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Units and Measurements Test - 83

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Units and Measurements Test - 83
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Accuracy of measurement is determined by
    Solution
    Accuracy of measurement is determined by the absolute errorAbsolute error is the is the difference between the actual and measured value. It is the maximum possible error that needs to be eliminate to get an accurate measurement.
  • Question 2
    1 / -0
    The dimension of $$\dfrac{R}{L}$$ are
    Solution

  • Question 3
    1 / -0
    What is the number of significant figures in $$0.310\times10^3$$
    Solution

  • Question 4
    1 / -0
    Pressure gradient has the same dimension as that of
    Solution

  • Question 5
    1 / -0
    Which of the following group have different dimension
    Solution

    Dipole moment = charge x distance
    Electric flux = electric field x area
     Dipole moment, electric flux and electric field have different dimensions.

  • Question 6
    1 / -0
    The dimensions of shear modulus are
    Solution

  • Question 7
    1 / -0
    The dimensions of magnetic field intensity in $$ M, L , T $$ and $$ C $$ is given as 
    Solution
    The dimensions of magnetic field intensity in $$ M, L , T $$ and $$ C $$ is given as  $$ MT^{-1}C^{-1} $$
  • Question 8
    1 / -0
    Which of the following is the best estimate for the mass of all the people living on the Earth?
    Solution
    The population is about $$6$$ billion = $$6 * 10^{9}$$. Assuming about $$100$$ lb per person = about $$50$$ kg per person ($$1$$ kg has the weight of about $$2.2$$ lb), the total mass is about $$(6 * 10^{9})(50 kg) = 3 * 10^{11} kg$$, 
    answer (d). 
  • Question 9
    1 / -0
    An unknown quantity $$\displaystyle "\alpha"$$ is expressed $$\displaystyle \alpha =\frac{2ma}{\beta }\log \left ( 1+\frac{2\beta \varphi }{ma} \right )$$
    where $$m$$ = mass, $$a$$ = acceleration, $$\displaystyle \varphi $$  = length 
    The unit of $$\displaystyle \alpha  $$ should be 
    Solution
    $$\alpha =\dfrac { 2ma }{ \beta  } \log { 1+\dfrac { 2\beta \psi  }{ ma }  }   $$


    First find unit of $$\beta $$.


    The value of log is dimensionless so dimension of:


    $$\beta \psi =ma$$


    $$\beta (m)=(kg)(m/sec^2)$$



    Unit of $$\beta =\dfrac { kg }{ { sec }^{ 2 } } $$ 



    Unit of $$\alpha =\dfrac { kg.m/{ sec }^{ 2 } }{ kg/{ sec }^{ 2 } } =m= meter$$

  • Question 10
    1 / -0
    The Bernoulli's equation is given by $$\displaystyle p + \frac {1} {2} \rho v^2 + h \rho g = k $$, 
    where $$p$$ = pressure, $$ \rho $$ = density, $$v$$ = speed, $$h$$= height of  the liquid column,$$g$$ = acceleration due to gravity and $$k$$ is constant. The dimensional formula for $$k$$ is same as that for : 
    Solution
    Dimension of k must be same as pressure according to principle of dimensional homogeneity.
    Thus it's dimensions are $$ML^{-1}T^{-2}$$ which is the same as modulus of elasticity (Stress/Strain).
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