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Units and Measurements Test - 81

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Units and Measurements Test - 81
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  • Question 1
    1 / -0
    The earth attracts a body of mass $$1$$ kg with a force of $$10$$ N. The mass of boy is $$50$$ kg. His weight will be
    Solution
    Using unitary method,
    For 1 kg ,force acting is 10N
    Thus for 50 kg ,force acting is $$50\times 10$$ = 500N
  • Question 2
    1 / -0
    The magnitude of any physical quantity
    Solution
    The magnitude is a absolute quantity and it does not depend on the method of measurement.
  • Question 3
    1 / -0
    Which pair has the same dimensions
    Solution
    The impulse is defined as the rate of change of momentum.
    Impulse = change in momentum 

    so dimensions of both quantities will be same and equal to $$MLT^{-1}$$
  • Question 4
    1 / -0
    The dimensional formula for impulse is same as the dimensional
    formula for
    Solution
    The impulse is defined as the rate of change of momentum of a body.

    So, the dimension of impulse will be same as that of momentum.
  • Question 5
    1 / -0
    Select the correct alternative 
    A block of wood of density $$0.8 g cm ^ 3 $$ has a volume of 76 $$cm ^3$$ . The mass of block is 
    Solution
    We know that 
    Mass = density × volume
    Therefore putting the values we have
    Mass = 0.8 × 76 gm
    Mass = 60.8 gm
    Hence the correct option is A. 

  • Question 6
    1 / -0
    The dimensional formula for r.m.s. (root mean square) velocity is
    Solution
    The dimensional formula for the RMS velocity is same as the normal velocity.

    So, dimension of RMS velocity is = $$[M^0LT^{-1}]$$
  • Question 7
    1 / -0
    If C and L denote capacitance and inductance respectively, then the dimensions of LC are
    Solution
    The resonance frequency of the series RLC circuit is given as:
    $$f=\dfrac{1}{2 \pi \sqrt{LC}}$$

    $$\Rightarrow =\dfrac{1}{f^2}=[M^0L^0T^2]$$
  • Question 8
    1 / -0
    Dimensions of CR are those of
    Solution
    According to the definitions:
    $$Capacity \times Resistance =\dfrac{Charge}{Potential}\times \dfrac{Volt}{amp}$$

    $$=\dfrac{amp \times second\times Volt}{Volt \times amp}=second$$
  • Question 9
    1 / -0
    The dimension of quantity (L / RCV) is
    Solution
    The above equation can be written as:
    $$\dfrac{L}{RCV}=[\dfrac{L}{R}]\dfrac{1}{CV}$$

    We know that $$\dfrac LR$$ is time constant and $$CV$$ is the charge of capacitor.
    $$=\dfrac{T}{Q}=[A^{-1}]$$
  • Question 10
    1 / -0
    The dimensions of "time constant" $$\dfrac{L}{R}$$ during growth and decay of current in all inductive circuit is same as that of
    Solution
    $$\dfrac LR$$ is defined as the time constant of a circuit.

    So, $$\dfrac{L}{R}$$ =Time constant.
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