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Units and Measurements Test - 89

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Units and Measurements Test - 89
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  • Question 1
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    Characteristics of Scientific observation are.
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  • Question 2
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    The distance covered by a particle in time $$t$$ is given by$$ x = a + bt + ct^2 + dt^3$$. The dimensions of $$a$$ and $$d$$ are - 
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  • Question 3
    1 / -0
    A glass cube of edge 1 $$ {cm}  $$ and $$  \mu=1.5  $$ has a spot at the centre .The area of the cube face that must be covered to prevent the spot from being seen is (in $  {cm}^{2} ) $
    Solution

  • Question 4
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    The mass of a bag is $$1.6kg$$. Two objects of mass $$20\,gm$$ and $$15\,gm$$ meausred to an accuracy of $$1gm$$ are added to it. The total mass of the bag calculated to the correct number of significant figures is 
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  • Question 5
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    Using mass (M), length (L), time(T) and current (A) as fundamental quantities,the dimension of permeability is
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  • Question 6
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    Suppose a quantity x can be dimensionally represented in terms of M, L and $$T$$ that is, $$[x]=M^aL^bT^c$$. The quantity mass.
    Solution

  • Question 7
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    Taking density $$(\rho)$$, velocity $$(v)$$ and area $$(a)$$ to be fundamental unit then the dimensions of force are:
    Solution

  • Question 8
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    A body of mass $$m_{1}$$, moving with uniform velocity of $$40\ m/s$$ collides with another mass $$m_{2}$$ at rest and then the two together begin to move in a uniform velocity of $$30\ m/s$$. The ratio of their masses $$(m_{1}/m_{2})$$ is
    Solution

  • Question 9
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    If area $$(A)$$, velocity $$(v)$$ and density $$(\rho)$$ are base units, then the dimensional formula of force can be represented
    Solution

  • Question 10
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    Which of the following pairs of physical quantities does not have same dimensional formula?
    Solution
    a) Work =$$F \times \Delta x=[MLT^{-2}[L]=[ML^2T^{-2}]]$$

    Torque=force $$\times$$ distance =$$[ML^2T^{-2}]$$

    b) Angular momentum$$mvr=[M][LT^{1}][L]=[ML^2T^{-1}]$$

    Plank's constant=$$\dfrac{E}{V}=\dfrac{[ML^2T^{-2}]}{[T^{-1}]}=[ML^2T^{-1}]$$

    c) Tension (force)=$$[MLT^{-2}]$$

    Surface tension =$$\dfrac{force}{length}=\dfrac{[MLT^{-2}]}{[L]}=[ML^0T^{-2}]$$

    d) Impulse $$=F \times \Delta t=[MLT^{-2}][T]=[MLT^{-1}]$$

    Momentum =$$mass \times velocity=[M][LT^{-1}]=[MLT^{-1}]$$

    So, among the above pairs only tension and surface tension does not have the same dimensional formula. They both sound similar but they both have different meaning and different applications.
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