${u}$$ = $$[M^{0}{L}{T}^{-1}]$$
  • Question 2
    1 / -0
    A physical quantity x depends on quantities y and Z as follows  : x= Ay+B tan (Cz), where A, B and C are constants . Which of the following do not have same dimensions ?
    Solution

  • Question 3
    1 / -0
    Dimensions of rate of change of flux are equivalent to those of 
  • Question 4
    1 / -0
    The dimension of the ratio of magnetic flux and the resistance is equal to that of:
    Solution
    Dimension of magnetic flux $$=[ML^2T^{-2}A^{-1}]$$

    Dimension of resistance $$=ML^2T^{-3}A^{-2}]$$

    Therefore,

    $$\dfrac{[Magnetic\,\,flux]}{[Resistance]}=\dfrac{[ML^2T^{-2}A^{-1}]}{[ML^2T^{-3}A^{-2}]}=[AT]=Charge$$
  • Question 5
    1 / -0
    If pressure is (P), velocity (V), and time (T) are taken as the fundamental quantities, then the dimensional formula of force is
    Solution

    $$Force=P^xV^yT^z$$

     

    $$[MLT^{-2}]=[MLT^{-2}L^{-2}]^x[LT^{-1}]^y[T]^z$$

     

    Comparing the dimensions on both side, we get,

     

    $$x=1$$,  $$y=2$$,  $$z=2$$


    So,  $$Force=[P^1V^2T^2]$$

  • Question 6
    1 / -0
    In a system of units if force (F), acceleration (A) and time, (T) are taken as fundamental units then the dimensional formula of energy is -
    Solution
    Consider that the energy is expressed as:
    $$E=KF^aA^bT^c$$

    Substituting the dimensional formulas:
    $$[ML^2T^{−2}]=[MLT^{−2}]^a[LT^{−2}]^b[T]^c$$

    $$[ML^2T^{−2}]=[M^aL^{a+b}T^{−2a−2b+c}]$$

    $$\Rightarrow a=1,a+b=2\Rightarrow b=1$$

    and $$−2a−2b+c=−2\Rightarrow c=2$$

    $$\therefore E=KFAT^2$$
  • Question 7
    1 / -0
    The dimensions of the ratio of angular momentum to linear momentum:
    Solution

  • Question 8
    1 / -0
    The term $$(1/2)pv^{ 2 }$$ occurs in Bernoulli's  equation , with $$\beta $$ being the density of fluid and V its speed . The dimensions of this term are 
    Solution

  • Question 9
    1 / -0
    Two resistance are measured in ohm and is given as:-
    $${ R }_{ 1 }=3\Omega \neq 1%$$
    $${ R }_{ 2 }=6\Omega \neq 2%$$
    When they are connectrd in parallel, the percentage error in equivalent resistance is
    Solution
    $$\text { Given: } R_{1}=3 \Omega \pm 0 \cdot 1 \quad R_{2}=6 \Omega \pm 0.2$$

    $$\begin{array}{l}\text { For parallel } \\\frac{1}{R_{e q}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}=\frac{1}{3}+\frac{1}{6}=\frac{2+1}{6}=\frac{3}{6}=\frac{1}{2}\end{array}$$

    $$\begin{array}{l}R_{e q}=2 \Omega \\\text { Differentiating eq }^{n} \text { (i) both side } \\-\frac{d R_{e q}}{R_{e q}^{2}}=-\frac{d R_{1}}{R_{1}^{2}}-\frac{d R_{2}}{R_{2}^{2}}\end{array}$$

    $$\begin{array}{l}\text { Error is always added }\\\qquad \begin{aligned}\frac{d R_{e q}}{R_{e q}^{2}} &=\frac{d R_{1}}{R_{1}^{2}}+\frac{d R_{2}}{R_{2}^{2}} \\\frac{d R_{e q}}{R_{e q}}&=\left(\frac{d R_{1}}{R_{1}^{2}}+\frac{d R_{2}}{R_{2}^{2}}\right)R_{0}\mathrm{~V}\\&=\left(\frac{0.1}{3^{2}}+\frac{0.2}{6^{2}}\right){2}\\&=\left(\frac{0.1}{9}+\frac{0.2}{36}\right){2}\end{aligned}\end{array}$$

    $$\begin{aligned}\frac{d \operatorname{Req} x}{\operatorname{Reg}} \times100\% &=\left(\frac{4+0.2}{36}\right)^{2} \times 100 \% \\&=\frac{0.6}{36}\times 2 \times 100 \\&=\frac{100}{3}\\&=3.33\%\end{aligned}$$
  • Question 10
    1 / -0
    If the radius of the earth were to shrink by 1% its mass remaining the same, the acceleration due to gravity on the earth's surface would
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